Imaginary and Complex Numbers Flashcards
If z = a + bj, what is the complex conjugate of z?
If z = a + jb
then the complex conjugate is:
ź (or z*) = a - jb
What is j1?
j1 = j
or
j = ‚/-1
What does j2 evaluate to?
j2 = -1
What does j3 evaluate to?
j3 = -j
What does j4 evaluate to?
j4 = j2•j2
= -1 • -1
= 1
What does √-1 x √-1 evaluate to?
√-1 x √-1 = j x j
= j2
= -1
What is the argument of a complex number?
give the formula
The argument of a complex number is the angle between the Re axis and the position vector of the complex number as depicted on an Argand diagram, such that -π < arg z ≤ π. This holds true as long as z ≠ 0.
Arg (z) = tan-1 Im(z) / Re(z), z ≠ 0
also
Arg (z) = sin-1 Im(z) / |z|, z ≠ 0
also
Arg (z) = cos-1 Re(z) / |z|, z ≠ 0
What is the modulus of an imaginary number?
Give formula
The Modulus of an imaginary number is the scalar length (magnitude) of the position vector of the imaginary number as depicted on an Argand diagram.
|z| = r = Sqrt (Re[z]2 + Im[z]2)
Write the complex number z = x + jy in polar form.
Given that |z| = r = Sqrt (Re[z]2 + Im[z]2)
and therefore Re(z) = r cosø
and also Im(z) = r sinø
z = r cosø + j r sinø
= r (cosø + j sinø)
Convert the Complex number z = r (cosø + j sinø) to Exponential form.
Given that (cosø + j sinø) = ejø
z = r (cosø + j sinø)
becomes
z = r(ejø)
=rejø
if and only if ø is in radians
Simplify j42
j42 = ( j4)10 ( j2)
= (1)10 (-1)
= -1
Simplify j12
j12 = ( j4)3
= (1)3
= 1
Simplify j11
j11 = ( j4)2 ( j3)
= (1)2 ( - j)
= - j
Simplify j - 8
j - 8 = ( j - 4)2
= (1)2
= 1
Simplify j-1
Start with j2 = -1
divide both sides by j
j = -1/j
= - j-1
multiply both sides by -1
j-1 = - j
Simplify j-2
j-2 = (j2)-1
= (-1)-1
= -1
Simplify j -3
j -3 = (j -2) j -1
= (-1) (-j)
= j
SImplify j -4
j -4 = (j -2)2
= (-1)2
= 1
Simplify j - 19
j - 19 = ( j-4)4 ( j - 3)
= (1)4 ( j)
= j
Simplify j - 30
j - 30 = ( j - 4)7 ( j - 2)
= (1) (-1)
= -1
Simplify j - 15
j - 15 = ( j - 4)3 ( j - 3)
= (1)3 ( j)
= j
Simplify j - 32
j - 32 = ( j - 4)8
= (1)8
= 1
Simplify j - 13
j - 13 = ( j - 4)3 ( j -1)
= (1)3 (- j)
= - j
Simplify j - 23
j - 23 = ( j - 4)5 ( j - 3)
= (1)5 ( j)
= j
In the complex number z = 3 + j5 what is the real part and what is the imaginary part? Use proper notation.
The parts of the complex number z = 3 + j5 are as follows:
Re(z) = 3 (the real part)
Im(z) = 5 (the imaginary part)
So, a complex number z = Re(z) + j Im(z)
Complete the following complex number addition:
(4 + j5) + (3 - j2)
(4 + j5) + (3 - j2) = 4 + j5 + 3 - j2
= (4 + 3) + j(5 - 2)
= 7 + j3
Complete the following complex number subtraction:
(4 + j7) - (2 - j5)
(4 + j7) - (2 - j5) = 4 + j7 - 2 + j5
= (4 - 2) + j(7 + 5)
= 2 + j12
Write down the general example of complex number addition.
z1 + z2 = (a + jb) + (c + jd)
= a + jb + c + jd
= (a + c) + j(b + d)
Complete the following complex number addition:
(5 + j7) + (3 - j4) - (6 - j3)
(5 + j7) + (3 - j4) - (6 - j3) = 5 +j7 + 3 - j4 - 6 + j3
= (5 + 3 - 6) + j(7 - 4 + 3)
= 2 + j6
Write down the general example of complex number multiplication.
z1 z2 = (a + jb)(c + jd)
= ac + jad + jbc + j2bd
= ac + jad + jbc - bd
= (ac - bd) + j(ad +bc)
Multiply the following complex numbers:
z1 = 3 + j4
z2 = 2 + j5
z1 z2 = (3 + j4)(2 + j5)
= 6 + j15 + j8 + j220
= 6 + j23 - 20
= -14 + j23
Multiply the following complex numbers:
z1 = (3 + j4)
z2 = (2 - j5)
z3 = (1 - j2)
z1 z2 z3 = (3 + j4)(2 - j5)(1 - j2)
= (3 + j4)(2 - j4 - j5 + j210)
= (3 + j4)(2 - j9 - 10)
= (3 + j4)(-8 - j9)
= -24 - j27 - j32 - j236
= -24 - j59 + 36
= 12 - j59
Multiply the complex numbers (5 + j8)(5 - j8)
Note: complex conjugates
(5 + j8)(5 - j8) = 25 + j40 - j40 - j264
= 25 - ( -64)
= 25 + 64
= 89
Under what circumstances is the complex number z = a + jb purely real?
The complex number z = a + jb is purely real when b = 0
Under what circumstances is the complex number z = a + jb purely imaginary?
The complex number z = a + jb is purely imaginary when a = 0
How do you divide one Complex number (z1 = a + jb) by another (z2 = c + jd)?
z1/z2 = (a + jb) / (c + jd)
to simplify we can make the denominator entirely real using the conjugate complex number z2*
z1z2* / z2z2* = (a + jb)(c - jd) / (c + jd)(c - jd)
= ((ac + bd) + j(bc - ad)) / c2 + d2
What is an Argand Diagram?
An Argand Diagram is a way of visually representing complex numbers.
In an Argand Diagram the complex number is plotted on a pair of co-ordinate axes, where the horizontal axis represents Real numbers and the vertical axis represents Imaginary numbers.

Given the modulus (r) and the argument (ø) how can you work out Re(z) and Im(z)?
Given r and ø we can determine Re(z) as follows:
Re(z) = rcos(ø)
Similarly, we can determine Im(z) as follows:
Im(z) = rsin(ø)
How would you multiply the following complex numbers:
z1 = r (cos a + j sin a)
z2 = s (cos b + j sin b)
hint: use exponential form
z1 = r (cos a + j sin a)
= reja
z2 = s (cos b + j sin b)
= sejb
z1z2 = reja • sejb
= rs(eja • ejb)
= rs(eja+jb)
=rsej(a+b)
Note: rsej(a+b) = rs(cos(a+b) + jsin(a+b))
What does the polar/exponential formtell us aboutcomplex number multiplication?
hint: magnitudes and angles
The polar form tells us that when we multiply complex numbers we:
- multiply the magnitudes
and
-
add the angles
e. g.
r (cos(a) + jsin(a)) • s (cos(b) + jsin(b))
= rs (cos(a + b) + jsin(a +b))
Divide the complex number
z1 = 7(cos (7π/6) + j sin (7π/6))
by
z2 = cos (7π/4) + j sin (7π/6)
hint: exp
z1 = 7(cos (7π/6) + j sin (7π/6))
= 7ej(7π/6)
and
z2 = cos (7π/4) + j sin (7π/6)
= ej(7π/4)
therefore
z1 / z2 = 7ej(7π/6) / ej(7π/4)
= 7ej(7π/6) • e- j(7π/4)
= 7ej(7π/6 - 7π/4)
= 7e- j7π/12
z3 = 7(cos (7π/12) - jsin (7π/12))
How would you divide the following complex numbers:
z1 = r (cos a + j sin a)
by
z2 = s (cos b + j sin b)
hint: use exponential form
z1 = r (cos a + j sin a)
= reja
and
z2 = s (cos b + j sin b)
= sejb
therefore
z1 / z2 = reja / sejb
= (r/s)eja • e- jb
= (r/s)ej(a - b)
= r/s (cos (a-b) + jsin (a-b))
What does the polar/exponential form tell us about complex number division?
hint: magnitudes and angles
The polar form tells us that when we divide complex numbers we:
- divide the magnitudes
and
-
subtract the angles
e. g.
r (cos(a) + jsin(a)) / s (cos(b) + jsin(b))
= r/s (cos(a - b) + jsin(a -b))
Does (z1z2)* = z1*z2* ?
Yes it does.
let z1 = a + jb and z2 = c + jd
z1z2 = (a + jb)(c + jd)
= (ac - bd) + j(ad + bc)
Therefore:
(z1z2)* = (ac - bd) - j(ad + bc)
Given that z1* = a - jb and z2* = c - jd
it can be seen that:
z1*z2* = (a - jb)(c - jd)
= (ac - bd) + j(-ad -bc)
= (ac - bd) - j(ad + bc)
Thus:
(z1z2)* = z1*z2*
What can we say about zz*?
hint: it something to do with mod z
Given that:
z = a + jb
and
z* = a - jb
we can see that:
zz* = (a + jb)(a - jb)
= a2 + b2
Given that |z| = √(a2 + b2)
it can be seen that:
zz* = |z|2