Kinetic Theory (unit 3) Flashcards
Equation of states for ideal gas?
Pv =nRT or NkT
What is R in the equation?
molar gas constant
What is K in the equation?
Boltzmann constant
What are the assumptions of molecules in KINETIC THEORY? MAIN ONES
-R - random movement of particles
-A- attraction , none between particles
-V- volume, negligible volume of particles, compared to volume of gas
-E- elastic collisions between particles, no KE lost, Ek is conserved
-D- duration of collisions is very short, compared to time between collisions
Behaviour of gases 3 things?
- Pressure ∝ 1/Volume at a constant temperature (T)
- Pressure ∝ Temperature at a constant volume
- Volume ∝ Temperature at a constant pressure
How is pressure exerted by a gas on a container?
- molecules have random movement
- molecules collide with container wall and rebound (momentum changes)
-Newton’s 2nd law- rate of change of momentum equal to force so the wall exerts a force on molecules - Newton’s 3rd law- wall exerts force on molecule, molecule exerts force on wall of container, this force provides the pressure as p = F/A
Units for mean square speed?
- m^2 s^-2
Why do we use mean square speed?
-the energy of the PARTICLES is distributed randomly,
-way of representing the speed of an average molecule.
Units for root mean square speed?
m s^-1.
What is meant by Agrovado’s constant?
the number of particles in one mole of a substance.
Molar mas equation?
M = Mr/1000
What is Mr?
-relative molecular mass
What 2 equations you need to show that the total
translational kinetic energy of a mole of a monatomic gas?
pV=nRT p= 1/3 N/V m c^2
Expression for the total translational kinetic energy of a gas? derivation
-make second equation equal to pV
-equate them so we get nRT=1/3 Nmc^2
-multiply both sides by 3/2 so we get 3/2 nRT = 1/2 Nmc^2
- for ONE MOLE OF GAS , total translational kinetic energy 3/2 RT as for 1 mole n=1 and N=Na
-so 3/2 RT = 1/2NaMc^2 (this is total translational kinetical energy - so KE of 1 molecule is 3/2 RT
What does 3/2 RT and 3/2 KT show about KE?
Since R and k are constants, these equations show that the kinetic energy is directly proportional to the absolute temperature of the gas.