Ionisation Energy Questions Flashcards

1
Q

Define first ionisation energy

A

First ionisation energy is the energy required to remove one electron from each atom in one mole of gaseous atoms to form one mole of gaseous 1+ ions.

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2
Q

Define successive ionisation energy

A

Successive ionisation energies are a measure of the energy required to remove each electron in turn

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3
Q

Write an equation, including state symbols, for each of the following processes:
First ionisation of manganese

A

Mn(g) → Mn+(g) + e-

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4
Q

Write an equation, including state symbols, for each of the following processes:
First ionisation of sulfur

A

S(g) → S+(g) + e-

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5
Q

Write an equation, including state symbols, for each of the following processes:
Second ionisation of copper

A

Cu+(g) → Cu2+(g) + e-

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6
Q

Write an equation, including state symbols, for each of the following processes:
Third ionisation of potassium

A

K2+(g) → K3+(g) + e-

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7
Q

Write an equation, including state symbols, for each of the following processes:
Fifth ionisation of phosphorus

A

P4+(g) → P5+(g) + e-

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8
Q

Give the electron configuration for the ion produced (above) in the first ionisation of sulfur

A

S+(g) has 15 electrons so is 1s22s22p63s23p3

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9
Q

Give the electron configuration for the ion produced (above) in the fifth ionisation of phosphorus

A

P5+(g) has 10 electrons so is 1s22s22p6

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10
Q

State and explain the trend in first ionisation energies as a Group is descended.

A

• First ionisation energy decreases as a Group is descended, because
Down a Group:
• The number of shells increases / so there is a bigger atomic radius;
• There is more shielding effect due to inner shell electrons;
• The increased shielding effect and increased distance of the outer electron from the nucleus far outweigh the increase in nuclear charge;
• So the nuclear attraction decreases down a Group, hence less energy is needed to remove the outer electron.

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11
Q

State and explain how the first ionisation energy of fluorine compares to the first ionisation energy of carbon.

A

Fluorine has a higher first ionisation energy than Carbon, because
• F has (3) more protons / higher nuclear charge than C
• The outer electron fills the same shell in both F and C (hence same shielding)
• The nuclear attraction is higher in F (hence F has a smaller atomic radius).

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12
Q

Explain why there is an increase in first ionisation energy between Na and Al.

A
  • Al has (2) more protons / higher nuclear charge than Na
  • The outer electron fills the same shell in both Na and Al (hence same shielding)
  • The nuclear attraction is higher in Al (hence Al has a smaller atomic radius).
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13
Q

Explain why there is a decrease in first ionisation energy between F and Na.

A
  • Na has one more shell than F (cannot say atomic radius is bigger as given in question!)
  • The outer electron in Na experiences more shielding than in F;
  • The increased shielding effect (and distance) far outweigh the increase in nuclear charge in Na;
  • So the nuclear attraction in Na is weaker than in F;
  • So less energy is needed to remove the outer electron in Na (than in F).
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