halogenalkenes Flashcards
1
Q
- Define nucleophile.
A
- A species that donates a lone pair of electrons.
2
Q
- Explain why nucleophiles can react with halogenalkanes.
A
- The carbon in the functional group is δ+ as it is attached to a halogen atom that is more electronegative. The δ+ carbon will attract nucleophiles.
3
Q
- Briefly describe homolytic fission and heterolytic fission.
A
- Homolytic fission – breaking a covalent bond so each atom gets one unpaired electron (free radical). Heterolytic fission – breaking a covalent bond so the more electronegative atom gets a lone pair of electrons.
4
Q
- Name and outline the mechanism for the reaction of 1-bromopropane with warm, aqueous NaOH. Write an overall equation for this reaction.
A
- . Nucleophilic substitution
5
Q
- Name and outline the mechanism for the reaction of 1-bromopropane with hot, ethanolic potassium cyanide. Write an overall equation for this reaction. Name the organic product that is formed.
A
6
Q
- Name and outline the mechanism for the reaction of bromoethane with warm, ethanolic ammonia. Write an overall equation for this reaction. Name the organic product that is formed.
A
7
Q
- When 1-chlorobutane, 1-bromobutane and 1-iodobutane react with water, 1-iodobutane reacts the fastest whilst 1-chlorobutane reacts the slowest. Explain these results.
A
- 1-iodobutane reacts the fastest and 1-chlorobutane reacts the slowest. This is because C-I has the weakest bond enthalpy so it is easiest to break.
8
Q
- When a halogenalkane reacts with NaOH/KOH, two different mechanisms can occur. Name these two different mechanisms and state the conditions that make it more likely to occur.
A
- Halogenalkane + aqueous NaOH/KOH will react via nucleophilic substitution mechanism. It is more likely with primary halogenalkanes. Halogenalkanes + hot, ethanolic NaOH/KOH will react via an elimination mechanism. It is more likely with tertiary halogenalkanes.
9
Q
- Name and outline the mechanism for the reaction of 2-chlorobutane with hot, ethanolic NaOH to form but-1-ene.
A
- Elimination:
10
Q
- Name and outline the mechanism for the reaction of 2-chlorobutane with hot, ethanolic NaOH to form but-2-ene.
A
- Elimination:
11
Q
- How are halogenalkanes classified as primary/secondary/tertiary?
A
- Primary halogenalkanes – have one R group attached to the carbon of the functional group. Secondary halogenalkanes – have two R groups attached to the carbon of the functional group. Tertiary halogenalkanes – have three R groups attached to the carbon of the functional group.