Human Genetics Flashcards

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1
Q

Red-green color blindness is X-linked in humans. If a male is red-green color blind, and both parents have normal color vision, which of the male’s grandparents is most likely to be red-green color blind?

A. maternal grandmother
B. maternal grandfather
C. paternal grandmother
D. paternal grandfather
E. either grandfather is equally likely

A

B. maternal grandfather

In this problem, an X-linked recessive allele is passed from an affected male, to a daughter who is a heterozygous carrier, and subsequently to an affected grandson.

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2
Q

When RFLP analysis is used to search for a human gene, the strategy is to first locate?

A. a known gene on the same chromosome
B. an homozygous individual with a simple RFLP pattern
C. a DNA sequence anywhere on the same chromosome
D. any DNA marker co-inherited with the genetic trait of interest
E. an exon of the disease gene

A

D. any DNA marker co-inherited with the genetic trait of interest

Genes and anonymous DNA markers that are located near each other on the same chromosome are “linked,” and do not segregate independently during meiosis.

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3
Q

Which of the following is not one of the objectives of the Human Genome Project?

A. Create a detailed genetic map of every human chromosome, with an average of 2-5% recombination frequency between markers.
B. Obtain a detailed physical map of every human chromosome, based on overlapping recombinant DNA molecules cloned as yeast artificial chromosomes.
C. Clone human beings.
D. Determine the sequence of all expressed human genes by cDNA cloning and sequencing.
E. Determine the complete DNA sequence of each human chromosome.

A

C. Clone human beings

Cloning humans, a horrifying thought just a few months ago, is now being debated very seriously.

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4
Q

A couple has a female child with Tay Sachs disease, and three unaffected children. Neither parent nor any of the four biological grandparents of the affected child has had this disease. The most likely genetic explanation is that Tay Sachs disease is inherited as a(n) ______________ disease.

A. autosomal dominant
B. autosomal recessive
C. sex-linked recessive
D. sex-linked dominant
E. cannot make a reasonable guess from this information

A

B. autosomal recessive

The disease is recessive because both parents are unaffected, and autosomal because a female child is affected but her father is not.

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5
Q

A human geneticist determined the pedigree shown in the diagram with filled symbols showing the affected individuals. How is this pattern of inheritance described?

A. autosomal dominant
B. autosomal recessive
C. sex-linked recessive
D. sex-linked dominant
E. none of these

A

A. autosomal dominant

A genetic trait that is passed from generation to generation to generation, from both fathers to daughters and mothers to daughters, is typically autosomal dominant.

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6
Q

Diagnosis of chromosome aneuploidy of unborn children is normally done by a combination of amniocentesis, cell culture, and _______________.

A. enzyme assay.
B. RFLP analysis.
C. pedigree analysis.
D. karyotyping.
E. somatic cell fusion.

A

D. karyotyping

A karyotype is used to display the number, types and appearance of chromosomes. Analysis of chromosomes of an unborn child can be carried out with cells obtained from the amniotic fluid within the mother’s uterus.

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7
Q

Which statement about Down’s syndrome is false?

A. The frequency increases dramatically in mothers over the age of 40.
B. The cause is a non-disjunction when chromosomes do not separate during the first meiotic division.
C. Affected individuals have an extra autosome.
D. The long time lag between onset of meiosis in ovarian tissue (during fetal development) and its completion (at ovulation) is most likely the reason for increased incidence in older mothers.
E. None, all statements are true.

A

E. None, all statements are true.

Down syndrome is also known as trisomy 21.

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8
Q

A human male carrying an allele for a trait on the X chromosome is:

A. heterozygous
B. homozygous
C. hemizygous
D. monozygous
E. holozygous

A

C. hemizygous

Males have a single copy of the X-chromosome.

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9
Q

Why would you predict that half of the human babies born will be males and half will be females?

A. Because of the segregation of the X and Y chromosomes during male meiosis.
B. Because of the segregation of the X chromosomes during female meiosis.
C. Because all eggs contain an X chromosome.
D. Because, on average, one-half of all eggs produce females.
E. Because of the formation of the Barr body early during embryonic development.

A

A. Because of the segregation of the X and Y chromosomes during male meiosis.

Sex is determined by the sex chromosome in the sperm that fertilizes the female egg. Half of the sperm have an X-chromosome and half have a Y-chromosome.

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10
Q

A man who had purple ears came to the attention of a human geneticist. The human geneticist did a pedigree analysis and made the following observations:

In this family, purple ears proved to be an inherited trait due to a single genetic locus. The man’s mother and one sister also had purple ears, but his father, his brother, and two other sisters had normal ears. The man and his normal-eared wife had seven children, including four boys and three girls. Two girls and two boys had purple ears. The purple-ear trait is most probably:

A. autosomal, dominant
B. autosomal, recessive
C. sex-linked, dominant
D. sex-linked, recessive
E. cannot be determined from this information

A

A. autosomal, dominant

A genetic trait that is passed from generation to generation to generation, from both fathers to daughters and mothers to daughters, is typically autosomal dominant.

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11
Q

Klinefelter’s syndrome (XXY) is an example of chromosomal aneuploidy that can be readily diagnosed by:

A. Behavioral analysis
B. Somatic cell genetics
C. Karyotyping
D. Biochemical analysis
E. Pedigree analysis

A

C. Karyotyping

A karyotype is used to display the number, types and appearance of chromosomes. An extra X chromosome in a Klinefelter’s individual could be readily diagnosed by karyotyping.

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12
Q

By examining a number of somatic-cell hybrid lines for enzyme activities and their human chromosome constitution, scientists can determine

A. on which human chromosome the gene for a particular enzyme is located
B. the number of genes for enzymes in the human genome
C. the number of chromosomes in the human genome
D. the number of human chromosomes in each cell
E. Scientists cannot determine any of these things

A

A. on which human chromosome the gene for a particular enzyme is located

It is possible to correlate enzyme activity with a specific chromosome in a somatic-cell hybrid

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13
Q

Which is NOT a common method used in human genetic analysis?

A. pedigree analysis
B. karyotyping
C. RFLP analysis
D. test cross
E. somatic cell genetics

A

D. test cross

Deliberate crosses are not used in studying human inheritance.

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14
Q

A Barr body is:

A. the cause of Down’s syndrome
B. an amplified gene
C. a polytene chromosome
D. a ribonucleoprotein particle
E. an inactivated X chromosome

A

E. an inactivated X chromosome

One of the two X chromosomes in female somatic cells is visualized as a densely staining body within the nucleus known as a “Barr body.”

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15
Q

Which of the following is a useful marker for genetic or physical mapping of human chromosomes? (More than one answer could be correct)

A. RFLPs, “restriction fragment length polymorphisms”
B. ESTs, “expressed sequence tags”
C. STRPs, “short tandem repeat polymorphisms”
D. STSs, “sequence tagged sites”
E. all of the above

A

E. all of the above

RFLPs are genetic markers detected by Southern hybridization. ESTs, STRPs, and STSs are markers detected by PCR.

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16
Q

Which of the following describes a type of polymorphism that occurs within the gene that causes Huntington’s disease?

A. RFLPs, “restriction fragment length polymorphisms”
B. ESTs, “expressed sequence tags”
C. STRPs, “short tandem repeat polymorphisms”
D. STSs, “sequence tagged sites”
E. None of the above

A

C. STRPs, “short tandem repeat polymorphisms”

A short sequence (CAG) is repeated many times in tandem. The number of repeats varies between the normal and disease-causing alleles of the gene.

17
Q

Which of the following type(s) of polymorphism are commonly detected by using the polymerase chain reaction (PCR) and specific oligonucleotide primers?

A. RFLPs, “restriction fragment length polymorphisms”
B. ESTs, “expressed sequence tags”
C. STRPs, “short tandem repeat polymorphisms”
D. STSs, “sequence tagged sites”
E. B, C, and D are correct

A

E. B, C, and D are correct

ESTs, STRPs, and STSs are all normally analyzed using the Polymerase Chain Reaction (PCR)

18
Q

Which of the following is a marker for regions of the DNA expressed as mRNA transcripts, and characterized by cDNA cloning?

A. RFLPs, “restriction fragment length polymorphisms”
B. ESTs, “expressed sequence tags”
C. STRPs, “short tandem repeat polymorphisms”
D. STSs, “sequence tagged sites”
E. all of the above

A

ESTs, “expressed sequence tags”

The term “EST” is now used to describe the DNA sequence of a short fragment of a cDNA copy of mRNA. mRNAs are expressed sequences.

18
Q

Which of the following is a marker for regions of the DNA expressed as mRNA transcripts, and characterized by cDNA cloning?

A. RFLPs, “restriction fragment length polymorphisms”
B. ESTs, “expressed sequence tags”
C. STRPs, “short tandem repeat polymorphisms”
D. STSs, “sequence tagged sites”
E. all of the above

A

ESTs, “expressed sequence tags”

The term “EST” is now used to describe the DNA sequence of a short fragment of a cDNA copy of mRNA. mRNAs are expressed sequences.

19
Q

First Message from a concerned grandmother:

I am wondering how to find out blood type of my grandson…my daughter is A+..father is in question…she is stressed to the max on the father of this baby boy.
What is the most common blood type and the most common donor and common receiver?

Answer to First Message by Professor Hallick:
Blood type analysis can occasionally rule out a potential father (i.e. if the mother is type A and the child is type O, the father could not be type AB, but could be type A, B, or O), but is not a method that can be used to establish paternity.
If the paternity of your grandson needs to be established for legal reasons, such as establishing responsibility for child support, a DNA test would be the accepted method. There are commercial laboratories that will do the test for a fee (several hundred dollars). Blood samples would be required from the mother, child, and any alleged fathers.
Second Message from grandmother:

Thanks so much for your prompt reply. Here is the scenario….paternity isn’t going to be established…it is going to lay…for lack of a better expression. My daughter is type A, my grandson is type B+, we do not know the types of the two gentlemen in question…my question is what are the types that the fathers would have to be in order for him to be a B+?
What is the correct answer to the grandmother’s question, “What are the types that the fathers would have to be in order for him (grandson) to be a B+?”

A. B or O
B. A, B, AB or O
C. AB or B
D. A or B
E. A, B, or AB

A

C. AB or B

The child must be genotype BO. The mother is the source of the O-allele and the biological father is the source of the B-allele.

20
Q

“Could a man with type B blood and a woman with type AB produce a child with type O blood?”

A. Possible
B. Not possible

A

B. Not possible

Dr. Hallick’s reply:
The children of a man with type B blood and a woman with type AB blood could be type A, type B, and type AB, but not type O.

21
Q

What if the mother is type O+ and the father is A-? What would the offspring’s blood type be? –Mark
The offspring could be:
A. A+, or O+
B. A-, or O-
C. A+, A-, O+, or O-
D. A+, or O-

A

C. A+, A-, O+, or O-

22
Q

If the mother of a child is blood type O+ and the child is A-, what blood type would the father be? Does the Rh factor of the child being - mean that one of the parents has to be negative? Both of my parents are Rh - all of us siblings are Rh- as well. Could two Rh- parents give birth to a Rh+ child? and versi versa? Thanks for all your help. –MaryEllen

The father could be:
A. A+, A-, or O-
B. A+, A -, AB+, or AB-
C. B+, B-, or O-

A

B. A+, A -, AB+, or AB-

Dr. Hallick’s reply:
The father could be type A or type AB. The types that can be ruled out for the father are type O and type B. The father must be the source of the A allele of the child.
The Rh factor information doesn’t discriminate potential fathers of the child. Even though the child is Rh-, it is not necessary that either parent be Rh-. The father of the child could be either Rh+ (heterozygous with one Rh+ allele and one Rh- allele) or Rh- (homozygous with two recessive Rh- alleles).

When the mother is Rh- and the father is Rh+ (heterozygous with one Rh+ allele and one Rh- allele), there is a 50% probability for an Rh+ child and a 50% probability for an Rh- child.
When the mother is Rh- and the father is Rh-, as in the case of your own family, then all children (all of your siblings) will be Rh-.

23
Q

what blood type the father of my son could have since my son and I are both type A+. Also, my brother is type 0 and my mom is A+.

A. A, AB, B, or O
B. Either A or B
C. Either A or O

A

A, AB, B, or O