Lec 16 - DNA Replication, Repair, & Recombination Flashcards

1
Q

DNA polymerase - nucleotide incorporation

which nuc used? how is it stabilized? processive vs distributive?

A
  • extends growing primer strand on 3’ end w complemetary dNTP
  • Two Mg2+ ions coordinate 3’-OH nucleophile
    • 3’-OH is required (made more powerful nuc by Mg2+)
  • Processivity is the # of cycles before polymerase dissociates (opposite is distributive)

DNA pol translocates 1 nucleotide after dNTP addition (sometimes dissociates/falls off instead)

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2
Q

DNA polymerase - fidelity

first check of fidelity? error rate?

A
  • first check for fidelity is active site geometry: steric constraints disallow energetically favorable mis-pairing
  • error rate 1 in 10,000 - 100,000 bases

(e coli genome is 4 mill bp… 4 mill/10k & 4 mill/100k –> 40-400)

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3
Q

DNA polymerase - proofreading

proofreading improves fidelity how? by what rate? final error rate?

A
  • proofreading catches errors after incorporation, befoore translocation
  • cleaves of mispaired base, tries again
  • improves fidelity 10^2 to 10^3
  • final error rate 10^-6 to 10^-8 (normal error rate 10^-4 - 10^-5) improves fidelity 100-1000 times)
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4
Q

(E coli replisome)

E coli DNA Polymerase I, III

pol I vs pol III? speed? replicative DNA helicase? couples what 2 things

A

DNA pol I
- first polymerase isolated
- abundant, single subunit; too slow, non-processive
- two exonuclease domains responsible for DNA cleanup (“nick translation”)

DNA pol III
- fast (1000 bp/sec); high processivity (>500,000 bp); clamped on substrate
- beta sliding clamp locked to helix (symmetric dimer)
- 3 pol III cores
- replicative helicase ahead polymerase separating two bp strands needed to copy (hexamer that forms ring around one DNA strands; energetically couples unfav sep of DNA w/ATP hydrolysis)

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5
Q

replication fork

A
  • leading strand synthesized 5’ to 3’ as fork moves
  • lagging strand synthesized in 5’ to 3’ in opp dir of leading; synthesized discontinuosly via Okazaki fragments
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6
Q

Primase synthesizes RNA primers

initial problem? solution? new problem? solution?

A
  • problem: DNA polymerase can only extend
  • solution: primase synthesizes RNA primer that DNA Pol III extends with DNA
  • new problem –> DNA full of short RNA primers

finishing the lagging strand
- DNA pol I removes RNA primer and replaces with DNA with “nick translation” (via 5’ to 3’ exonuclease activity)
- DNA ligase seals remaining DNA-DNA “nick”

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7
Q

Bacterial Replication Machinery

  • SSB
  • DnaB protein (helicase)
  • primase (DnaG protein)
  • DNA pol III
  • DNA pol I
  • DNA ligase
  • DNA gyrase (DNA top II)
A

Single-stranded Binding protein SSB
- coats lagging strand until its replicated
- binding to ssDNA

DnaB protein (helicase)
- DNA unwrithing as it untwists; primosome constituent

Primase (DnaG protein)
- RNA primer synthesis; primosome constituent

DNA pol III
- new strand elongation

DNA pol I
- filling gaps; excision of primers

DNA ligase
- ligation

DNA gyrase (DNA top II)
- supercoiling: negative supercoil promotes unwinding

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8
Q

(similar to bacteria, more complex)

Eukaryotic replisome

2 replicative polymerases? clamp? helicase complex?

A
  • leading strand synthesized by elipson ε DNA polymerase, lagging by delta δ DNA polymerase
  • Processivity clamp PCNA (proliferating cell nuclear antigen) acts same way as clamp
  • PCNA clamp is trimer (instead of beta dimer clamp); 6 proteins that are diff instead of same
  • replicative helicase has MCM2-7 complex
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9
Q

coordinating replication

Eukaryotic replication initiation + end replication problem

each origin replicates exactly once; persistent replication bubbles must be avoided somehow…

A

Initiation
- ORC (origin recognition complex) is an ATP dependent helicase loader that binds to origin/ATP during G1 (fires only in S, once)
- MCM2-7 is a replicative helicase

End problem
- because the linear chromosomes, RNA primers at extreme 5’ end cant be fixed, leaving gap behind after primer removed (lost genetic info)

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9
Q

Bacterial vs Eukaryotic genome replication

chromosome shape? origin(s) of replication?

A

Bacterial:
- large circular chromosome
- two strands copies together, no single-stranded DNA region
- initiation at a single origin of replication
- elongagtion at two replication forks traveling around circle
- each fork replicates >2 mil bps

Eukaryotic:
- long linear chromosomes
- multiple origins of replication
- forks create replication bubble (2 replicating duplexes in bubble & 1 parental duplex outside); when forks meet, they collide and dissasemble
- replication initiation & end replication problem…

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10
Q

telomeres + telomerase

A

telomeres
- sequences at end of eukaryotic chromosomes
- repetitive buffer sequences with no genetic info; eventually eroded
- puts limit on replication & plays a role in aging

telomerase
- reverse transcriptase (RNA template–> DNA)
- expressed in germline; if reactivated in somatic cells, can lead to cancer

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11
Q

DNA replication is semiconservative (1 old, 1 new strand)

Meselsohn-Stahl experiment

metabolic labeling

A
  • grown in heavy nitrogen –> 1 band, all heavy
  • grown in light nitrogen –> 1 band, medium (new DNA light, parent DNA heavy)
  • light nitrogen (gen 2) –> 2 bands (daughter duplex splits to 1 heavy, 1 light.. replicated strand is light.. results in medium weight band and completeley light band)

cells grown in heavy N isotope and then light one, to track duplex in E

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12
Q

PCR - polymerase chain reaction

amplifies –> 1 billion copies of target DNA

A
  • 2 short primers, 1 at end of each target; 3’ end facing inward
  • (1) heat to denature/melt/separate strands to form ssDNA
  • (2) cool to anneal primers onto DNA template
  • (3) DNA polymerase extends primers from 3’ end
  • (4) cycling (repeat process); DNA polymerase must be thermostable; PCR products double each time, exponentially

DNA polymerase requires a primer

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13
Q

DNA legions

3 examples

if not repaired, legions become mutations

A

DNA legions
- methylation induced mispairing (methylated G with T)
- loss of base
- UV induced pyrimidine dimer (kink)

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14
Q

direct repair

A

-O6-methylguanine DNA methyltransferase transfers 1 methyl off guanine onto cycteine (cannot be recycled)

cell makes entire protein used in reversing 1 mutagenic change

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15
Q

repair of abasic sites

A
  • base falls off by spontaneous hydrolysis of N-glycosidic bond linking them to 1’-OH of deoxyribose (frequent enough in purines)
  • results in abasic site (no base) or an AP site (apurinic/apyrimidinic)

3 step repair: removal of abasic site, resynthesis of complementary strand
(1) AP endonuclease cuts 5’ side of AP site (cleaves backbone)
(2) DNA Pol I resynthesizes and uses 5’ to 3’ exonuclease to degrade ahead (removes AP site via nick translation)
(3) DNA ligase connects 3’ end of resynthesized region to 5’ end of old strand

similar to okazaki fragment resolution

16
Q

base excision repair (BER)

A
  • corrects damaged bases (including uracil in DNA); cells create abasic site deliberately to be repaired with BER
  • DNA glycosylases excise damaged bases (cut glycosyl bond); eg: uracil in DNA, oxidized guanine

(1) cut off base
(2) generate abasic site (AP endonuclease cuts, DNA Pol resynthesizes, ligase connects)

17
Q

nucleotide excision repair (NER)

A
  • excise large strech of damages strand; resynthesize; ligate together

(1) excinuclease cuts damages strands on both sides of large damage (13 nt in bact; 29 nt in euk)
(2) DNA helicase remove region of damage
(3) DNA polymerase I resynthesizes
(4) DNA ligase seals

18
Q

mismatch of undamaged bases

molecular signal?

A
  • errors in replication introduce mismatches of two undamaged bases
  • recognized by MutS/MutL (not AT or CG)
  • repair strategy is remove & resynthesize
19
Q

mismatch repair (mmr)

in bacteria

A
  • bacteria use DNA methylation to mark parental/old strand (does not affect base pairing)
  • old strand methylated, new strand unmethylated; genome hemi-methylated just after replication (bacteria assume methylated parental strand is correct)
  • unmethylated strand degraded & resynthesized
  • new strand becomes methylated quickly; short window when this can be distinguished

(1) loop out mismatch
(2) scan both sides for hemi-methylated site via MutH protein; cleave unmethylated strand (can lie 5’ to 3’ relative to mismatch on newly-synthesized strand; exonucleases can travel both dir)
(3) strand degraded and resynthesized by DNA Pol III

20
Q

mismatch repair (mmr)

in eukaryotes

A
  • eukaryotes recognize mismatches (via MutS/MutL)
  • no hemi-methylation; repair closely follows replisome
  • on lagging strand, new/”wrong” strand has Okazaki fragments, which are cut and resynthesized
  • leading side: unknown how cell distinguishes from old
21
Q

trans-lesion synthesis (SOS) & strand invasion

what response is activated in bacteria? polymerases used in bacteria? // protein involved in strand invasion? steps? junction name?

A

trans-lesion synthesis
- unrepaired errors may block DNA replication
- in bacteria, SOS response induced (when ssDNA stalled at rep fork) which activates error-prone DNA polymerases (IV and V in e coli)
- this process is low fidelity/no proofreading; but anything is better than nothing

strand invasion
- unrepaired nick results in replication collapse; polymerase runs to end of template and stalls
- not spontaneous: RecA polymerizes along single strand; initially aded by RecBCD; promotes invasion of single strand
(1) exonuclease removes 5’ end, freeing 3’ region (to be extended)
(2) free 3’ end invades intact duplex (strands swap basepairing)
(3) branch migration far enough via point of strand exchange so processed end also pairs
(4) now we have 2 double helices connected at a **holiday junction ** where strands exchange (X shape); crossed-over strands cut and religated with no crossover

22
Q

recombinational repair (HR)

(in eukaryotes)

similar with repair of replication fork collapse (5’end resection; strand invasion); steps? fixes what?

A
  • fix double stranded breaks by copying the homologous chromosome (serves as repair template)
  • 2 strand invasions; 2 holiday junctions
    (1) both ends of break processed with 5’ end resection
    (2) Rad51 mediates strands invasion onto intact repair partner
    (3) Rad51 scans duplex for match; generates 2 holiday junctions & resynthesizes both ends of broken dna
23
Q

end joining (NHEJ)

steps? two proteins used?

A
  • homologous recomb is good pathway when DNA rep occuring; but other times, non-homologous end joining is better
    (1) Ku70 and Ku80 form ring that binds to ends of ds-break
    (2) nucleotides removed at site of break
    (3) translesion polymerases can fill in some gaps if needed
    (4) DNA ligase joins 2 ends together

“stitch & fix” .. error-prone repair