Lab Assessment Flashcards
First law of thermodynamics
Energy cannot be created nor destroyed, only altered
If heat is lost by the system, it is Gained by the surroundings, and vice versa
q system = -q surroundings
q = heat
q>0
q is positive
Heat flows in
Object heats up, surroundings cool down
Product-sided
Temperature change does not necessarily accompany heat flow
q<0
q is negative
Heat flows out
Object cools down, Surroundings heat up
Reactant-sided
Temperature change does not necessarily accompany heat flow
Heat capacity
Specific heat capacity, c, is a measure of a materials resistance to temperature change
Greater heat capacity =…
For a constant mass of material (m) and amount of heat exchanged (q), a material with a greater heat capacity is more resistant to temperature change
Formula to find heat lost or gained by a system
q = mc(Tf-Ti)
q is heat transferred into or out of material, typically in units of J, can be positive or negative
m is mass of material, typically in units of g
c is specific heat of material, typically in units of J/gCelsius or J/gK
Delta T is temperature change of material due to the gained or lost heat
For two materials, A and B, in thermal conduct in an isolated system, then…
For two materials, A and B, in thermal conduct in an isolated system, like a perfect calorimeter, then qA=-qB
Calorimeter
Main purpose is to contain the heat transfer between two systems (a chemical reaction and surrounding solution) and limit heat exchanged with the surroundings
Without calorimeter, there is no way to know how much heat is exchanged with the surroundings
Experimental enthalpy change
When an aqueous reaction is carried out in a constant-pressure calorimeter, q reaction ~=~ -q solution
Under constant pressure, q reaction = (n)(delta H), where n is moles of reactions that occur
q solution = m solution * c solution * delta T solution
(n)(delta H) = -m solution * c solution * delta T solution
Delta H can be found by (-m solution * c solution * delta T solution)/(n)
Final units = kJ/mol
Enthalpy change
Delta H
Represents the heat absorbed or released by the reaction under constant pressure
Delta H > 0
Reaction is endothermic and absorbs heat
q > 0
Delta H < 0
Reaction is exothermic and releases heat
q < 0
Determining Tf and Ti through calorimeter graph
Tf (extrapolated) is the y-intercept, if it were to occur instantaneously
Expected enthalpy change
Sum the enthalpies of formation of reactants and subtract that from the sum of enthalpies of formation of products
Ex:
A + B -> C + D
(C+D) - (A+B) = expected delta H
NOTE: make sure to balance equation given, and multiply the each enthalpy by its moles
Ex:
2A + B -> C + D
(C+D) - ((2*A)+B) = expected delta H
Endothermic
q > 0
Delta H > 0
Energy in solution increases
Heat absorbed from surroundings
System gets hotter
Beaker would feel cold
Color intensifies with heat
Exothermic
q < 0
Delta H < 0
Energy in solution decreases
Heat absorbed from system
System gets colder
Beaker would feel hot
Color fades with heat
Freezing point depression
Delta Tf is the freezing point depression of a solution due to a dissolved solute, conventionally reported as a positive number even though the temperature is going down
Delta Tf = |Tf solvent - Tf solution|
Delta Tf = i * m * Kf
Freezing point of pure solvent is higher than that of a solution
More concentrated solutions have lower freezing points
Magnitude of freezing point depression is directly proportional to concentration of solute
i
van’t Hoff factor
Represents number of independent solute particles per unit of whole solute in solution
Freezing point depression is a colligative property, so all that matters is the number of solute particles, not the type of solute particles
i = 1 for nonelectrolytes
i = number of dissociated ions for electrolytes
Ex: NaCl -> Na^+ + Cl^- , so i=2
Electrolytes
Substances which, when dissolved, break up into cations and anions
Ex: NaCl turns into Na^+ and Cl^-
Can be identified if consists of a metal and a non-metal, or if its one of the strong acids
Most ionic compounds, most acids, most bases
m
Molality of solute in solution
m = (mol solute)/(kg solvent)
Special measure of concentration that is independent of temeprature
Kf
Freezing point depression constant that depends on the solvent
How to identify freezing point from temperature-v-time data
Temperature is constant over time while material is freezing
Average of data points in flat region of graph
Calculate molar mass using freezing point depression
From Delta Tf = imKf, m can be found. Then use known mass of dissolved solute and known mass of solvent to find molar mass of solute
m = (delta Tf)/(Kfi)
mol of solute = mkg of solvent
molar mass = (mass of solute in grams)/(mol of solute)
Greater magnitude freezing point depression
Means lower freezing point
Means higher freezing point depression