LAB PRACTICAL Flashcards

1
Q

Measurement estimates

A

one value beyond the last marking on measurement device

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2
Q

Pharmacokinetics

A

process by which drug is absorbed, metabolized, eliminated

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3
Q

Catalysis

A

increase in rate of reaction due to participation of catalyst which lowers activation energy

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4
Q

Order of reaction

A

determined by coefficient in balanced equation but must be determine EXPERIMENTALLY

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5
Q

Arrhenius Equation

A

k = Ae^_Ea/RT with R = 0.008314, Ea = activation energy

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6
Q

Greater activation energy means

A

slower rate

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7
Q

Chemical Kinetics Reaction Rate

A

Rate = k [Fe3+]m[I-]n (we determined m and n experimentally)

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8
Q

Chemical Kinetics Rate in terms of Triiodide ion

A

Rate =Δ[I3-] / Δt

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9
Q

What was Fe3+ conmibed with

A

I- and S2O3 2-

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10
Q

Chemical Kinetics Plot

A

y = ln(Rate) x = ln([I-]_ with slope = n

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11
Q

Methyl green

A

green color with seven methyl groups attached, parent dye has 0 groups

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12
Q

Rate of Decolorization [OH-]

A

[OH-] = 4.5 x 10^-2 x [PO4 3-] / [HPO4 2-]

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13
Q

Rate of Decolorization rate law

A

rate = k1[dye][H2O] + k2[dye][OH-]

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14
Q

Dye and Absorbance

A

[dye] = A / e L
-lnA = kobst -lnA0

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15
Q

Graph -lnA versus time

A

slope is observed rate constant

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16
Q

What is the slope of Kobs vs. [OH-] equal to

A

= K2, kobs = k1[H2O] + K2[OH-]
K1[H2O] remains constant and does not effect slope (acts as an intercept)

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17
Q

ΔG°= (2 equations)

A

ΔG° = ΔH° - TΔS°
ΔG° = -RTlnK

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18
Q

If K > 1

A

ΔG° < 0 and the process will proceed in the forward direction

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19
Q

lnK =

A

lnK = -ΔH° / RT + ΔS° / R

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20
Q

Ksp is independent or dependent on temperature

A

dependent

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21
Q

Plot lnK versus 1/T

A

slope is -ΔH°/R

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22
Q

Ice cream freezes

A

at a lower temperature than the freezing point of water so rock salt is added

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23
Q

m =

A

m = moles solute / kg solvent

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24
Q

is molality temperature dependent or independent

A

independent

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25
Vant Hoff Factor
number of dissolved particles the solute contributes
26
m = (with VHF)
m = Δtf / I kf
27
Natural dye in solar cell experiment
TiO2 stained and dye absorbs light from sun to produce flow of electrons
28
Semi conducting material
TiO2, titanium dioxide
29
How to electrons flow in solar cell
from TiO2 coated electrode to the counter electrode producing electricity
30
What does the dye molecule release when it absorbs light
electrons
31
Mediator
Iodide ion in the electrolyte
32
Voltage
difference in energy levels of TiO2 and mediator
33
Current is directly proportional to
amount of light or number of photons absorbed by the dye
34
Power of solar cell
voltage x current in Watts
35
Compound in raspberries that plays a role in solar cell
Anthocyanin (carbohydrate) (REVIEW STRUCTURE)
36
Chelation
bonding in ions and molecules to metal ions, involves presence of two separate bonds between polydentate ligand and single central metal atom (REVIEW STRUCTURE)
37
Mediator oxidation
I- + I2 <--> I3 -
38
Mediator reduction
6e- + 3I2 <--> 2I3-
39
Common uses of TiO2
toothpaste and food coloring
40
Area of solar cell to produce 1 watt?
1 watt = Power Watt x Area
41
Commercial vinegar contains
5-6% acetic acid
42
Percent Error =
Absolute Value of Actual - Experimental / Actual x 100
43
Molarity Calculations
M1V1 = M2V2
44
Percentage (w/v) acetic acid in vinegar
mol / L x 1L / 1000 mL x 5.00 mL = mol x mol x g / mol = x g / 5.00 mL = X x 100
45
Examples of coordination compounds
hemoglobin, vitamin b12, chlorophyll
46
Ammonia serves as
ligand
47
Sulfate ion serves as
counter ion
48
Copper coordination compound formula
Cux(NH3)y(SO4)z x H2O
49
Color indicator in volumetric analysis of ammonia
methyl orange
50
Beer Lambert Law
absorption of light as it passes through solution is proportional to the concentration of the absorbing species
51
Empirical formula
Cu(NH3)4(SO4)
52
Bonsted-Lowry acid
proton donor
53
Strong acid
ionizes essentially to completion
54
Larger Ka
stronger acid
55
Equivalence point
final solution neutral (equal moles), where amount of base has been added, + 1 drop is light pink, vertical on curve
56
End point
1 final drop turned light pink
57
After reaching equivalence point
pH is high due to excess base
58
Ka =
Ka = [A-][H3O+] / [HA]
59
Ionization equation
[A-] = [H3O+] because 1:1 mole ratio
60
Titration data M
MaVa=MbVb Ma=MbVb / Va
61
Percent ionization =
% = [H3O+] / Ma x 100
62
Buffer solution
contains weak acid and conjugate base
63
Henderson-Hasselbalch
pH = pKa + log [A-] / [HA]
64
Halfway point
pH 1/2 = pKa
65
1st derivative
max, equivalence point, intersection with x-axis
66
2nd derivative
inflection point, change = 0
67
Saturated solution
in state of dynamic equilibrium between dissolved, dissociated, ionic compound and undissolved solid
68
The solubility of an ionic compound is
lower than a solution containing a common ion than in pure water
69
Ksp Barium Nitrate
Ksp = [Ba2+][NO3]2
70
Dynamic Equilibrium
rate of forward = rate of reverse
71
Equilibrium constant
Keq = [products] / [reactants]
72
Equilibrium constant graph
y axis = A/([Fe3+]I [SCN-]I) x axis = A x ([Fe3+]I + [SCN-]I) / ([Fe3+]I [SCN-]I) slope = -Keq
73
Freezing point
temperature when solvent in solution and pure solid have same vapor pressure
74
Larger Ka
more ionization and stronger