Inorganic Chemistry Flashcards
3.2.1
What is the definition of periodicity?
It is the quality or character of being periodic; the tendency to recur at intervals
3.2.1
How is an element classified?
An element is classified as s,p,d,f block when the highest energy electrons are in an s,p,d,f sub-shell.
3.2.1
What are the 2 physical properties trends of period 3 elements?
- Atomic radius
- melting points
3.2.1
Why does atomic radius decrease across a period?
Atomic radius decreases across a period because…
* As the number of protons increase across the period, nuclear charge increase therefore stronger nuclear attraction.
* Therefore outer electrons (which are in the same level across the period) are drawn closer to the nucleus.
3.2.1
Why does the melting point across a period increase?
The m.p.s of metallic elements increase across the period.
* Na ➜ Al, number of outer electrons increase
* Therefore more electrons can be delocalised, leading to a greater attraction between positive ions and delocalised electrons.
* Size of ions decrease across the period, leading to smaller ions, and therefore greater attraction between positive ions and delocalised electrons.
* Therefore more energy required to overcome attraction
3.2.1
Why is the melting point of silicon very high?
The melting point of silicon is very high.
* Si has a giant covalent structure (compared to giant metallic for Na, Mg + Al).
* Therefore a lot of energy is required to break the strong covalent bonds.
3.2.1
Why are the melting points of phosphorus, sulphur, chlorine and argon low?
The m.p.s of phosphorus (P4), sulphur (S8), chlorine (Cl2) + argon (Ar) are low.
* P4, S8 and Cl2 are simple covalent molecules and little energy is required to overcome the weak van der Waals’ forces between the molecules.
* Ar exists as atoms and very little energy is required to overcome the weak van der Waals forces between the atoms.
3.2.1
Why do the melting points of elements after Si increase from phosphorus to sulfur then decrease again?
- attractions between molecules
- nuclear charge
The m.p.s of the elements after Si increase from phosphorus to sulfur then decrease again.
* Attractions between molecules = van der Waals’ forces (as molecules = non-polar).
* Greater the number of electrons, greater the induced dipole attractions, therefore greater van der Waals’ forces of attraction between molecules.
* This increases energy required to overcome attractions.
- P4 number of electrons < S8 no. of electrons therefore m.p. increase P4 to S8.
- S8 number of electrons > Cl2 no. of electrons and Ar has very low m.p. as monoatomic (resulting in very weak van der Waals forces) therefore m.p. decrease again.
3.2.1
Why does the first ionisation energy increase across a period?
- Increase nuclear charge with similar shielding across the period, leading to stronger nuclear attraction.
- Therefore atomic radius decrease across the period.
- Therefore outer electron closer to the nucleus.
*More energy required to remove outer electron.
3.2.1
Why are the first ionisation energy of atoms of group 3 elements lower than expected?
- Group 3’s outer electron is in the p sub shell whilst group 2’s outer electron is in the s sub-shell.
- Therefore group 3’s outer electron is further from the nucleus than group 2’s + has more shielding than group 2 (due to more inner electrons).
- Therefore weaker nuclear attraction, so electron more easily removed (less energy required to do so).
3.2.1
Why are the first ionisation energy of atoms of group 6 elements is lower than expected?
- Group 6 atoms have a p4 arrangement the repulsion of 2 electrons in the same p orbital leads to less energy being required to remove the outer electron.
3.2.2
What are the trends of atomic radius down Group 2?
Atomic radius increases down the group because…
*No. of shells increases down the group
*Therefore more shielding + therefore outer electrons further away from nucleus so…
*weaker nuclear attraction
3.2.2
What are the trends of first ionisation energy down Group 2?
First ionisation energy decreases down the group because:
*Number of shells increases down the group
*Therefore more shielding and Therefore outer electron further away from nucleus so
*weaker nuclear attraction therefore outer electron held less tightly
*Therefore easier to remove outer electron (requires less energy).
3.2.2
What are the trends of melting point down Group 2?
M.p.s decrease down the group because…
*Ions all have a +2 charge and same number of delocalised electrons per atom.
*However, size of metal ions increase down the group therefore atomic radius increase
*Therefore outer electrons further from nucleus so weaker nuclear attraction
*Therefore strength metallic bonding decrease
3.2.2
What are the first 4 metals in Group 2?
- Magnesium (Mg)
- Calcium (Ca)
- Strontium (Sr)
- Barium (Ba)
3.2.2
What occurs when Magnesium (Mg) reacts with water?
Reacts very slowly with warm water - few bubbles.
* Mg(s) + 2H2O(l) → Mg(OH)2 + H2 BUT, reacts vigorously with steam.
* Mg(s) + H2O(g) → MgO + H2
- MgO is formed rather than steam as the hydroxide is not stable at higher temperatures and thermally decomposes to give MgO and H2O.
3.2.2
What occurs when Calcium (Ca) reacts with water?
Reacts with cold water and fizzing is seen in an exothermic reaction. White ppt. forms.
* Ca + 2H2O → Ca(OH)2 + H2
3.2.2
What occurs when Strontium (Sr) reacts with water?
Reacts vigorously with cold water and fizzing is seen in a highly exothermic
reaction.
* Sr + 2H2O → Sr(OH)2 + H2
3.2.2
What occurs when Barium (Ba) reacts with water?
Reacts violently with cold water and fizzing is seen in a highly exothermic reaction.
* Ba + 2H2O → Ba(OH)2 + H2
3.2.2
What is the trend of reactivity down Group 2?
- Why is this the trend
Reactivity increases down the group because
* Metals lose outer electrons when they react.
* As we go down the group number of shells in therefore more shielding.
* Therefore weaker nuclear attraction and electron held less tightly by nucleus as we go down the group.
* Hence electron is lost more easily and metal = more reactive.
3.2.2
How can the Relative Solubilities of Group 2 Hydroxides in Water be found?
- what must be added
The relative solubilities can be found by adding a solution of NaOH to solutions of the Group 2 ions + observing ppt.
3.2.2
What is the solubility of Magnesium hydroxide?
Sparingly soluble in water (as sol. is slightly alkali indicating some OH- dissolved)
= thick white ppt.
* Mg2+(aq) + 2OH-(aq) → Mg(OH)2(s)
3.2.2
What is the solubility of Calcium hydroxide?
Slightly soluble in water = white ppt.
* Ca2+(aq) + 2OH-(aq) → Ca(OH)2(s)
3.2.2
What is the solubility of Strontium hydroxide / Barium hydroxide?
Soluble in water = no ppt.
3.2.2
What is the trend in solubility of hydroxides down Group 2?
The solubility of hydroxides down Group 2 increases
3.2.2
How can the Relative Solubilities of Group 2 sulphates in Water be found?
- what must be added
The relative solubilities can be found by adding a solution of Na2SO4 to solutions of the Group 2 ions + observing ppt.
3.2.2
What is the solubility of Mganesium sulfate?
Soluble in water = no ppt.
3.2.2
What is the solubility of Calcium sulfate?
Sparingly soluble in water = thin white ppt.
* Ca2+(aq) + SO42-(aq) → CaSO4(s)
3.2.2
What is the solubility of Stronstium sulfate?
Insoluble in water = white ppt.
* Sr2+(aq) + SO42-(aq) → SrSO4(s)
3.2.2
What is the solubility of Barium sulfate?
Insoluble in water = thick white ppt.
* Ba2+(aq) + SO42-(aq) → BaSO4(s)
3.2.2
What is the trend in solubility of sulphates down Group 2?
The solubility of sulphates down Group 2 decreases
3.2.2
How do you test for sulfate ions?
1) To 1cm3 of unknown solution add 1cm3 of dilute HCl acid.
* The HCl acid removes any other ions (e.g. carbonate ions) which may affect the test by giving a white ppt. with barium chloride solution = false positive result.
2) Add 1cm3 of barium chloride solution. If sulphate ions present: white ppt formed Ba2+(aq) + SO42-(aq) → BaSO4(s)
- If no sulphate ions present: no ppt formed
3.2.2
What are the Selected uses of the Magnesium and it’s Compounds?
Magnesium is used in the extraction of titanium from its ore.
* The main titanium ore, titanium(IV) oxide (TiO2) is first converted to titanium(IV) chloride (TiCl4) by heating it with carbon in a stream of chlorine gas.
* The titanium chloride is then purified by fractional distillation, before being reduced by magnesium in a furnace at almost 1000°C
- TiCl4 + 2Mg → Ti + 2MgCl2
3.2.2
What are the Selected uses of the Magnesium hydroxide and it’s Compounds?
Mg(OH)2 is used in medicine as a suspension in water known as ‘milk of magnesia’ to neutralise excess acid in the stomach.
3.2.2
What are the Selected uses of the Calcium hydroxide and it’s Compounds?
Ca(OH)2 is used in agriculture in solid form known as ‘slaked lime’ to neutralise acidic soil.
3.2.2
What are the Selected uses of the Calcium oxide / Calcium carbonate and it’s Compounds?
CaO / CaCO3 is used to remove SO2 from flue gases (= by-products of the combustion of fossil fuels) to prevent the formation of acid rain.
3.2.2
What are the Selected uses of the Barium sulfate and it’s Compounds?
BaSO4 is used in medicine as a ‘Barium meal’ given to patients to eat who need x rays of their intestines.
* The barium absorbs the X-rays and so when BaSO4 gets to the gut the outline of the gut can be located using X-rays.
* Although Barium ions are toxic it is safe to use here because barium sulphate is insoluble therefore not absorbed into the blood.
3.2.3
What is the appearance of group 7 elements?
fluorine, chlorine, bromine and iodine
- Fluorine = poisonous pale yellow gas.
- Chlorine = poisonous green gas.
- Bromine = toxic red-brown volatile liquid - it forms a red-brown vapour.
- Iodine = shiny grey solid - it sublimes to form a violet vapour w/ gentle heating.
3.2.3
What are the trends in properties down group 7?
- Electronegativity decreases down the group
- B.p.s increase down the group
- Oxidising power decreases down the group
3.2.3
- Number of shells increase down the group therefore size of atoms increase so.
- bonding electrons in a covalent bond are further from the nucleus + there is more shielding.
- Therefore weaker attraction between positively charged nucleus and bonding pair of electrons.
- Therefore element has lower electronegativity.
3.2.3
- Size of diatomic molecules increase down the group.
- Larger molecules have more electrons, leading to greater induced dipole-dipole forces.
- Therefore greater van der Waals’s forces between molecules.
- Therefore more energy required to overcome the greater van der Waals’s forces as you go down the group.
3.2.3
An oxidising agent accepts electrons.
* Size of ions increase down the group.
* Therefore outer electrons are more shielded and further away from the nucleus.
* Therefore electrostatic force of attraction by nucleus on the additional electron becomes weaker down the group.
* Therefore harder to gain an electron.
3.2.3
in displacement reactions, what would we expect from our knowledge of oxidising powers of halogens decrease down the group?
…Fluorine to displace all other halogens from solutions of halide
compounds.
…Chlorine to displace bromide and iodide from solutions of bromide
iodide compounds.
…Bromine to displace iodide from a solution of an iodide compound.
3.2.3
What occurs when potassium chloride solution KCl (aq) - colourless - reacts with Cl2 (aq), Br (aq), I2 (aq)?
- Cl2 (aq) : no reaction
- Br (aq) : no reaction
- I2 (aq) : no reaction
3.2.3
What occurs when potassium bromide solution KBr (aq) - colourless - reacts with Cl2 (aq), Br (aq), I2 (aq)?
- Cl2 (aq) : orange solution (Br2) formed
- Br (aq) : no reaction
- I2 (aq) : no reaction
3.2.3
What occurs when potassium iodide solution KI (aq) - colourless - reacts with Cl2 (aq), Br (aq), I2 (aq)?
- Cl2 (aq) : brown solution (I2) formed
- Br (aq) : brown solution (I2) formed
- I2 (aq) : no reaction
3.2.3
What does a reducing agent do?
A reducing agent donates electrons. They, themselves, are OXIDISED.
3.2.3
What does a reducing power do?
- why does it increase down group 7
Reducing power increases down the group because:
* Size of the ions increase down the group.
* Therefore outer electrons are more shielded and further away from the
nucleus.
* Therefore electrostatic force of attraction by nucleus on outer
electrons becomes weaker down the group.
* Therefore easier to lose an electron.
3.2.3
What occurs in reactions of solid sodium halides with concentrated sulphuric acid?
- Fluoride (F-)
NaF + H2SO4 → NaHSO4 + HF NOT REDOX - it is an ACID/BASE REACTION
* Observations: misty white fumes (HF) are evolved.
3.2.3
What occurs in reactions of solid sodium halides with concentrated sulphuric acid?
- Chloride (Cl-)
NaCl + H2SO4 → NaHSO4 + HCl NOT REDOX - it is an ACID/BASE REACTION
* Observations: misty white fumes (HCl) are evolved.
3.2.3
What occurs in reactions of solid sodium halides with concentrated sulphuric acid?
- Bromide (Br-)
NaBr + H2SO4 → NaHSO4 + HBr NOT REDOX - it is an ACID/BASE REACTION
2HBr + H2SO4 → Br2 + SO2 + 2H2O REDOX
* Observations, reaction 1:
* misty white fumes (HBr) and red-brown vapour (Br2) are evolved.
* Observations, reaction 2:
- Br is oxidised from -1 (in HBr) to 0 (in Br2) therefore bromine = oxidation product. - S is reduced from +6 (in H2SO4) to +4 (in SO2) therefore sulphur dioxide = reduction product.
3.2.3
What occurs in reactions of solid sodium halides with concentrated sulphuric acid?
- Iodide (I-)
NaI + H2SO4 → NaHSO4 + HI NOT REDOX
2HI + H2SO4 → I2 + SO2 + 2H2O REDOX
6HI + H2SO4 → 3I2 + S + 4H2O REDOX
8HI + H2SO4 → 4I2 + H2S + 4H2O REDOX
* Observations (all these reactions happen in succession - not in isolation): misty white fumes evolved (HI), purple vapour evolved (I2), yellow solid formed (S), rotten egg smell (H2S) + black solid formed (I2).
* Redox:
➜ For the 1st redox reaction.
- the I is oxidised from -1 (in HI) to 0 (in I2) the S is reduced from +6 (in H2SO4) to +4 (in SO2)
➜ For the 2nd redox reaction,
- the I is oxidised from -1 (in HI) to 0 (in I2) the S is reduced from +6 (in H2SO4) to 0 (in S)
➜ For the 3rd redox reaction,
- the I is oxidised from -1 (in HI) to 0 (in I2) the S is reduced from +6 (in H2SO4) to -2 (in H2S)
Therefore oxidation product = iodine; reduction products = sulphur dioxide, sulphur and hydrogen sulphide.
3.2.3
How do you identify halide ions with dilute nitric acid (HNO3), followed by silver(I) nitrate (AgNO3) solution?
- Add dilute nitric acid (HNO3), followed by silver(I) nitrate (AgNO3) solution.
Ag+(aq) + Cl-(aq) → AgCl(s) = white ppt. formed
Ag+(aq) + Br-(aq) → AgBr(s) = cream ppt. formed
Ag+(aq) + I-(aq) → AgI(s) = yellow ppt. formed - The dilute nitric acid removes other ions which would react with the silver nitrate solution (e.g. carbonates/sulphates/hydroxides)
N.B. silver nitrate solution does not form ppt. with fluoride ions in solution as silver fluoride is soluble in water. So, we can’t use it as test.
3.2.3
How do you identify halide ions with ammonia solution?
AgCl: will redissolve in dilute and concentrated ammonia solution to form a colourless solution.
AgBr: does not redissolve in dilute ammonia solution but does redissolve in conc. ammonia solution forming a colourless solution.
AgI does not redissolve in dilute or conc. ammonia solution.
3.2.3
What reaction occurs when chlorine mixes with water?
When you mix chlorine with water, it undergoes disproportionation (This means Chlorine, Cl2 is both oxidised and reduced).
Cl2 + H2O ⇌ HClO + HCl
* The Cl is oxidised from 0 (Cl2) to +1 (HOCl)
* The Cl is reduced from 0 (Cl2) to -1 (HCl)
3.2.3
What are the advantages + disadvantages of chlorine and chlorate?
- Chlorate(I) ions kill bacteria, this is why chlorine is used in water treatment to kill bacteria. It’s been used to treat drinking water and the water in swimming pools.
- The benefits to health (including, the irradiation of bacterial diseases like cholera) from using chlorine OUTWEIGH the fact it’s toxic / carcinogenic to humans.
In sunlight (UV), chlorine can decompose water to form chloride ions and oxygen.
2Cl2 + 2H2O ⇌ 4HCl + O2
3.2.3
What occurs in the reaction of Chlorine with Cold, Dilute, Aqueous NaOH (making bleach)?
- what is observed
When you mix chlorine gas with cold, dilute, sodium hydroxide solution at room temperature it undergoes disproportionation.
Cl2 + 2NaOH → NaCl + NaClO + H2O
* The Cl is oxidised from 0 (Cl2) to +1 (NaClO)
* The Cl is reduced from 0 (Cl2) to -1 (NaCl)
Observation: green gas forms a colourless solution.
One of the products formed is sodium chlorate(I), NaClO. It’s in solution in this case and that is bleach (which kills bacteria)
3.2.4
What are the general properties of transition metals?
Characteristics include:
* complex formation
* formation of coloured ions
* variable oxidation state
* catalytic activity
These properties arise from an incomplete d sub-level in atoms or ions.
Why is zinc not considered a transition metal?
Zinc can only form a +2 ion, which has a complete d orbital and does not have an incomplete d orbital in any of its compounds.
Define a complex in the context of transition metals.
A complex is a central metal ion surrounded by ligands.
What is a ligand?
A ligand is an atom, ion, or molecule that can donate a lone electron pair.
what is a lewis acid?
electron pair acceptor
what is a lewis base?
electron pair donor
ligands act as lewis_______? becasue?
bases because they donate a lone pair to form a coordinate bond
metal ions act as lewis______? because?
acids because they accept the lone pair
What is co-ordinate bonding?
Co-ordinate bonding is when the shared pair of electrons in the covalent bond comes from only one of the bonding atoms.