Identities/Formulae Flashcards

1
Q

cos^2x + sin^2x

A

= 1

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2
Q

sin2x

A

= 2sinxcosx

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3
Q

cos2x

A

= cos^2x - sin^2x / 2cos^2x -1 / 1 - 2sin^2x

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4
Q

sec^2x

A

= 1 + tan^2x

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5
Q

cosec^2x

A

= 1 + cot^2x

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6
Q

sin^2x

A

= 0.5 - 0.5cos2x

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7
Q

cos^2x

A

= 0.5 + 0.5cos2x

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8
Q

if det(M) = 0

A

M is Singular, ad - bc = 0

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9
Q

How many inverses do Singular Matrices have?

A

No inverses as they have no determinant so 1 / det(M) is undefined so there is no working matrix.

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10
Q

sinhx

A

= 0.5(e^x - e^-x)

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11
Q

coshx

A

= 0.5(e^x + e^-x)

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12
Q

arsinhx

A

= ln(x + root(x^2 +1))

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13
Q

arcoshx

A

= ln(x + root(x^2 -1))

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14
Q

artanhx

A

= 0.5ln((1 + x)/ (1 - x))

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15
Q

How do Hyperbolic identites differ from standard?

A

Wherever a hyperbolic function has a product of two sines, the product of the hyperbolic sines must be negated.

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16
Q

cosh^2x - sinh^2x

A

= 1

17
Q

1 - tanh^2x

A

= sech^2x

18
Q

coth^2x - 1

A

= cosech^2x

19
Q

z^n

A

r^n(cosnx + isinnx)

20
Q

Volume of Rev with a Parametric Equation

A

Pi (int (y^2 (dx/dt) dt))

21
Q

Perpendicular Tangent

A

x = rcosx

22
Q

Parallel Tangent

A

y = rsinx

23
Q

(z + z^-1)

A

2cosx

24
Q

(z^n + z^-n)

A

2cosnx

25
Q

(z - z^-1)

A

2isinx

26
Q

(z^n - z^-n)

A

2isinnx

27
Q

How to solve a Partial Fraction with a Quadratic Factor in the denominator?

A

This cannot be solved normally, there will not be a quadratic term on the RHS of the equation so therefore one of the terms will always be wrong. So therefore in order to solve this, we must include a term one below the term in the denominator, which for a quadratic, is a linear term such as Bx + C. If this was a cubic on the denominator then we would have to include a quadratic term on the numerator etc. And then this can be solved normally.

For example:
(5x - 7) / (x +1) (x^2 + 1) = A / (x +1) + (Bx + C) / (x^2 + 1)

28
Q

How to find the inverse of a 3x3 matrix?

A

Form the new matrix by finding the determinant for each term within the matrix. Then apply the new signs to each of the terms, pluses in a diagonal shape, and then minuses elsewhere. Then take the transpose, switching each term in diagonal lines from right to left. Finally, find the original determinant of the matrix and place 1 / det(M) outside the inverse matrix you just formed.