GRE Tips & Tricks Flashcards
RTD Problems
Make a table for the information:
Rate Time Distance Car
OR
Rate Time Distance Harvey Clyde
Relative RTD Problems
Make a table to combine the information:
Rate Time Distance Harvey Clyde ------------------------------------------------------------------------ Total
Population Problems
Sometimes you need to pick a smart # to start the population and use the rate.
Ratio Labeling
Always label the ratio with units so you don’t mix up the ratio.
Ex: x dogs : x cats = 2 dogs : 3 cats
Commission-Salary Problems
Set up a chart where you can see the change in numbers:
Average # Sum Old Total: $800 n 800n This Sale: $2000 1 2000 New Total: $900 n + 1 900(n+1)
800n + 2000 = 900(n+1)
11 sales = n + the big sale = 12 sales total
Evenly Spaced Sets Trick
Median = Average, so just add the first and the last terms, then divide by two.
(First + Last)/2 = average/median
STD Question Types
1) changes in STD when a list is transformed = closer/farther from mean?
2) comparisons of the STD of two or more lists = more spread out from its mean?
Anagram Problems
Most problems involving rearranging objects can be solved by anagramming.
Anagram Problems- Uncounting
You have to “uncount” different arrangements when calculating the number of possible arrangements. Set up an Anagram Grid with unique items/people on top and repeating labels on bottom.
Ex: 7 people on shuttle, 3 seats available.
Person = 7! 7 x 6 x 5 x 4 x 3 x 2 x 1 Seat = 4! 4 x 3 x 2 x 1
7!/4! Possible Arrangements = 7 x 6 x 5 = 210
- You divide by 4! because these arrangements are irrelevant. Seats vs no seats, they are distinguishable.
Anagram Problems- CAN’T Uncount
You cannot “uncount” different arrangements when the “chosen ones” are indistinguishable from the “unchosen ones”
Ex: 7 standby passengers, 3 are selected for a flight.
- The 7 passengers are all the same! You cannot distinguish between them. Thus…
Person A B C D E F G
Seat Y Y Y N N N N
Person = 7! 7 x 6 x 5 x 4 x 3 x 2 x 1 Seat = (3! x 4!) (3 x 2 x 1) (4 x 3 x 2 x 1)
7!/(3! x 4!) Possible Arrangements = 7 x 5 = 35
Basic Quantitative Comparison Tips
3 Tips
1) Try to prove D
- Use -1, 0, and 1
- Use positive numbers greater than 1 and fractions between 0 and 1
- Use negative numbers less than -1 and fractions between 0 and -1
2) Use the Invisible Inequality
- Add or subtract to both quantities
- Multiply or divide both quantities by a positive number
- Square or square root both quantities if they are positive.
3) Use Quantity B as a Benchmark
- Use when Quantity B is a number (no variables)
- When Quantity A requires calculation, try to save time by using Quantity B
- Use Quantity B as a guide to try to prove (C)
Variable Quantitative Comparison Problems (Algebra)
4 tips
1) If a variable has a unique value (Ex: x+3 = -5) then solve for the value of the variable.
2) If a variable has a defined range (Ex: -4 ≤ w ≤ 3) then test the boundaries
3) If a variable has a relationship with another variable (Ex: 2p = r) then simplify the equation and make a direct comparison of the variables.
4) If a variable has no constraints, then try to prove (D).
5) If a variable has specific constraints (Ex: x is negative), then try to prove (D).
Quadratic Equation Quantitative Comparison Problems (Algebra)
2 tips
1) If a quadratic appears in one or both quantities:
- FOIL the quadratic
- eliminate common terms, and
- compare the quantities
2) If a quadratic appears in the common information
- factor the equation and find both solutions, and
- plug both solutions into the quantities for A and B.
*Strange Symbol Quantitative Comparison Problems (Algebra)
2 tips
1) If the question contains numbers, plug in the numbers and evaluate the formula.
2) If the question does not contain numbers, plug the give variable(s) directly into the formula.
Absolute Values Quantitative Comparison Problems
(Algebra)
2 tips
1) If the absolute value also contains a positive number, make the variable positive to maximize the absolute value.
2) If the absolute value also contains a negative number, make the variable negative to maximize the absolute value.