JLH Chem Ch 5 Flashcards
Consider the reaction of hydrogen and oxygen to form water, according to the balanced equation: 2 H2 + O2 –> 2 H2O. Identify the limiting reactant in the molecular art.
Count how many molecules each: 3 O2 4 H2
Consider the reaction of hydrogen and nitrogen to form ammonia, according to the balanced equation:
3 H2 + N2 -→ 2 NH3
Identify the limiting reactant in the molecular art.
H2 is the limiting reactant
Using the balanced equation for the reaction of H2 with O2 to form H2O, determine the limiting reactant with
5.0 mol H2 and 5.0 mol O2
H2 is the limiting reactant
Using the balanced equation for the reaction of H2 with O2 to form H2O, determine the limiting reactant with
8.0 mol H2 and 2.0 mol O2
O2 is the limiting reactant
The amount of A2, the limiting reactant, determines how much AB can form. Because the balanced equation shows that each A2 molecule forms two AB molecules, three A2 molecules form how many AB molecules?
six AB molecules
Using the balanced equation, 3 H2 + N2 -→ 2 NH3
Calculate the number of moles of product formed from 5.0 moles of H2 and 3.0 moles of N2
Identify H2 as the original quantity and use the mole ratio from the balanced equation as a conversion factor to calculate how much N2 is needed for complete reaction.
Using the balanced equation, 3 H2 + N2 -→ 2 NH3, calculate the number of moles of product formed with
1.0 mole H2 and 2.0 mol N2
0.67 mol
Using the balanced equation, N2 + O2 -→ 2 NO,
determine the limiting reactant when 10.0 g of N2 (molar mass 28.02 g/mol) react with 10.0 g of O2 (molar mass 32.00 g/mol)
Using the balanced equation, N2 + O2 -→ 2 NO,
determine the limiting reactant for:
12.5 g N2 and 15.0 g O2
(N2 molar mass 28.02 g/mol; O2 molar mass 32.00 g/mol)
N2
Using the balanced equation, N2 + O2 -→ 2NO,
calculate the number of grams of NO (molar mass 30.01 g/mol) formed when 10.0 g of N2 (molar mass 28.02 g/mol) react with 10.0 g of O2 (molar mass 32.00 g/mol)
1st, determine the limiting reactant (O2)
Using the balanced equation, N2 + O2 -→ 2 NO,
determine the limiting reactant:
12.5 g N2 and 15.0 g O2
(N2 molar mass 28.02 g/mol; O2, molar mass 32.00 g/mol)
N2
Using the balanced equation, N2 + O2 -→ 2 NO,
calculate the number of grams of NO (molar mass 30.01 g/mol) formed when 10.0 g of N2 (molar mass 28.02 g/mol) react with 10.0 g of O2 (molar mass 32.00 g/mol)
1st, determine limiting factor (O2)
How many of each atom is in
C2H6O + 3O2
2 C
6 H
7 O
How many of each atom is in
Mg3 (PO4)2
3 Mg
2 P
8 O
How do we balance this equation?
C3H8 + O2 -> CO2 + H2O
Place coefficient 3 before CO2 on right side
Place coefficient 4 before H2O on right side
Place coefficient 5 before O2 on left side