Lec 21 Flashcards

1
Q

Forward genetic

A

using phenotypes to start, don’t need to know the gene. They are unbiased.

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2
Q

Reverse genetics

A

using DNA to start

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3
Q

Forward genetic screens begin with?

A

mutagenesis, an organism is treated with a mutagen to create mutations randomly throughout the genome

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4
Q

Typical goal of forward genetics?

A

to achieve saturation mutagenesis meaning that every gene has undergone at least one mutation

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5
Q

A good model organism for forward genetics

A

must be able to:

  • progress through its life cycle in a laboratory
  • have a short generation time
  • produce a reasonable number of progeny
  • be amenable to crossing
  • organisms that are diploid usually have a starting genotype that is homozygous at all loci.
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6
Q

choosing a mutagen for forward genetics

A
  • the choice of mutagen depends on both the research organism and the type of mutant alleles desired
  • chemical mutagens can induce many mutations, allowing saturation to be reached with only a few thousand individuals
  • transposons can be used to induce mutations but result in fewer mutations, so saturation is difficult. However, they provide a DNA “tag” that makes finding and cloning the affected genes relatively easy
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7
Q

In all mutagenesis used for forward genetic screens…

A

mutants of interest must be crossed to WT to ensure that the collected mutants have only the mutation of interest

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8
Q

How can newly induced dominant mutations be identified in forward?

A

can be identified in the F1 generation produced by breeding the mutagenized males with WT females. Dominant mutations are relatively rare and they are usually gain of function.

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9
Q

Recessive mutations in forward

A

loss of function mutations are much more common and usually recessive; therefore further breeding is required to make each mutation homozygous

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10
Q

Screending for a dominant mutation

A
  • Individual mutants in F1 are likely all different from another, this results in different genes or different mutations in the same gene.
  • segregate in 1:1 ration
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11
Q

Screening for recessive mutation

A

with saturation mutagenesis, most F1 progeny will carry at least one mutation contributed by a mutant sperm but you cant “see” it. You mate each of these F1 progeny with a WT female to obtain F2.
If the F1 male does carry a recessive mutation, 1/2 of F2 progeny will carry the mutation but you can’t see it. Need to interbreed F2 and screen F3.
-F3 will be a 3:1 ration of WT

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12
Q

Screening for a recessive mutation in self-fertilizing organism

A

recessive mutations in plants or self-fertilizing animals are easier to identify, as self-fertilized F1 individual produce an F2 generation from which recessive mutations can be identified

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13
Q

How can inefficiency of F3 screen be circumvented?

A

by using chromosomes that are marked and can be followed through generation. Balancer chromosomes in Drosophila allow specific chromosomes to be transmitted intact through multiple generations.

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14
Q

Features of balancer chromosomes

A
  1. one or more inverted segments to prevent transmission of chromosomes that have undergone crossing over (no homologous recombination)
  2. a recessive allele resulting in lethality so that individuals cannot be homozygous for the balancer
  3. A dominant mutation producing a visible phenotype so that segregation of the chromosome can be followed through generations
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15
Q

Advantage of using haploid organisms in a forward genetic screen

A

both recessive and dominant mutations can be identified directly

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16
Q

disadvantage of using haploid organisms in a forward genetic screen

A

mutations that cause lethality cannot be obtained. This problem can be circumvented by screening for conditional mutant alleles

17
Q

conditional alleles

A
  • in conditional mutants, the enconded gene product is either functional or not needed under one condition- the permissive condition- but it is required and either absent or inactive under another condition- the restrictive condition
  • in some lethal conditions, the mutant phenotype can be rescued by addition of a needed substance to the growth medium, or another condition, such as temperature, can be altered
18
Q

Null alleles

A

cells can’t divide so no colony of yeast with this allele/mutation can be recovered

19
Q

Temperature sensitive allele

A

gene product works fine at permissive temperature (23˚C). Yeast make colonies even if they contain a mutation in an essential gene for cell division

  • the temp-sensitive mutants fall into categories based on the phenotype of the yeast after shifting them to be restrictive temp. (36˚C).
20
Q

Two approaches to physically identify specific genes

A
  • certain genes can be identified by complementation of recessive mutant phenotype by introduction of a WT gene
  • using DNA sequencing technology, genes identified in genetic screens may be found by comparing mutant and WT genome sequences
21
Q

how to determine the number of genes identified in the screen

A

complementation test

22
Q

if progeny produced by crossing two mutant alleles are WT the mutant alleles…

A

complement, affect two different genes

23
Q

If progeny of two mutant alleles are mutant…

A

the mutations affect the same gene, they fail to complement

24
Q

Genomic libraries

A

collections of cloned DNA fragments that represent the entire genome of an organism, including repetitive and noncoding sequences

25
Q

Complementary DNA libraries (cDNA)

A

represent only a portion of the genome and are collections of cloned DNA fragments that represent mRNA produced by an organism or cell type

26
Q

in both types of libraries, howre fragments carried?

A

cloning vectors

27
Q

genomics approach to gene identification following mutagenesis -1

A
  • the mutant line is backcrossed with the WT strain

- F1 individuals are interbred and homozygous mutantts selected from the F2 generation