Kinetic Theory (unit 3) Flashcards

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1
Q

Equation of states for ideal gas?

A

Pv =nRT or NkT

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2
Q

What is R in the equation?

A

molar gas constant

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3
Q

What is K in the equation?

A

Boltzmann constant

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4
Q

What are the assumptions of molecules in KINETIC THEORY? MAIN ONES

A

-R - random movement of particles
-A- attraction , none between particles
-V- volume, negligible volume of particles, compared to volume of gas
-E- elastic collisions between particles, no KE lost, Ek is conserved
-D- duration of collisions is very short, compared to time between collisions

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5
Q

Behaviour of gases 3 things?

A
  • Pressure ∝ 1/Volume at a constant temperature (T)
  • Pressure ∝ Temperature at a constant volume
  • Volume ∝ Temperature at a constant pressure
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6
Q

How is pressure exerted by a gas on a container?

A
  • molecules have random movement
  • molecules collide with container wall and rebound (momentum changes)
    -Newton’s 2nd law- rate of change of momentum equal to force so the wall exerts a force on molecules
  • Newton’s 3rd law- wall exerts force on molecule, molecule exerts force on wall of container, this force provides the pressure as p = F/A
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7
Q

Units for mean square speed?

A
  • m^2 s^-2
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8
Q

Why do we use mean square speed?

A

-the energy of the PARTICLES is distributed randomly,
-way of representing the speed of an average molecule.

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9
Q

Units for root mean square speed?

A

m s^-1.

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10
Q

What is meant by Agrovado’s constant?

A

the number of particles in one mole of a substance.

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11
Q

Molar mas equation?

A

M = Mr/1000

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12
Q

What is Mr?

A

-relative molecular mass

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13
Q

What 2 equations you need to show that the total
translational kinetic energy of a mole of a monatomic gas?

A

pV=nRT p= 1/3 N/V m c^2

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14
Q

Expression for the total translational kinetic energy of a gas? derivation

A

-make second equation equal to pV
-equate them so we get nRT=1/3 Nmc^2
-multiply both sides by 3/2 so we get 3/2 nRT = 1/2 Nmc^2

  • for ONE MOLE OF GAS , total translational kinetic energy 3/2 RT as for 1 mole n=1 and N=Na
    -so 3/2 RT = 1/2NaMc^2 (this is total translational kinetical energy
  • so KE of 1 molecule is 3/2 RT
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15
Q

What does 3/2 RT and 3/2 KT show about KE?

A

Since R and k are constants, these equations show that the kinetic energy is directly proportional to the absolute temperature of the gas.

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16
Q

What can you get with number of moles?

A

n = N (number of molecules) /Na (Agravado’s number)

17
Q

How to get molecular mass?

A

Mass of one molecule/ average atomic mass (u)

18
Q

How to get mass from molar mass?

A

Molar mass x no of moles

19
Q

What does Q mean?

A
  • heat flowing into system
20
Q

What does w mean?

A

-work done by system