Introduction To Stereochemistry Flashcards

1
Q

Conformation=

A

Different arrangements caused by rotations alone

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2
Q

Conformers

A

Different conformations which are energy minima

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3
Q

Karplus equation

A

Determines size of coupling constant between 2 protons

-varies with dihedral angle

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4
Q

Constitutional/structural isomers

A

Different connectivity between atoms

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5
Q

Configurational isomers (stereoisomers)

A

All have same constitution but structures have different shape and can’t be inter-converted by rotating single bonds

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6
Q

If stereoisomers are non-superimposable mirror images=

A

Enantiomers

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7
Q

If stereoisomers aren’t enantiomers=

A

Diastereomers

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8
Q

Properties of enantiomers

A

Same chemical and physical properties

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9
Q

Properties of diastereomers

A

Properties aren’t the same

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10
Q

Non-optically active diastereomer=

A

Meso form

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11
Q

If there are 2 stereogenic centres

A

Have two sets of enantiomers

The sets are diastereomers of each other

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12
Q

Chiral if:

A
  • no symmetry

- only rotational symmetry

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13
Q

Achiral if:

A
  • plane of symmetry
  • centre of inversion
  • improper rotation axis (rotate then reflect)
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14
Q

Achiral molecules

A

Can be superimposed onto their mirror image

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15
Q

How to resolve enantiomers

A

1) Add enantiomerically pure amine
- > diastereomeric salts (different properties)
2) dissolve in ethanol (one dissolves, the other does not)
3) filter
- >seperate

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16
Q

Diastereotopic protons

A

If compare molecule where Ha is replaced with D with one where Hb is replaced with D, they are diastereomers

  • never in exactly the same environment
  • are strongly coupled to each other
17
Q

Energy of alkenes

A

More substituted= lower in energy

18
Q

Elimination tends to be

A

Antiperiplanar

19
Q

A-value

A

A group’s preference for an equatorial position

20
Q

Trans decalin

A

Locks ring conformation

21
Q

3J (ax-ax)

A

9-13Hz

22
Q

3J (eq-eq)

A

1.5-6.5Hz

23
Q

3J (ax-eq)

A

1.5-6.5Hz

24
Q

2J (geminal)

A

11-14Hz

25
Q

4J (w)

A

1-4Hz

26
Q

Substitution in a ring favours

A

Axial leaving group

- nucleophile approach less hindered, static relief from axial leaving group

27
Q

Epoxide opening

A

Transdiaxial

28
Q

Ring stability

A

5>6>3»4~7