IV Injection Lectures Flashcards

1
Q

What’s the difference between an IV bolus and an IV infusion?

A

An IV bolus is injected very quickly whereas an IV infusion is administered much slower

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2
Q

What are the advantages and disadvantages of an IV bolus injection?

A

Gets a high concentration of the drug very fast

Useful for emergency treatments as a result

However must monitor for toxicity and irritation

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3
Q

What ADME processes are NOT associated with IV injections? Why?

A

Absorption and the first pass effect. This is because the drug doesn’t need to be absorbed since it directly enters systemic circulation. Because of this there is also no first pass effect, drug is distributed into the tissues before passing the liver.

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4
Q

What is the disposition of a drug? Why is this considered in IV injections?

A

A given drug’s elimination and distribution characteristics

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5
Q

Describe the plasma profile of an IV bolus. What are the two phases?

A

Initial distribution phase where concentration of drug rapidly falls due to the distributing out of the plasma.

Elimination phase where equilibrium is determined. Slow decline due to elimination of the drug from the body.

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6
Q

When the distribution phase is very short what model do we use?

A

The one-compartment model

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7
Q

Why is the one compartment model suitable for drugs with very short distribution phases?

A

Only the elimination phase is observed thus we can assume the body is acting as a single compartment.

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8
Q

What is the first order elimination equation for the one-compartment model (in amount of drug and in concentration)?

A

C = C0*e^-kt

A = A0*e^-kt

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9
Q

What are the assumptions of the one-compartment model?

A

Volume of the compartment equals volume of distribution.

Elimination is first order

Elimination follows linear kinetics

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10
Q

How can we determine k graphically?

A

By calculating the gradient

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11
Q

How would you apply the 1st order elimination equation to any two points in time?

A

Substitute variables x and x0 for x2 and x1

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12
Q

How can you determine the kinetics of a drug from semilog paper? Why can’t you calculate k from semilog paper?

A

If zero order, horizontal line
If first order, straight diagonal line
If second order, curved line

Can’t calculate k from semilog paper due to the logged axis, too hard to identify the gradient accurately. Excess calculations required.

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13
Q

What equation links clearance to the elimination constant?

A

Cl = V*k OR k = Cl/V

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14
Q

What is the elimination half life?

A

The amount of time for half of the drug to be eliminated

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15
Q

How can we use successive half lives to “predict” a drug concentration at a given time?

A

By calculating the number of half lives that would pass to reach a given time, we therefore know how many times the original concentration must be halved to estimate the concentration at a given time.

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16
Q

What is the equation for AUC?

A

AUCinf = C0/k

17
Q

What equation relates AUC to clearance?

A

AUCinf = D/Cl

18
Q

Why is AUC the preferred method to. estimate clearance?

A

It is model independent and thus always correct regardless of the PKs of a drug.

19
Q

Elimination half life equation? How do you derive it?

A

t1/2 = 0.693/k

If you can’t remember it, derive it from the regular ln equation

20
Q

What are the advantages and disadvantages of IV infusion?

A

Drug plasma levels can be easily controlled, constant drug plasma levels can be achieved whilst suffering less problems due to irritation or toxicity from the drug.

However,

It requires continuous monitoring, requires drugs to be quite soluble and stable and can’t be used on fluid restricted patients.

21
Q

What must be considered with an IV infusion that isn’t with an IV bolus?

A

An input rate must be considered with an IV infusion.

22
Q

One compartment IV infusion equation?

A

C = (R/Cl)(1-e^-kt)

23
Q

What are the three phases of IV infusion?

A

Accumulation phase

Plateau/steady state phase

Post-infusion phase

24
Q

Why is the steady state IV infusion equation so simple?

A

Since over long periods of time (1-e^-kt) equates to 1 and thus can be removed.

25
IV post infusion equation? What does this equation resemble?
C post inf = C0*e^-kt post inf The IV bolus equation
26
What variable do we need in order to deriver the value of k in the elimination of any drug?
The value of t 1/2
27
What is the first order half life equation?
t 1/2 = 0.693/k
28
What equation is used to predict the time taken to reach the steady state?
ln(1-F) = -k*tF
29
What is the fraction of the steady state equation? What variables does it depend on?
ln(1-F) = -k*tf It depends on the half life and therefore depends on the clearance of the drug as well as apparent volume of distribution.
30
What value do we set F to when trying to predict the time taken reach the steady state concentration? Why?
0.99 As close to 1 as possible. A value of 1 would however result in ln(1-1) = ln(0) which is a mathematical error.
31
How many half lives does it take to reach the steady state for ALL drugs?
More than 4 half lives (4 Half lives is 94% of the plateau)
32
What is the benefit of combining IV bolus and IV infusion when administering a drug?
Bolus provides immediate concentration, infusion maintains concentration long term.
33
How is the equation for bolus dose followed by infusion made easier to understand?
We perceive the value of the overall amount of drug as the sum of the drug from each form of administration. This is extrapolated to the 1st order concentration equation.
34
What is the equation for a bolus loading dose followed by an infusion? Which portion is dedicated to infusion? How do you know?
C = C0*e^-kt + Css(1-e^-kt) The latter half is dedicated to the IV infusion. This is because it involves the steady state equation.
35
What method should be followed when answering questions about the change in infusion rate?
Separate the question into a timeline: 1st infusion, second infusion, post second infusion. List the timings for each to calculate t values.