independent study questions part 1 Flashcards
A flatworm is a simple soft bodied animal. The diagram shows the movement of aquatic flatworm in light and in shade. The path followed by the flatworm over a period of 3 minutes was traced on the side of a tank
Name the type of behaviour shown. Give a reason for your answer (2 marks)
kinesis
movement is random
suggest one advantage to the behaviour shown in the diagram (1 mark)
remains in shade so avoids predators
describe 3 changes in the root tip cells between stages A and D (3 marks)
formation of vacuole
formation of starch grain
cells get longer
the scientists hypothesis was that there was a relationship between the starch grains in the root tip cells and the bending and direction of growth of lateral roots
does the information in the diagram support this hypothesis? Give reasons for your answer (3 marks)
grows sideways as grains form
more bending as grains increase in number
more elongation of cells downwards as starch grains increase
Explain how this distribution of IAA causes the root to bend (2 marks)
IAA at bottom of root where high IAA concentration inhibits expansion of cells
IAA at top of root where low IAA concentration leads to expansion of cells
give one conclusion about the response of maggots which is supported by these results (1 mark)
give evidence from the table for your conclusion (1 mark)
maggots prefer red rather than green
more in red than green but light intensity the same
the chi squared test was used to analyse the data. For the results obtained suggest one null hypothesis which might be analysed by a chi squared test (1 mark)
no difference in response to different light intensities
It was suggested that the movement of the maggots might have been influenced by the Earths magnetic field. Suggest one simple way of repeating the investigation which would avoid this possibility (1 mark)
place magnets around the box to create an alternative magnetic field
the biologist concluded that the worms’ behaviour demonstrated taxis
How do these results support this conclusion (2 marks)
taxis is a directional response
moved towards temperature they were cultured in
Using the information provided, suggest an explanation for the worms’ behaviour on the glass surface in the absence of food (3 marks)
hungry so seeking food
move towards temperature they were cultured in
associate this temperature with food
In each experiment, the biologist exposed the surfaces to light that was dim and even, so he could see where the worms went
Apart from seeing where the worms went, suggest two reasons why it was importing that the light was dim and even (2 marks)
dim light is like their normal environment
even light because worms might move away from bright light
dim light ensures that heat from light is not a variable
the pea seedlings were kept in the dark after each treatment. Explain why this was necessary. (1 mark)
seedlings are phototropic
what conclusion can be made from the results for treatment B? (1 mark)
cells in root tip respond to gravity
Suggest how IAA could have caused results for
treatment A (2 marks)
treatment C (2 marks)
treatment A
more IAA on lower side
lower side grows slower
treatment C
less IAA produced
lower side grows faster
what type of behaviour was shown by the termite from group B? (1 mark)
give evidence for your answer (1 mark)
taxis
moves towards light
explain what the results from group A suggest about the factors controlling the behaviour of winged termites (3 marks)
gravity
antennae involved
doesn’t respond to light as they are unable to see
suggest one advantage to the termites from group C of the behaviour shown in the investigation (2 marks)
helps them to reach the surface
produce new colonies
which of the blood vessels D to G
carries oxygenated blood to the heart (1 marks)
carries deoxyganted blood to the lungs (1 mark)
G
E
explain in terms of pressure, why the semi lunar valves open (1 marks)
pressure is greater in ventricle than artery
when a wave of electrical activity reaches the AVN, there is a short delay before a new wave leaves the AVN. Explain the importance of this short delay ( 2 marks)
allows the atria to empty
before the ventricles contract
use information from the table to explain how training has caused the resting heart rate of this athlete to be lower (2 marks)
increase in volume of heart
cardiac output is the same so must be increase in stroke volume
explain why it takes time for the rod cells to recover their sensitivity to light after moving into darkness (2 marks)
rhodopsin broken down by light time for photosynthesis
use information in figures 1 and 2 to explain the differences in sensitivity of rod cells to red and green light (2 marks)
rhodopsin absorbs green light more readily than red
after re synthesis less intense green light needed to break down rhodopsin than red light
suggest an explanation for the difference in sensitivity of rod cells to the white and green spots after 30 minutes ( 1 mark)
white has high proportion of wavelengths to which rhodopsin not sensitive
describe how a pacinian corpuscle produces a generator potential when stimulated (3 marks)
increases pressure changes stretch mediated sodium ion channel
sodium channels open and sodium ions flow in
depolarisation leading to generator potential
why do these data suggest about the control of heart rate by the parasympathetic and sympathetic nervous systems in response to changes in arterial blood pressure? (3 marks)
parasympathetic greater effect than sympathetic
parasympathetic keeps heart rate down as blood pressure increases
sympathetic keeps heart rate up as blood pressure increases