Heat Exchangers and Condensers Flashcards
The rate of heat transfer between two liquids in a heat exchanger will increase if the… (Assume
single-phase conditions and a constant specific heat for both liquids.)
flow rates of both liquids increase by 10 percent.
Refer to the drawing of an operating lube oil heat exchanger (see figure below). Given the following information: cp-oil = 1.1 Btu/lbm-°F cp-water = 1.0 Btu/lbm-°F Toil in = 174°F Toil-out = 114°F Twater-in = 85°F Twater-out = 115°F ṁ oil = 4.0 x 104 lbm/hr ṁ water = ? What is the approximate mass flow rate of the cooling water?
8.8 x 104 lbm/hr
The rate of heat transfer between two liquids in a single-phase heat exchanger will decrease if the…
(Assume constant specific heat capacities.)
flow rate of the colder liquid decreases by 10 percent.
Refer to the drawing of an operating lube oil heat exchanger (see figure below). Given the following information: ṁ oil = 2.0 x 104 lbm/hr ṁ water = 3.0 x 104 lbm/hr cp-oil = 1.1 Btu/lbm-°F cp-water = 1.0 Btu/lbm-°F Tcw-in = 92°F Tcw-out = 125°F Toil-in = 180°F Toil-out = ? Which one of the following is the approximate temperature of the lube oil exiting the heat exchanger (Toil-out)?
135°F
Which one of the following will reduce the heat transfer rate between two liquids in a heat exchanger?
(Assume single-phase conditions and a constant specific heat for both liquids.)
The inlet temperature of the colder liquid increases by 20°F.
The rate of heat transfer between two liquids in a heat exchanger will increase if the: (Assume
single-phase conditions and a constant specific heat for each liquid.)
flow rate of the hotter liquid increases by 10 percent.
Refer to the drawing of an operating lube oil heat exchanger (see figure below). Given the following information: ṁ oil = 1.5 x 104 lbm/hr ṁ water = 2.5 x 104 lbm/hr cp-oil = 1.1 Btu/lbm-°F cp-water = 1.0 Btu/lbm-°F Tcw-in = 92°F Tcw-out = 125°F Toil-in = 160°F Toil-out = ? Which one of the following is the approximate temperature of the lube oil exiting the heat exchanger (Toil-out)?
110°F
Refer to the drawing of an operating lube oil heat exchanger (see figure below). Given the following information: cp-oil = 1.1 Btu/lbm-°F cp-water = 1.0 Btu/lbm-°F ṁoil = 1.2 x 104 lbm/hr ṁwater = 1.61 x 104 lbm/hr Toil in = 170°F Toil out = 120°F Twater out = 110°F Twater in = ? Which one of the following is the approximate cooling water inlet temperature (Twater in) for the heat exchanger?
69°F
Refer to the drawing of an operating lube oil heat exchanger (see figure below). Given the following information: ṁ oil = 1.8 x 104 lbm/hr ṁ water = 3.3 x 104 lbm/hr cp-oil = 1.1 Btu/lbm-°F cp-water = 1.0 Btu/lbm-°F Tcw-in = 90°F Tcw-out = 120°F Toil-in = 190°F Toil-out = ? What is the approximate temperature of the lube oil exiting the heat exchanger (Toil-out)?
140°F
Refer to the drawing of an operating lube oil heat exchanger (see figure below). Given the following information: ṁ oil = 1.5 x 104 lbm/hr ṁ water = 2.5 x 104 lbm/hr cp-oil = 1.1 Btu/lbm-°F cp-water = 1.0 Btu/lbm-°F Toil-in = 160°F Toil-out = 110°F Tcw-in = 92°F Tcw-out = ? Which one of the following is the approximate temperature of the cooling water exiting the heat exchanger (Tcw-out)?
125°F
The rate of heat transfer between two liquids in a heat exchanger will decrease if the: (Assume
single-phase conditions and a constant specific heat for both liquids.)
flow rates of both liquids decrease by 10 percent
Refer to the drawing of a lube oil heat exchanger (see figure below).
Given the following heat exchanger parameters:
• Lube oil flow rate is 200 lbm/min.
• Lube oil enters the heat exchanger at 140°F.
• Lube oil leaves the heat exchanger at 100°F.
• Specific heat of the lube oil is 0.8 Btu/lbm-°F.
• Cooling water flow rate is 400 lbm/min.
• Cooling water enters the lube oil heat exchanger at 60°F.
• Specific heat of the cooling water is 1.0 Btu/lbm-°F.
What is the approximate temperature of the cooling water leaving the lube oil heat exchanger?
76°F
Refer to the drawing of an operating lube oil heat exchanger (see figure below). Given the following information: Q̇ oil = 1.0 x 107 Btu/hr Toil in = 170°F Toil out = 134°F Twater in = 85°F Twater out = 112°F cp-oil = 1.1 Btu/lbm-°F cp-water = 1.0 Btu/lbm-°F ṁwater = ? Which one of the following is the approximate mass flow rate of the cooling water?
3.7 x 105 lbm/hr
Refer to the drawing of an operating lube oil heat exchanger (see figure below). Given the following information: ṁ oil = 1.8 x 104 lbm/hr ṁ water = 3.3 x 104 lbm/hr cp-oil = 1.1 Btu/lbm-°F cp-water = 1.0 Btu/lbm-°F Tcw-in = 90°F Tcw-out = 120°F Toil-in = 170°F Toil-out = ? What is the approximate temperature of the lube oil exiting the heat exchanger (Toil-out)?
120°F
Refer to the drawing of an operating water cleanup system (see figure below).
If cooling water flow rate is 1.0 x 106 lbm/hr, what is the approximate water flow rate in the cleanup
system?
2.2 x 105 lbm/hr
A main turbine-generator was operating at 80 percent load with the following initial steady-state lube
oil and cooling water temperatures for the main turbine lube oil heat exchanger:
Toil in = 174°F
Toil out = 114°F
Twater in = 85°F
Twater out = 115°F
Six months later, the following current steady-state heat exchanger temperatures are observed:
Toil in = 177°F
Toil out = 111°F
Twater in = 85°F
Twater out = 115°F
Assume the lube oil system is a closed system. Also, assume the following did not change:
• Cooling water mass flow rate
• Cooling water and lube oil specific heats
• Heat exchanger heat transfer coefficient
Which one of the following could be responsible for the differences between the initial and current
steady-state heat exchanger temperatures?
The current main turbine lube oil mass flow rate is less than the initial flow rate.
A main turbine-generator was operating at 80 percent load with the following initial steady-state lube
oil and cooling water temperatures for the main turbine lube oil heat exchanger:
Toil in = 174°F
Toil out = 114°F
Twater in = 85°F
Twater out = 115°F
Six months later, the current steady-state heat exchanger temperatures are:
Toil in = 174°F
Toil out = 120°F
Twater in = 85°F
Twater out = 120°F
Assume that the lube oil mass flow rate does not change, and that the specific heat values for the
cooling water and lube oil do not change. Also assume that the main turbine lube oil system is a
closed system.
The differences between the initial and current steady-state heat exchanger temperatures could be
caused by the current main turbine-generator load being __________ with the current heat exchanger
cooling water mass flow rate being __________.
lower; lower
Refer to the drawing of an operating parallel-flow lube oil heat exchanger (see figure below).
Assume that lube oil (LO) inlet temperature is greater than cooling water (CW) inlet temperature.
Unlike a counter-flow heat exchanger, in a parallel-flow heat exchanger the __________ temperature
can never be greater than the __________ temperature.
CW outlet; LO outlet
Refer to the drawing of an operating process water cleanup system (see figure below).
Assume there is no heat loss from the process water cleanup system to the surroundings and the
process water flow rate does not change. If valve D closes fully, what will be the final steady-state
temperature of the process water flowing through the filter?
540°F
A counter-flow heat exchanger is being used to cool the lube oil for a main turbine and generator.
The main turbine and generator was initially operating at 100 percent load with the following stable
heat exchanger conditions:
Toil in = 174°F
Toil out = 114°F
Twater in = 85°F
Twater out = 115°F
Main turbine and generator load was reduced, and the heat exchanger cooling water mass flow rate
was decreased to one-half of its initial value, resulting in the following stable current conditions:
Toil in = 178°F
Toil out = 138°F
Twater in = 85°F
Twater out = ?
Assume that the lube oil mass flow rate and the specific heats of both fluids did not change.
Which one of the following is the current cooling water outlet temperature?
125°F
Given the following parameter values for a feedwater heater:
Feedwater inlet temperature = 320°F
Feedwater inlet pressure = 1,000 psia
Feedwater mass flow rate = 1.0 x 106 lbm/hr
Extraction steam pressure = 500 psia
Assume that the extraction steam enters the heater as a dry saturated vapor and leaves the heater as a
saturated liquid at 500 psia.
Which one of the following is the approximate mass flow rate of extraction steam required to increase
feedwater temperature to 380°F?
8.4 x 104 lbm/hr
Refer to the drawing of an operating parallel-flow lube oil heat exchanger (see figure below).
Unlike a counter-flow heat exchanger, in the parallel-flow heat exchanger the __________
temperature will always be greater than the __________ temperature.
LO outlet; CW outlet
Which one of the following will increase the heat transfer rate between two liquids in a heat
exchanger? (Assume single-phase conditions and a constant specific heat for both liquids.)
The inlet temperature of the hotter liquid increases by 20°F.
Given the following parameters for an operating lube oil heat exchanger: Lube oil inlet temperature = 150°F Lube oil outlet temperature = 105°F Cooling water inlet temperature = 60°F Cooling water outlet temperature = 110°F Considering only counter-flow and parallel-flow heat exchanger designs, the lube oil heat exchanger described above must be…
counter-flow, because the lube oil outlet temperature is less than the cooling water outlet
temperature.
A reactor is shut down with core decay heat being removed by the residual heat removal (RHR)
system. Assume that only the RHR heat exchangers are removing heat from the reactor coolant
system (RCS), and that the RHR system provides complete thermal mixing of the RCS. Also, assume
that core decay heat is the only source of heat addition to the RCS.
Given the following information:
Reactor core rated thermal power = 2,950 MW
Core decay heat rate = 0.5% rated thermal power
RHR system heat removal rate = 5.3 x 107 Btu/hr
RHR and reactor coolant cp = 1.05 Btu/lbm-°F
Combined RCS and RHR inventory = 425,000 lbm
Which one of the following actions will establish a reactor cooldown rate between 20°F /hour and
30°F/hour?
Increase RHR heat exchanger flow rate to increase the cooldown rate by 20°F/hour.
A reactor is shut down with core decay heat being removed by the residual heat removal (RHR)
system. Assume that only the RHR heat exchangers are removing heat from the reactor coolant
system (RCS), and that the RHR system provides complete thermal mixing of the RCS. Also, assume
that core decay heat is the only source of heat addition to the RCS.
Given the following information:
Reactor core rated thermal power = 2,950 MW
Core decay heat rate = 0.5% rated thermal power
RHR system heat removal rate = 5.7 x 107 Btu/hr
RHR and reactor coolant cp = 1.05 Btu/lbm-°F
Combined RCS and RHR inventory = 450,000 lbm
Which one of the following actions will establish a reactor cooldown rate between 20°F/hour and
30°F/hour?
Increase RHR heat exchanger flow rate to increase the cooldown rate by 10°F/hour.
A reactor is shut down with core decay heat being removed by the residual heat removal (RHR)
system. Assume that only the RHR heat exchangers are removing heat from the reactor coolant
system (RCS), and that the RHR system provides complete thermal mixing of the RCS. Also, assume
that core decay heat is the only source of heat addition to the RCS.
Given the following information:
Reactor core rated thermal power = 2,950 MW
Core decay heat rate = 0.6 percent of rated thermal power
RHR system heat removal rate = 8.1 x 107 Btu/hr
RHR and reactor coolant cp = 1.05 Btu/lbm-°F
Combined RCS and RHR inventory = 450,000 lbm
Which one of the following actions will establish an RCS cooldown rate between 20°F/hour and
30°F/hour?
Reduce RHR heat exchanger flow rate to decrease the cooldown rate by 20°F/hour.
A reactor is shut down with the residual heat removal (RHR) system in service. Assume that only the
RHR heat exchangers are removing heat from the reactor coolant system (RCS), and the RHR system
provides complete thermal mixing of the RCS. Also, assume that core decay heat is the only source
of heat addition to the RCS.
Given the following current information:
Reactor core rated thermal power = 2,950 MW
Core decay heat rate = 0.6 percent of rated thermal power
RHR system heat removal rate = 4.7 x 107 Btu/hr
RHR and reactor coolant cp = 1.05 Btu/lbm-°F
Combined RCS and RHR coolant mass = 450,000 lbm
Which one of the following actions will establish a reactor coolant heatup rate between 10°F/hour and
20°F/hour?
Increase RHR heat exchanger flow rate to reduce the heatup rate by 10°F/hour
Refer to the drawing of an operating water cleanup system (see figure below).
All valves are identical and are initially 50 percent open. To lower the temperature at point 7, the
operator can adjust valve __________ in the open direction.
D
Refer to the drawing of an operating lube oil heat exchanger (see figure below).
Increasing the oil flow rate through the heat exchanger will cause the oil outlet temperature to
__________ and the cooling water outlet temperature to __________.
increase; increase
Refer to the drawing of an operating lube oil heat exchanger (see figure below).
Assume that the inlet lube oil and inlet cooling water temperatures are constant and cooling water flow
rate remains the same. Decreasing the oil flow rate through the heat exchanger will cause the lube oil
outlet temperature to __________ and the cooling water outlet temperature to __________.
decrease, decrease