Hydrocarbons Flashcards
What is homolytic fission?
The breaking of a covalent bond with one of the bonded electrons going to each atom, forming two radicals.
What is heterolytic fission?
The breaking of a covalent bond with both of the bonded electrons going to one of the atoms, forming a cation and an anion
What is an addition reaction?
A reaction in which a reactant is added to an unsaturated molecule to make a saturated molecule
What is a free radical substitution reaction?
one or more hydrogen atoms is removed from a saturated hydrocarbon and replaced by another atom
What is an elimination reaction?
The removal of a small molecule from a saturated molecule to make an unsaturated molecule
What is an electrophile?
An electron pair acceptor
(An atom (or group of atoms) that is attracted to an electron-rich centre or atom, where it accepts a pair of electrons to form a new covalent bond)
What is a nucleophile?
AN ELECTRON PAIR DONOR
An atom (or group of atoms) that is attracted to an electron- deficient centre or atom, where it donates a pair of electrons to form a new covalent bond.
Describe the bonding in alkanes
Covalent bonds between C-H and C-C formed by the overlap of orbitals creating sigma bonds consisting of one electron from each bonding atom.
Carbon always forms 4 bonds with surrounding atoms while H only forms 1
Describe the shape of alkanes (bond angle)
Each carbon is surrounded by 4 electron pairs which repel each other to form bond angles of 109.5°. Long chain alkanes do not have fixed shapes, they could be zigzagged or they could form a U shape.
What is the effect of chain length on boiling point of alkanes
As the chain length increase, more London forces are present between molecules as there is more surface area contact. The more London forces require a larger amount of energy to overcome therefore the boiling point is higher on longer chained alkanes.
What is the effect of branching on boiling point of alkanes?
Alkanes with more branches have less surface area contact between each other meaning that there are less London forces present, therefore requiring less energy to overcome, meaning alkanes with more branching have lower melting points.
Why is UV light required when reacting halogens with alkanes?
When reacting a halogen with an Alkane to form a haloalkane, UV light must be present as it provides the molecules with sufficient activation energy for the reaction to take place.
Describe the initiation stage of bromination
The halogen (Br2) is broken down into radicals with free electrons (Br• + Br•)
Describe the propagation stage of bromination
Their are two stages to propagation:
Stage 1- Br• is used to form a •CH3 radical and a HBr molecule
Stage 2- a Br2 molecule and the •CH3 form CH3Br and Br•
The cycle then repeats, the Br• used in stage 1 is formed in stage 2
Limitations of radical substitution
- Further substitution (CH3Br, CH2Br2, CHBr3 or CBr4)- Substitution on different points on the chain (isomers can be formed)