Homework Problems - What to do? Flashcards
A chemical reaction occurs in an aqueous in a flask. What is the system and the surroundings?
The system is the reaction inside the flask
surroundings is everything outside the flask
Convert between energy units
231 cal to J
2.88 x 10^4 J to kcal
1 cal = 4.184 joules
231 cal x (4.184J) = 967J
1 Cal = 1kcal
2.88x10^4 J x 1/4.184 x 1kcal/1000 = 6.88kcal
A system absorbs 196kJ of heat and the surroundings do 117kJ of work on the system. What is the change in internal energy of the system?
we know q = 196kJ
w = 117Kj
Find E = internal energy of system
use equation Esystem = q + w
(196kJ) + (117kJ) = 313kJ
How much heat is required to warm 1.50 kg of sand from 25 degrees Celsius to 100 degrees Celsius? Cs for sand = 0.84
Given
mass = 1.50kg ==> (must be in grams bc of Cs)
Cs = 0.84 J/gC
100.0 - 25.0 = 75.0 = deltaTemp
Equation q = m x Cs x deltaT
(1.50kg x 1000) x (0.84 J/gC) x (75C) = 94500 J of heat required
How much work is required to expand the volume of a pump from 0.0L to 2.5L against an internal pressure of 1.1 atm?
Given
- 5L - 0.0L = 2.5L = deltaVolume
- 1 atm = pressure
Equation
The gas does work and the volume increases (deltaV > 0) so the work done is negative
w = -P x deltaV
-(1.1 atm) x (2.5L) = -2.75 L x atm
negative liters-atmopsheres makes no sense so make it positive
need final units to be in joules
-2.75 L x atm x (