Imaging with a thick lens Flashcards

1
Q

why use cardinal points?

A

the basic imaging properties such as image size, location, and orientation are completely determined by the locations of the cardinal points

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
2
Q

Where do we act like all the refractions occur at in thick lens?

A

principal planes

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
3
Q

nodal points

A

have the property that a ray aimed at one of them will be refracted by the lens such that it appears to have come from the other. and with the same angle with respect to the optical axis

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
4
Q

Assumptions of thin lenses

A
  • both sides in same medium
  • lens is thin, 0 thickness
  • paraxial approximation
How well did you know this?
1
Not at all
2
3
4
5
Perfectly
5
Q

how can you tell in a thin lens, that the same medium is on both sides of the lens

A

equal focal lengths on either side of the lens

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
6
Q

if the focal length is shorter on one side of the thin lens…

A

the short side is in a medium with higher RI

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
7
Q

principle plane

A
  • refraction happens at principle plane
  • not really a flat surfaces
  • curved
How well did you know this?
1
Not at all
2
3
4
5
Perfectly
8
Q

principal point

A

where the principle plane intersects the optical axis

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
9
Q

Rule number 1 in thick lens

A

parallel then refracts at H’

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
10
Q

rule number 3 of thick lens

A

goes towards N, goes straight across to N’ and then comes out of lens at the same angle as it entered lens
ANGLE PRESERVATION
there is a virtual parallel displacement from N’ to N

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
11
Q

P=N

A

in a lot of thick lens systems, but not always

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
12
Q

actual rays

A

are subjected to two refractions, one per refracting surface

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
13
Q

conventional rays

A

change path only when encounter the prinicple planes (parallel and focal ray) or the nodal points (the nodal/radial ray)

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
14
Q

Ray propagation in a thick lens

A

rays do not pass through the cardinal points, however it is very useful to follow the rules of conventional rays to find the final path of any ray

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
15
Q

object distance in thick lens

A

measured from H

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
16
Q

image distance in thick lens

A

measured from H

17
Q

thick lens imaging relationship

A

1/xo + 1/Feff = 1/xi

18
Q

focal length measurement when rays propagating from right to left

A

measured from the principal plane H’

19
Q

focal length measurement when rays are propagating from left to right

A

measured from the principal plane H

20
Q

thin lens in contact optical power

A

Ptot=P1+P2

21
Q

optical power in a lens system: general

A

Ptot=P1+P2-(d/n)P1P2

22
Q

optical power in lenses separated by distance in air

A

Ptot=P1+P2-dP1P2

23
Q

d

A

the distance from the object space principal plane of the first lens (H’) to the image space principal plane (H’2) of second lens

24
Q

for calculation of the principle point locations as well as nodal point locations

A

use the object space principal plane of the first lens (H1), and for the image space, the image space principal plane (H’2) of the second lens

25
Q

the origin from which we measure gamma and gamma’ as well as thickness (d)

A

principal point P1 and the principal point P2 respectively.

these points now have the role of the respective V and V’ points

26
Q

imaging with two or more lenses

A
  1. we find the reduced system cardinal points
  2. locate the image by application of the thick ray diagrams
    OR
    employ the analytical expressions
27
Q

use of the intermediate object

A
  1. find the location and size of the primary image by applying summation of beam vergence and optical power (analytical solutions)
    OR
    locate the primary image with ray fiagrams apllicable for a single, thin lens (schematic solution)
  2. this is the intermediate object. The pricedure may be repeated for any additional optical element
28
Q

Use of intermediate object

A
  • if 2nd lens appears to block the construction rays, we ignore it for now
  • to find final image from intermediate object, we now ignore first lens and trace rays and find image location as normal