Imaginary and Complex Numbers Flashcards

1
Q

If z = a + bj, what is the complex conjugate of z?

A

If z = a + jb

then the complex conjugate is:

ź (or z*) = a - jb

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2
Q

What is j1?

A

j1 = j

or

j = ‚/-1

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3
Q

What does j2 evaluate to?

A

j2 = -1

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4
Q

What does j3 evaluate to?

A

j3 = -j

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5
Q

What does j4 evaluate to?

A

j4 = j2•j2

= -1 • -1

= 1

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6
Q

What does √-1 x √-1 evaluate to?

A

√-1 x √-1 = j x j

= j2

= -1

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7
Q

What is the argument of a complex number?

give the formula

A

The argument of a complex number is the angle between the Re axis and the position vector of the complex number as depicted on an Argand diagram, such that -π < arg z ≤ π. This holds true as long as z ≠ 0.

Arg (z) = tan-1 Im(z) / Re(z), z ≠ 0

also

Arg (z) = sin-1 Im(z) / |z|, z ≠ 0

also

Arg (z) = cos-1 Re(z) / |z|, z ≠ 0

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8
Q

What is the modulus of an imaginary number?

Give formula

A

The Modulus of an imaginary number is the scalar length (magnitude) of the position vector of the imaginary number as depicted on an Argand diagram.

|z| = r = Sqrt (Re[z]2 + Im[z]2)

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9
Q

Write the complex number z = x + jy in polar form.

A

Given that |z| = r = Sqrt (Re[z]2 + Im[z]2)

and therefore Re(z) = r cosø

and also Im(z) = r sinø

z = r cosø + j r sinø

= r (cosø + j sinø)

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10
Q

Convert the Complex number z = r (cosø + j sinø) to Exponential form.

A

Given that (cosø + j sinø) = e

z = r (cosø + j sinø)

becomes

z = r(e)

=re

if and only if ø is in radians

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11
Q

Simplify j42

A

j42 = ( j4)10 ( j2)

= (1)10 (-1)

= -1

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12
Q

Simplify j12

A

j12 = ( j4)3

= (1)3

= 1

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13
Q

Simplify j11

A

j11 = ( j4)2 ( j3)

= (1)2 ( - j)

= - j

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14
Q

Simplify j - 8

A

j - 8 = ( j - 4)2

= (1)2

= 1

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15
Q

Simplify j-1

A

Start with j2 = -1

divide both sides by j

j = -1/j

= - j-1

multiply both sides by -1

j-1 = - j

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16
Q

Simplify j-2

A

j-2 = (j2)-1

= (-1)-1

= -1

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17
Q

Simplify j -3

A

j -3 = (j -2) j -1

= (-1) (-j)

= j

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18
Q

SImplify j -4

A

j -4 = (j -2)2

= (-1)2

= 1

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19
Q

Simplify j - 19

A

j - 19 = ( j-4)4 ( j - 3)

= (1)4 ( j)

= j

20
Q

Simplify j - 30

A

j - 30 = ( j - 4)7 ( j - 2)

= (1) (-1)

= -1

21
Q

Simplify j - 15

A

j - 15 = ( j - 4)3 ( j - 3)

= (1)3 ( j)

= j

22
Q

Simplify j - 32

A

j - 32 = ( j - 4)8

= (1)8

= 1

23
Q

Simplify j - 13

A

j - 13 = ( j - 4)3 ( j -1)

= (1)3 (- j)

= - j

24
Q

Simplify j - 23

A

j - 23 = ( j - 4)5 ( j - 3)

= (1)5 ( j)

= j

25
Q

In the complex number z = 3 + j5 what is the real part and what is the imaginary part? Use proper notation.

A

The parts of the complex number z = 3 + j5 are as follows:

Re(z) = 3 (the real part)

Im(z) = 5 (the imaginary part)

So, a complex number z = Re(z) + j Im(z)

26
Q

Complete the following complex number addition:

(4 + j5) + (3 - j2)

A

(4 + j5) + (3 - j2) = 4 + j5 + 3 - j2

= (4 + 3) + j(5 - 2)

= 7 + j3

27
Q

Complete the following complex number subtraction:

(4 + j7) - (2 - j5)

A

(4 + j7) - (2 - j5) = 4 + j7 - 2 + j5

= (4 - 2) + j(7 + 5)

= 2 + j12

28
Q

Write down the general example of complex number addition.

A

z1 + z2 = (a + jb) + (c + jd)

= a + jb + c + jd

= (a + c) + j(b + d)

29
Q

Complete the following complex number addition:

(5 + j7) + (3 - j4) - (6 - j3)

A

(5 + j7) + (3 - j4) - (6 - j3) = 5 +j7 + 3 - j4 - 6 + j3

= (5 + 3 - 6) + j(7 - 4 + 3)

= 2 + j6

30
Q

Write down the general example of complex number multiplication.

A

z1 z2 = (a + jb)(c + jd)

= ac + jad + jbc + j2bd

= ac + jad + jbc - bd

= (ac - bd) + j(ad +bc)

31
Q

Multiply the following complex numbers:

z1 = 3 + j4

z2 = 2 + j5

A

z1 z2 = (3 + j4)(2 + j5)

= 6 + j15 + j8 + j220

= 6 + j23 - 20

= -14 + j23

32
Q

Multiply the following complex numbers:

z1 = (3 + j4)

z2 = (2 - j5)

z3 = (1 - j2)

A

z1 z2 z3 = (3 + j4)(2 - j5)(1 - j2)

= (3 + j4)(2 - j4 - j5 + j210)

= (3 + j4)(2 - j9 - 10)

= (3 + j4)(-8 - j9)

= -24 - j27 - j32 - j236

= -24 - j59 + 36

= 12 - j59

33
Q

Multiply the complex numbers (5 + j8)(5 - j8)

Note: complex conjugates

A

(5 + j8)(5 - j8) = 25 + j40 - j40 - j264

= 25 - ( -64)

= 25 + 64

= 89

34
Q

Under what circumstances is the complex number z = a + jb purely real?

A

The complex number z = a + jb is purely real when b = 0

35
Q

Under what circumstances is the complex number z = a + jb purely imaginary?

A

The complex number z = a + jb is purely imaginary when a = 0

36
Q

How do you divide one Complex number (z1 = a + jb) by another (z2 = c + jd)?

A

z1/z2 = (a + jb) / (c + jd)

to simplify we can make the denominator entirely real using the conjugate complex number z2*

z1z2* / z2z2* = (a + jb)(c - jd) / (c + jd)(c - jd)

= ((ac + bd) + j(bc - ad)) / c2 + d2

37
Q

What is an Argand Diagram?

A

An Argand Diagram is a way of visually representing complex numbers.

In an Argand Diagram the complex number is plotted on a pair of co-ordinate axes, where the horizontal axis represents Real numbers and the vertical axis represents Imaginary numbers.

38
Q

Given the modulus (r) and the argument (ø) how can you work out Re(z) and Im(z)?

A

Given r and ø we can determine Re(z) as follows:

Re(z) = rcos(ø)

Similarly, we can determine Im(z) as follows:

Im(z) = rsin(ø)

39
Q

How would you multiply the following complex numbers:

z1 = r (cos a + j sin a)

z2 = s (cos b + j sin b)

hint: use exponential form

A

z1 = r (cos a + j sin a)

= reja

z2 = s (cos b + j sin b)

= sejb

z1z2 = reja • sejb

= rs(eja • ejb)

= rs(eja+jb)

=rsej(a+b)

Note: rsej(a+b) = rs(cos(a+b) + jsin(a+b))

40
Q

What does the polar/exponential formtell us aboutcomplex number multiplication?

hint: magnitudes and angles

A

The polar form tells us that when we multiply complex numbers we:

  • multiply the magnitudes

and

  • add the angles
    e. g.

r (cos(a) + jsin(a)) • s (cos(b) + jsin(b))

= rs (cos(a + b) + jsin(a +b))

41
Q

Divide the complex number

z1 = 7(cos (7π/6) + j sin (7π/6))

by

z2 = cos (7π/4) + j sin (7π/6)

hint: exp

A

z1 = 7(cos (7π/6) + j sin (7π/6))

= 7ej(7π/6)

and

z2 = cos (7π/4) + j sin (7π/6)

= ej(7π/4)

therefore

z1 / z2 = 7ej(7π/6) / ej(7π/4)

= 7ej(7π/6) • e- j(7π/4)

= 7ej(7π/6 - 7π/4)

= 7e- j7π/12

z3 = 7(cos (7π/12) - jsin (7π/12))

42
Q

How would you divide the following complex numbers:

z1 = r (cos a + j sin a)

by

z2 = s (cos b + j sin b)

hint: use exponential form

A

z1 = r (cos a + j sin a)

= reja

and

z2 = s (cos b + j sin b)

= sejb

therefore

z1 / z2 = reja / sejb

= (r/s)eja • e- jb

= (r/s)ej(a - b)

= r/s (cos (a-b) + jsin (a-b))

43
Q

What does the polar/exponential form tell us about complex number division?

hint: magnitudes and angles

A

The polar form tells us that when we divide complex numbers we:

  • divide the magnitudes

and

  • subtract the angles
    e. g.

r (cos(a) + jsin(a)) / s (cos(b) + jsin(b))

= r/s (cos(a - b) + jsin(a -b))

44
Q

Does (z1z2)* = z1*z2* ?

A

Yes it does.

let z1 = a + jb and z2 = c + jd

z1z2 = (a + jb)(c + jd)

= (ac - bd) + j(ad + bc)

Therefore:

(z1z2)* = (ac - bd) - j(ad + bc)

Given that z1* = a - jb and z2* = c - jd

it can be seen that:

z1*z2* = (a - jb)(c - jd)

= (ac - bd) + j(-ad -bc)

= (ac - bd) - j(ad + bc)

Thus:

(z1z2)* = z1*z2*

45
Q

What can we say about zz*?

hint: it something to do with mod z

A

Given that:

z = a + jb

and

z* = a - jb

we can see that:

zz* = (a + jb)(a - jb)

= a2 + b2

Given that |z| = √(a2 + b2)

it can be seen that:

zz* = |z|2