Gravitational Fields Flashcards
Define Gravitational Field
A region where an object that has mass, experiences a force
State newton’s law of gravitation and state equation it comes from
Attractive forces between two point masses is directly proportional to the product of their masses and inversely proportional to the square of their seperation
F=GMm/r^2
Define Gravitational Field strength and state the equation it comes from
Force acting on a body per unit mass
G=F/m
Equations for potential energy for uniform and radial field and define potential energy
Uniform, Ep=mgh
Radial = (Gm1m2)/r
Work done in moving object with mass from infinity to that point in the field
Define absolute Gravitational potential energy
Work done per unit mass in moving a body from infinity to that point in Gravitational Field
V=GM/r
Work done = m x V
Derive two equations to show Kepler’s 3rd Law
Derive two equations for equation of orbital velocity
Derive two equations to get equation for escape velocity
Derive two equations for total orbital energy
State times for Low earth orbit (LEO), Medium earth orbit (MEO), High earth orbit (HEO)
LEO : less than 2 hours
MEO : More than 2 hours and less than 24 hours
HEO : greater than 24 hours
Similarity and difference between geostationary and geoschrynous orbits, state advantage of geostationary
Similarity : time period of 24 hours
Differnce : geostationary orbits above same point Earth’s equator
Geoschrynous orbit do not stay above same points of Earth’s surface
Advantage : easier to track
State uses of geostationary orbits
State a little explanation
Monitoring weather : whole earth may be scanned
GPS : several satellites needed to fix position on earth
Communications : limited by intermittent contact
Problem of putting more satellites in orbit
Satellites orbit in closer proximity
Greater risk of collisions
What is meant by satellites in polar orbits
State uses
Satelite passes over north and south poles
Making them ideal for espionage (spying on other countries)
A
Speed = distance / time
Distance = 2.04 x 10^7
Can’t use Kepler’s third law as that gives the orbital of the earth, so your radius would just be equal to radius of earth