L3 and L4 Measuring GFR And Renal Clearance Flashcards
GFR gives a rough measure of the number of …
Functioning nephrons
Decreased GFR is a key sign of renal disease
A reduction in GFR may indicate a disease progression, or development of a reversible problem
Grading of chronic renal insufficiency and dosages of drugs secreted by kidneys are based on…
GFR (glomerular filtration rate)
Experimentally, the polysaccharide ______ is often used to measure GFR
Inulin
Inulin clearance = GFR
If a material is neither reabsorbed or secreted by the nephron, then…
What goes in must come out
GFR = (Ux)(V)/Px
Where:
Ux = concentration of x in the urine
V = Urine rate
Px = concentration of x in the plasma
The perfect marker for GFR is freely filtered but neither _________ nor _________
Neither reabsorbed nor secreted
Inulin clearance is the gold standard but it is not commonly used clinically
_____________ clearance and plasma _____________ concentration are frequently used as indicators of GFR in clinical practice
Creatinine
Other techniques: EDTA, iothalamate clearance
Creatinine is produced by ____________ at a relatively constant rate from breakdown of ___________________.
Skeletal muscle, creatine phosphate
Why use creatinine to measure GFR?
It is freely filtered, not reabsorbed, and is only slightly secreted
It is also already at a steady-state concentration in the blood, if formation and excretion are stable
Blood creatinine levels can provide an estimate of …
GFR over the preceding hours
Calculation of GFR by determining creatinine clearance can be described by the following formula:
Ccr = (Ucr)(V)/Pcr ≈ GFR
Where:
Ccr = Creatinine clearance
Ucr = concentration of creatinine in urine (mg/100ml)
V = volume of urine (ml/min)
Pcr = concentration of creatinine in plasma (mg/100ml)
Normal Ccr ≈ 80-110 ml/min/1.73m2
Method for sample collection in order to properly measure GFR
Patient voids on arising at 7 am, urine discarded
Urine collected for 24 hours, including specimen on arising on the following morning at 7 am
Blood same also taken during the same 24 hour period
Ccr = (U x V) / P
Where U = concentration of Cr in urine
V = volume of urine
P = Concentration of Cr in plasma
If a patient’s
Urine flow (V) = 2.0 ml/min
Urine [Cr] = 0.6 mg/ml
Plasma [Cr] = 0.01 mg/ml
What is the patient’s GFR?
GFR = (U x V)/P = (0.6 x 2.0)/(0.01) = 120 ml/min
What if all you have is the plasma [Cr]?
You can estimate GFR based upon their inverse relationship.
Several algorithms exist for estimating GFR based on plasma creatinine, based on large data sets
The different algorithms used to estimate GFR based on plasma creatinine
Cockcroft-Gault equation
- requires age, weight, sex and Pcr
MDRD 4 (Modification of Diet in Renal Disease) - requires age, sex, race, and Pcr
Chronic Kidney Disease Epidemiology Collaboration (CKD-EPI)
- requires age, sex, race, and Pcr
What is Blood Urea Nitrogen (BUN)
Amino acid catabolism in the liver produces urea —> urea synthesis varies with protein intake and liver function —> about 1/2 of the filtered urea is reabsorbed (reabsorption increases when GFR is low)
________ is not a good GFR marker
BUN
__________ represents the volume of plasma that is cleared of a given solute per minute.
Clearance
Cx = (Ux)(V)/(Px)
Normal Cr clearance is ________ for females and _________ for males
≈85-125 ml/min for females
≈97-140 ml/min for males
Clearance of a secreted substance will be greater than Ccr, thus greater than GFR
Clearance of reabsorbed substances will be less than Ccr and less than GFR (ex: glucose, complete reabsorption, clearance is zero)
If GFR = 125 ml/min (from Cr plasma)
Px = 0.02 mg/ml
Ux = 0.10 mg/ml
V = 2.5 ml/min
Is Substance X secreted or reabsorbed?
Start with clearance:
Cx = (Ux x V)/Px = (0.10 x 2.5)/0.02 = 12.5 ml/min
12.5 < 125
Substance X is reabsorbed
If GFR = 125 ml/min
Px = 0.008 mg/ml
Ux = 2.5 mg/ml
V = 1.8 ml/min
Is Substance X secreted or reabsorbed?
Cx = (2.5 x 1.8)/0.008 = 562.5 ml/min
562.5 > 125
Substance x is secreted
If GFR = 125 ml/min
P(ur) = 0.15 mg/ml
U(ur) = 3.9 ml/ml
V = 2.5 ml/min
Is Urea secreted or reabsorbed?
C(ur) = (3.9 x 2.5)/0.15 = 65
65 < 125
Approximately 1/2 of filtered urea is reabsorbed
For glucose: GFR = 125 ml/min P(glucose) = 1.0 mg/ml U(glucose) = 0 mg/ml V = 2.5 ml/min
Is glucose reabsorbed or secreted?
Because U = 0, and C = (UxV)/P so C = 0
100% of the filtered glucose is reabsorbed
Clearance ratios allow us to compare the clearance of any substance with…
Inulin clearance
Clearance ratio = C(x)/C(inulin)
If C(x)/C(inulin) = 1.0 the substance must also be a GFR marker (filtered, but neither secreted nor absorbed)
C(x)/C(inulin) < 1.0 —> Either substance is not filtered, or it is filtered and reabsorbed
C(x)/C(inulin) > 1.0 —> The substance is filtered and secreted
What does Para-Aminohippurate (PAH) tell us about renal plasma flow?
Since all the blood is cleared of PAH, C(PAH) is an estimate of RPF.
PAH in plasma —> some PAH is filtered —> all the remaining PAH is secreted —> all of the PAH is excreted in urine, none is left in the plasma
C(PAH) = (Upah x V)/Ppah = (540ml/min)(1)/(1) = 540 ml/min ≈ RPF
If we use PAH to estimate RPF, how can we determine renal blood flow (RBF)?
RBF = RPF/(1-Hct)
If Hct = 0.4 and RPF = 540 ml/min (from previous example):
RBF = (540)/(1-0.4) = 900 ml/min
The process by which a protein-free filtrate that is otherwise identical to plasma is produced
Glomerular filtration
The process by which waste products, metabolites, toxins etc are removed from the peritubular capillaries into the lumen of the tubule
Tubular secretion
The process by which valuable molecules (glucose, amino acids, etc) are moved from the tubular lumen back to the peritubular capillaries
Tubular reabsorption