JUNE 2011 Flashcards
Give one way in which the structure of an mRNA molecule is different from the structue of a tRNA molecule (1 mark)
- tRNA molecules contain hydrogen bonds
Explain the difference between pre-mRNA and mRNA (1 mark)
- pre-mRNA contains introns whereas mRNA does not
Explain why the percentages of bases from the middle part of the chromosome and the end part are different (2 marks)
- Different genes present
- Different base sequences i
- pre-mRNA transcribed from different DNA base sequence
Describe how hormones are different in the cells that they affect (1 mark)
- Affect cells with only the right receptor
Describe how hormones and local chemical mediators reach the cells they affect (2 marks)
- Hormones in the blood
2. Local chemical mediators are spread by diffusion
Synapses are unidirectional. Explain how acetylcholine contributes to the synapse being unidirectional. (2 marks)
- Ach released from the presynaptic side
- Diffusion from higher to lower concentration
- Receptors in the postsynaptic side
When a young shoot is illuminated from one side, IAA stimulates growth on the shades side. Explain why growth on the shaded side helps to maintain the leaves in a favourable environment (2 marks)
- Leaves bend towards the light
2. Light used in photosynthesis
Scientists can separate DNA fragments using electrophoresis. Suggest how they can use electrophoresis to estimate the number of base pairs in the separated fragments. (2 marks)
- Smaller fragments of DNA will move faster
2. Compare the distance moved by each fragment to see how the different fragments contain a different number of bases.
Scienists need to take precautions when they carry out restriction mapping. They need to make sure that the enzyme they used has completely digested the DNA. One change they may carry out is to add the sizes of fragment together. How could the scientists use this information to show that the DNA has not been completely digested? Explain your answer. (2 marks)
- Large pieces of DNA present
- Add up to more than total length of original DNA
- Because this would add undigested to total original DNA
Papaya plants reproduce sexually by means of seeds. Papaya plants grown from seeds are very variable in their yield. Explain why. (2 marks)
- Meiosis occurs
- Crossing over/ Independent segregation occurs
- Fusion of genetically different gametes/ random fertilisation
Explain the advantage of growing papaya plants from tissue culture rather than from seeds (1 mark)
- Will be genetically identical so all plants will have the same desirable characteristics
Explain how an increase in the iguana’s body temperature affects its oxygen consumption when it is at rest (3 marks)
- Increase in temperature increases the rate of reactions
- More ATP needed
- Oxygen consumption increases so more aerobic respiration can occur
The units in the table allowed the scientists to compare the oxygen consumption’s of different iguanas. Explain how. (1 mark)
- Units given per gram
The behaviour of the desert iguanas keeps their body temperatures within a narrow range. Explain how. (2 marks)
- Outside the optimum temperature the iguana moves between sun and shade.
- To either warm up or cool down
At high temperatures, a desert iguana keeps its mouth wide open and breathes in and out rapidly. This is called panting. Explain how panting helps to reduce the body temperature of an iguana. (2 marks)
- Panting allows evaporation of water from the lining of the mouth
- Heat transferred from the blood to the outside environment