Group 7 Flashcards
What is the name for group 7 elements
Halogens
Are halogens metals
No
What do halogens exist as
Simple molecules, which is a pair of halogen atoms joined together with a covalent bonds
Explain why the BP and MP increase as you go down the group
- Molecules become larger
- Intermolecular forces become stronger
- More energy is needed to overcome these bonds
State the state and colour of bromine, iodine and chlorine at room temp
Iodine - Solid & Purple-Black
Bromine - Liquid & Brown
Chlorine - Gas & Pale Green
Explain the reactivity of group 7 elements
They all have 7 electrons in the outer most shell, so they have similar chemical reactions
What is the product of halogens reacting with metals
Salts, which are made up of ions (held together by ionic bonds)
How do sodium and chloride react when heated vigorously
Orange flame and clouds of white sodium chloride
How do fluorine, iodine, bromine, chlorine react with iron wool
Fluorine - Cold iron wool burns to produce iron fluoride
Chlorine - Hot iron wool burns vigorously to produce orange-brown iron chlorine
Bromine - Hot iron wool burns quickly to produce red-brown iron fluorine
Iodine - Hot iron wool reacts in iodine vapour to form grey iron iodide
State the symbol equation for the reaction of iron and chlorine
2Fe(s) + 3Cl2(g) → 2FeCl3(s)
Name the product of halogens reacting with hydrogen
Halogen halide
What is the state of a halogen halide
They are gases and dissolve in water to produce acidic solutions
How do fluorine, bromine, iodine and chlorine react with hydrogen
Fluorine - Explodes at room temperature forming hydrogen fluoride
Chlorine - Explodes with a flame forming hydrogen chloride
Bromine - Vigorous reaction when warmed with hydrogen, forming hydrogen bromide
Iodine - Very slow reaction when heated strongly, forming some hydrogen iodide
Explain displacement reactions within group 7
A more reactive halogen can displace a less reactive halogen from solution of its salts
Write a symbol equation for the displacement reaction between bromine and sodium iodine solution
Br2(aq) + 2NaI(aq) → 2NaBr(aq) + I2(aq)
