Lab 1: Quality control of Aspirin and Paracetamol Flashcards
What is quality control?
Common practice in the pharmaceutical industry before any new batch of raw material or final product will be used in manufacturing a dosage form such as a tablet
What is the aim of lab 1:
To confirm the identity and determine the purity of paracetamol and aspirin batches and ensure their compliance with BP specficiations
What is the chemical names of Aspirin?
Acetyl salicylic acid
2-acetoxybenzoic acid
Which part of aspirin is hydrolysed when reacting with NaOH?
The ester bond.
What are the main funtional groups used to identify aspirin in the IR spectrum?
from highest wave number: C=O C=C C-C C-O
What is the functional group present in salicylic acid which was not present in acetylsalicylic acid?
The phenol group. This has been hydrolysed from the ester.
NB: the Carboxylic acid group also appears in the salicylic acid IR at around 1700 wavenumber
How many moles of NaOH is required to react with 1 mole of acetylsalicylic acid?
2
What is the equation of the hydrolysis of Acetylsalicylic acid?
Acetylsalicylic acid + 2NaOH -> sodium salicylate + CH2COO-Na+ + H2) + H2SO4 –> salicylic acid
Why was NaOH and sulfuric acid added to aspirin and boiled?
This was an identification test for Aspirin. The normal hydrolysis of acetylsalicylic acid will form a white precipitate, salicylic acid, or aspirin as the end product.
Formation of this white precipitate confirms the tablet is aspirin.
What causes the white precipitate of the aspirin identification test?
Carboxylic acid part of the aspirin reacting with the sulfuric acid.
the sulfuric acid sucks up the sodium, so there is no salt.
The white precipitate is the salicylic acid.
Why was ferric chloride, ethanol and icy water added to the precipitate?
Ethanol further broke up salicylic acid into phenol.
Ferric chloride forms an iron complex with the phenol
Icy water prevents the OH groups from ionising but enabled formation of VW bonds
The colourless solution should have turned purple further confirming the tablet was aspirin.
Why is 0.1M HCl solution used to titrate in the aspirin assay?
0.5M NaOH had a known amount of aspirin added to it. Indicator was also added.
By titrating this against the 0.1M HCl, we can see the volume of HCl required to neutralise the NaOH (Endpoint would be seen from the colour change of yellow to red using phenol red indicator.)
Why is the assay of Aspirin repeated with a blank substance?
This is also titrated with 0.1MHCl solution to determine the amount of HCl required to neutralise the NaOH.
By subtracting the test volume from the blank volume, we can determine the volume of NaOH reacting with the aspirin.
Via further calculations (n=m/M etc) we can determin the AMOUNT of NaOH reacting with aspirin.
How can we calculate the amount of aspirin present in the test sample (from the assay)?
You know the initial concentration of NaOH used was 0.5M
and the volume difference between the blank and test samples (in my group this is 7.12mL or 0.00712L
You can find the number of moles of NaOH and convert to mmol (this is 3.6mmol)
You know that 1 mol of aspirin reacts with 2 mol of NaOH which means 1.8mol of aspirin must have reacted.
The MW of aspirin is 180.15g/mol. now you can find out the mass of aspirin in mg
This comes to 324.27mg.
The percentage purity is out of a 500mg tablet, hence, 64.9%
What must the purity of aspirin in a sample be to pass the quality standards?
99.5-101%