Leason 3: Radio Wave Characteristics Flashcards
Which of the following types of propagation is most commonly associated with occasional strong signals on the 10, 6, and 2 meter bands from beyond the radio horizon?
A. Backscatter
B. Sporadic E
C. D layer absorption
D. Gray-line propagation
B. Sporadic E
Sometimes you will hear amateur stations located past the horizon on 10 meters, 6 meters and 2 meters with strong signals. These over-the-horizon signals are being reflected by the E layer of the atmosphere. This propagation type is called sporadic E.
What weather condition might decrease range at microwave frequencies?
A. High winds
B. Low barometric pressure
C. Precipitation
D. Colder temperatures
C. Precipitation
Which of the following results from the fact that signals propagated by the ionosphere are elliptically polarized?
Either vertically or horizontally polarized antennas may be used for transmission or reception.
What is the relationship between the electric and magnetic fields of an electromagnetic wave?
A. They travel at different speeds
B. They are in parallel
C. They revolve in opposite directions
D. They are at right angles
D. They are at right angles.
Notes: A radio wave has two components: the electric and magnetic fields. The two fields of an electromagnetic wave are at right angles to each other.
What is the approximate velocity of a radio wave in free space?
A. 150,000 meters per second
B. 300,000,000 meters per second
C. 300,000,000 miles per hour
D. 150,000 miles per hour
B. 300,000,000 meters per second
What is the effect of vegetation on UHF and microwave signals?
Absorption.
When using a directional antenna, how might your station be able to communicate with a distant repeater if buildings or obstructions are blocking the direct line of sight path?
Try to find a path that reflects signals to the repeater.
What property of a radio wave defines its polarization?
The orientation of the electric field.
Why are simplex UHF signals rarely heard beyond their radio horizon?
UHF signals are usually not propagated by the ionosphere.
What band is best suited for communicating via meteor scatter?
A. 33 centimeters
B. 6 meter band
C. 2 meter band
D. 70 centimeter band
B. 6 meter band.
Communications via meteor scatter occurs when radio waves are reflected back to Earth from the ionized atmosphere because meteorites are entering Earth’s atmosphere and burning up on entry. The 6-meter, or 50 MHz, band is excellent for meteor scatter communications because of its wavelength.
What are the two components of a radio wave?
A. Impedance and reactance
B. Voltage and current
C. Electric and magnetic fields
D. Ionizing and non-ionizing radiation
C. Electric and magnetic fields
What is the effect of fog and rain on signals in the 10 meter and 6 meter bands?
A. Absorption
B. There is little effect
C. Deflection
D. Range increase
B. There is little effect
Which of the following effects might cause radio signals to be heard despite obstructions between the transmitting and receiving stations?
A. Knife-edge diffraction
B. Faraday rotation
C. Quantum tunneling
D. Doppler shift
A. Knife-edge diffraction
What is a characteristic of HF communication compared with communications on VHF and higher frequencies?
A. HF antennas are generally smaller
B. HF accommodates wider bandwidth signals
C. Long distance ionospheric propagation is far more common on HF
D. There is less atmospheric interference (static) on HF
C. Long distance ionospheric propagation is far more common on HF
Notes: The amateur radio VHF and UHF and above bands are mostly for communications with other stations that are within line of sight. These bands depend on repeaters to increase their effective range. The HF bands are well suited for long-range communications because their radio waves are reflected back toward earth instead of punching through the ionosphere. The ability of HF frequencies to bounce off the ionosphere and provide long-distance propagation is far more common.
What is the formula for converting frequency to approximate wavelength in meters?
A. Wavelength in meters equals frequency in hertz multiplied by 300
B. Wavelength in meters equals frequency in hertz divided by 300
C. Wavelength in meters equals frequency in megahertz divided by 300
D. Wavelength in meters equals 300 divided by frequency in megahertz
D. Wavelength in meters equals 300 divided by frequency in megahertz.
Notes:
Remember, on the FCC exam you are asked to pick the most correct answer, so 2.047474 meters is closer to 2 meters than 20 meters.