Higher Course Flashcards

1
Q

Collinearity

A

Find gradient of 2 points
Use one of those points and the other one not used
If same then collinear

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2
Q

Parallel Gradients

A

Find gradient of given equation

Sub into straight line using given points

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3
Q

Perpendicular Gradient

A

Find gradient
Find perpendicular gradient
Sub into straight line equation

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4
Q

Median

A

Find midpoint
Find gradient through midpoint and other point
Sub into straight line

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5
Q

Perpendicular Bisector

A

Find midpoint
Find gradient with points used to find midpoint
Find perpendicular gradient
Sub straight line equation with gradient and midpoint

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6
Q

Altitude

A

Find gradient
Find perpendicular gradient
Sub into straight line equation

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7
Q

Polynomials

A

Use synthetic division to find if a factor

Then factorise if asked

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8
Q

Polynomials with unknown coefficients

A

Use synthetic division and simplfy to find the coefficients

if 2 unknown coefficients then use simultaneous equations

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9
Q

Determining the equation from a graph

A
Find roots (3) 
Sub roots into K(x-a)(x-b)(x-c) to find k (x=0) 
Use K in f(x)=K(x-a)(x-b)(x-c) and multiply out
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10
Q

Differentiation

A

Multiply by power

minus 1 off the power

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11
Q

Rate of Change

A

Differentiate

Sub in the number asked

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12
Q

Equation of a tangent

A

Find y to get coordinates
Find gradients by differentiation
Sub in for straight line equation

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13
Q

Stationary Points

A

Find f’(x)
Find f’(x) =0 to get x
Sub x into original equation
Use nature table to determine the nature of roots

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14
Q

Curve Sketching

A

Find y intercept when x=0
Find x intercept when y=0
Find stationary points
Sketch a graph using x and y intercept and results of nature table

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15
Q

Optimisation

A

Find area using A=LxB

Find S.P’s of original equation
Find x
Use nature table to get value asked
Sub back into length or breadth of the room

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16
Q

Trig Exact Values

SIN

A
0° = 0 
30° = 1/2
45° = 1/√2
60° = √3/2
17
Q

Trig Exact Values

COS

A
0° = 1 
30° = √3/2 
45°= 1\√2
60° = 1/2
18
Q

Trig Exact Values

TAN

A
0° = 0 
30° = 1/√3
45°= 1 
60° = √3
19
Q

Radians Values

A
360° = 2π
180° = π
90° = π/2 
60° = π/3 
45° = π/4 
30° = π/6
20
Q

Inverse Functions

A

Replace f(x) with y
Change the subject to x
Replace y with x
Replace x with f’(x)

21
Q

Quadratic Inequations

A

Factorise to find roots
Draw a sketch
If bounded is between the 2 roots
If unbounded 2 separate values

22
Q

The discriminat

A

b²-4ac
If below 0 - no real roots
If equal to 0 - 2 real and distinct roots
If over 0 - roots are real and distinct

23
Q

Find intersection of a line and curve

A
Simply equation 
Use discriminate 
If 0 - then a tangent 
If less than 0 - no intersection 
If over 0 - 2 points of intersection
24
Q

Find intersection of a line and curve with 2 points

A

Simply equation
Factorise to find 2 x points
Sub into original equation
Find coordinates of 2 points of intersection

25
Distance Formula
√(x2-x1)²+(y2-y1)²
26
Circle Equation
(x-a)²+(x-b)²=r² (a,b) is the centre r is the radius
27
General Formula of a Cricle
x²+y²+2gx+2fy+c=0 centre = (-g,-f) Radius -√g²+f²-c
28
Coordinates and the Circle
Sub coordinates into equation | Determine LHS and compare to RHS
29
Nature of intersection of line and curve
Sub equation of line into circle equation Simplify and rearrange to 0 Use discriminate to determine nature
30
Find the points of intersection of line and circle
Sub equation of line into circle equation Simplify and rearrange to 0 Factorise for 2 x points Sub into line equation to get coordinates
31
Equation of a tangent to a curve
Find the centre to get the points Use points to find the gradient Sub into line equation
32
The intersection of 2 circles
Find the radius and circle of both equations Find the distance between the centres Add the radius compare centre distances and add the radius to determine the intersection
33
The intersection of 2 points - Intersections
r1+r2 less than AB - 2 points of intersection r2-r1=AB - one circle is inside the other r1+r2 more than AB 2 points of intersection
34
Integration
Add one to the power | Divide by new power
35
Definite Integration
f(b) - F(a) | Integrate by subbing in (b) then sub in (a) into x
36
Area under a curve
Integrate If negative the under x-axis Use units²