Kompleksna St.

Question 1

i 0
i 1
i 2
i 3
i 4n+k

Answer 1

1
i
-1
-i
i k

Question 2

Nasprotno stevilo?

Answer 2

-z=-a-bi

Question 3

Konjugirano st.

Answer 3

z(povpr.)=a-bi

Question 4

Absolutna vrednost?

Answer 4

|z|=✔️a2 + b2 = ✔️z•z(povp)

Question 5

Obratno st.?

Answer 5

z -1= 1/a+bi= a-bi/a2+b2

Question 6

Deljenje?

Answer 6

Mnozis stevec in imenovalec z konjugiranim imaginarnim stevilom, ki je v imenovalcu.

Question 7

Z•(konjug)Z=?

Answer 7

(A+bi)•(a-bi)=a2+b2