Intermolecular forces Flashcards
London forces?
aka instantaneous dipole-induced dipole
- ALL atoms and molecules form
- weakest intermolecular forces
*any molecule/atom w electrons can form a dipole when they move near to another atom or molecule
London forces step-by-step
*electrons in electron clouds alw moving really quickly/electron density fluctuates over time
1. at any particular moment - electrons in atom likely to be more to 1 side than the other
- at this mo - atom would hv a temporary/instantaneous dipole (LHS & RHS have delta +-)
- this dipole can induce another temp dipole in opp direction on neighbouring atom as electron clouds in both mols repel e/o - pushing electron density of neighbouring mol to far end
- (as e.g. delta+ end of mol A closer to mol B so - electron density of mol B pulled to left so - delta- on LHS & delta+ on RHS so - induced dipole) - 2 dipoles then attracted to e/o
- leaves + and - attracted to e/o - weak attraction = London force
- when mols move away dipole interaction destroyed
3.2nd dipole can induce another in 3rd atom
4. cos electrons constantly moving - dipoles r being created & destroyed all the time
- even tho dipoles keep changing - overall effect = atoms attracted to e/o
London forces hold some molecules in a lattice/crystal structure? e.g. I2
- I atoms held tgt in pairs by strong covalent bonds to form mols of I2
- molecules then held tgt in a molecular lattice arrangement by weak London forces aka simple molecular structure
Features of London forces?
- (the larger the mol, the larger the electron cloud) the more electrons there r in a mol, the greater the fluctuation in electron density (more electron drift) & larger the instantaneous & induced dipoles created
- depend on shape & size of mols - the more points of contact between mols, the greater force
- mols w greater SA - stronger London as bigger exposed electron cloud
- boil liquid/melt solids - breaking weak London forces - stronger forces - more energy - higher bp
- longer, straight chain hydrocarbons have more forces so - more energy needed to overcome - bp increases
- branched hydrocarbons can’t pack tgt as close - weakens forces between chains - lowers bp (molecular surface contact small compared to straight)
Dipole-Dipole
- delta+ & delta- charges on polar molecules cause - weak electrostatic forces of attraction between molecules aka permanent dipole - permanent dipole bonds
- unlike London, these interactions involves molecules w permanent dipole so - stronger
- mols w this hv London asw
- mols that hv both generally hv higher mp & bp w similar London that can’t form dipole-dipole
Testing polar molecules?
- place charged rod bear a steady stream of a polar liquid e.g. water
- shld see liquid bend towards rod as mols align to face opp charged rod
e.g. O delta- &+ rod attracted & bends towards
Hydrogen bonding?
- when H on 1 mol forms bond w lone pair on F, N, O (3 most electronegative elements)
- F, N, O very electronegative so - draw bonding electrons away from H atom
- bond so polarised & H has such high charge density (cos so small) that - H atoms form weak bonds w lone pairs of electrons on F, N, O atoms of other mols
- strongest intermolecular force
- organic mols that form H bonds often contain OH/NH groups
- when comparing: look at how many H bonds each molecule can form
Drawing hydrogen bonding?
- dashed lines between lone pairs on F, N, O & H on other mol
- *lone pairs
- *partial charges
Features of H bonds?
- substances that form H bonds hv high mp & bp - a lot of energy required to overcome H bonding
Why does ice float on water?
- in ice: H2O mols arranged so that there’s max no. H bonds - regular lattice structure
- H bonds hold H2O molecules further apart than liquid - less dense
- as ice melts - some of h bonds broken & lattice breaks down - allowing molecules to ‘fill’ spaces
- so - ice much less dense than H2O - floats
How do the no. hydrogens i’m a molecule limit the number of hydrogen bonds it can form?
- when there aren’t enough hydrogens to satisfy all the lone pairs & vice versa
e.g. HF can only form 1 : as 1 H even tho 3 F lone pairs - e.g. each N in NH3 has 1 lone pair & 3 Hs so - not enough lone pairs to satisfy Hs