GENOMICS Flashcards

1
Q

Why use DNA polymerase for enzyme restriction?

A

PCR
Generate probes
Blunt endings of DNA

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2
Q

Why use polynucleotide kinase for enzyme restrictions?

A

Used to phosphorylate chemically synthesised DNA - can be ligated to another fragment.
Used to sensitively label DNA so that is can be traced using - radioactively labelled ATP or fluorescently labelled ATP

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3
Q

Features of plasmid vectors

A

Can be linearised at 1 or more sites in non-essential stretches of DNA
Can have DNA inserted into them
Can be re-circularised without loss of the ability to replicate
Often modified to replicate at high multiplicity within a host cell
Contain selectable markers
Most are relatively small 4-5kb in size

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4
Q

How are bacterial plasmids used as a vector

A

The vector and the PCR amplicon of the gene must be cut with restriction enzymes to produce compatible ends
Then joined by ligation using DNA ligase

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5
Q

Functionality of Plasmids

A

Express the recombinant gene in a living organism of choice
add or modify control elements
alter the properties of the gene product

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6
Q

Why are plasmids an essential part of the tool kit?

A

Discrete circular dsDNA molecules
Are a means by which genetic information is maintained in bacteria
Genetic elements that exist replicate independently of the bacterial chromosomes and therefore extra-chromosomal
Normally exchanged between bacteria within a restricted host range

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7
Q

The reaction for DNA sequencing

A
Sequencing reaction
Strand separation
Annealing primer
Extension
Chain termination
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8
Q

Describe the steps for DNA sequencing, strand separation and annealing primer

A

DNA is mixed with dideoxy and deoxy nucleotides
Oligonucleotide primer binds to template
polymerase recognises the primer and creates an initiation complex and start elongation.

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9
Q

How does dideoxy chain termination work?

The steps in dideoxy chain termination

A
  1. Have a produce template – done by PCR
  2. Enzymatic sequencing reaction – DNA polymerase make multiple copies of DNA
  3. Size separation of products by capillary electrophoresis – sorting by size
  4. Detection of reaction products – sequential detection of the terminating nucleotide to identify the base
  5. Readout of sequence – reconstructing the sequence
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10
Q

Principles of genetic linkage

A

Genetic linkage - tendency to alleles at neighbouring loci to segregate together at meiosis
Cross overs are more likely to occur between loci separated by distance than between loci close together on chroomosome

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11
Q

What is linkage analysis?

A

Method used to map the location of a disease gene in the genome
Genetic markers that are close to our disease gene will be co-inherited together

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12
Q

Ideal genetic markers

A
Polymorphic
Randomly distributed across the genome
Fixed location in genome
Frequent in population
Stable with time
Easy to assay
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13
Q

Mechanism for X-inactivation

A

The Xist gene is transcribed as a long non-coding RNA from the X-inactivation centre and binds all over the X-chromosome
Histone acetylation removed and histone and DNA methylation occur
Inactive X-chromosome is heterochromatic – Barr body
Tsix is derived by transcription in the opposite direction and antagonises Xist RNA to keep 1 X active

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14
Q

What does transcriptomics do

A

Discovers the biology of your samples
Classify samples
Predict which class a sample belongs to

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15
Q

Data analysis work flow

A

1) Feature extraction
2) Quality control
3) Normalisation
4) Differential expression analysis
5) Biological analysis
6) Submit data to public repository

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16
Q

Expression analysis

A

1) Normalisation
2) Hierarchial clustering
3) Gene filtering
4) Statistical tests
5) Generate gene list
6) Biological interpretation

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17
Q

How do SNP microarrays work

A

Microarrays hybridise with genomic DNA adjacent to SNPs

The SNP is extended by 1 base that is fluorescently labelled and detected using a high definition scanner

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18
Q

Steps in next generation sequencing

A

1) DNA library construction
2) Cluster generation
3) Sequencing by synthesis
4) Data analysis

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19
Q

Describe the process of DNA library construction

A

Shearing - DNA chopped into small fragments

Must repair the ends of fragments - Adapters added

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20
Q

Describe the process of cluster generation

A

Hybridise DNA library fragment to flow cell - is random.

Must amplify fragments. - bridge amplification to make clusters

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21
Q

Describe the process of sequencing by synthesis

A

Modified 4 bases with chain terminators, different fluorescent colour dye.
Sequence each single nucleotide 1 cycle at a time in a controlled manner.
Single nucleotide incorporation (DNA polymerase)
Flow cell wash
Image the 4 bases
Repeat for full length sequence

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22
Q

How is RNA sequenced in NGS

A

RNA first converted to cDNA before library construction.
NGS of RNA samples - show which genes are actively expressed.
Number of sequencing reads = measure gene abundance
RNA seq can discover distinct isoforms of genes

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23
Q

Metagenomics

A

Study of genetic material covered directly from environmental or biological systems/compartments

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24
Q

Microbiome

A

Characteristic microbial community occupying a reasonably well defined habitat which has distinct physio chemical properties

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25
Q

Microbiota

A

Ecological community of commensal and pathogenic microorganisms. Includes bacteria, achraea, fungi and viruses

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26
Q

Work flow of 16S PCR amplification

A

1) sample collection
2) DNA extraction
3) 16S PCR amplification
4) Sequencing
5) Analysis

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27
Q

In 16S PCR amplification which variable region is chosen?

A

Choice of variable region determines resolution - longer = greater resolution.

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28
Q

Which controls to use in 16S PCR amplification

A

16SrRNA gene found in all bacteria

Method sensitive to contamination

29
Q

How to prevent contamination in 16S PCR amplification

A

Randomise samples
Note batch numbers of reagants
Sequence negative controls

30
Q

What is whole genome shotgun metagenomics?

A

Assess taxonomic diversity in sample
Assess composite gene functions in sample
Unbiased, all micro-organisms

31
Q

Work flow of whole genome shotgun

A
Sample collection
DNA extraction
Whole genome sequencing
Sequencing
Analysis
32
Q

How to enrich without amplification - Pre-extraction

A

Differential lysis of mammalian cells
Enrich for intact microbial cells
Potential bias towards gram-positive bacteria

33
Q

How to enrich without amplification - post-extraction

A

Enzymatic degradation of methylated nucleotides target mammalian DNA
Bias against AT rich bacterial genomes

34
Q

Mechanism of RNAi mediated gene silencing

A

ShRNA procude 50-70 nucleotides. Once transcribed it exits the nucleus. Cleaved by a nuclease = DICER
Cleaved segments bind to RISC and direct cleavage and degradation of complementary mRNA

35
Q

How to make a mutant mouse

A
  • Targeting vector constructed and introduced into the nucleus of pluripotent ES cells.
  • Gene integrates in the cassette. ES selected.
  • Positive ES cells grown to blastocytes and implanted into a pseudo pregnant recipient mouse DNA cassette.
  • Flanked both upstream and downstream with DNA sequences that match with site introduced - HOMOLOGENE ARMS
36
Q

Site specific recombinase

A

Efficiently cause deletions or translocations, inversions in the genomic DNA with high fidelity

37
Q

Cre-lox system

A

Site specific recombinase technology.

Cre-recombinase recombines a pair of lox sequences.

38
Q

Mechanism of deletion in cre-lox system

A

LoxP sites face the same direction

Cre-recombinase will detect the unidirectional loxP sites and excise the floxed segment of DNA

39
Q

Mechanism of inversion in cre-lox system

A

LoxP sites orientated towards each other.

Region floxed will become inverted

40
Q

Translation blocking MOs

A

Bound to 5’ UTR of mRNA

Interfere with ribosomal initiation - prevent translation of transcript

41
Q

Splice inhibiting MOs

A

Prevent splice directing small ribonucleoprotein complexes from binding to their targets at the borders of introns on a strand of pre-mRNA

42
Q

What does CRISPR/Cas9 system do

A

Guide RNA binds to strand of genomic DNA
Cas9 endonucleases bind to non-protospacer portion of gRNA + PAM of DNA.
DSB 3bp upstream of PAM
Mutations can be introduced through NHEJ and HDR

43
Q

Mitochondrial DNA replication machinery

A

Polymerase G
Twinkle
Single stranded binding protein (mtSSBP)
TFAM

44
Q

Steps in strand displacement model of mtDNA replication

A
  1. Replication of heavy strand begins at origin of heavy strand
  2. Replication of light strand begins at origin of light strand
  3. Replication of both strands completed
  4. Segregation of daughter molecule
45
Q

Describe what happens in the initiation of heavy strand replication

A

Parental heavy strand displaced and coated with mtSSBP
Twinkle helicase unwinds mtDNA
Mitochondrial RNA polymerase synthesise RNA primer using light strand as template.
Polymerase G use RNA primer to replicate DNA at origin of heavy strand

46
Q

Describe what happens when light strand begins replication

A

Heavy strand replication passes to origin of light strand.
STEM LOOP structure is formed preventing mtSSBP binding.
Mitochondrial RNA polymerase synthesises RNA primer using heavy strand as template
Polymerase G uses RNA primer to replicate light strand at origin

47
Q

Genomic imprinting

A

Is the selective expression of genes related to the parental origin of the gene copy

48
Q

Process of imprinted genes

A

Is mediated by Imprinting control regions (ICRs)
1 copy is silenced by DNA methylation catalysed by DNMT3a and histone methylation - leading to inactivation
Imprinting patterns are reset during gamete formation

49
Q

Hyperchromicity

A

Increased absorption of light at 260nm on denaturation

Single stranded DNA absorbs UV light better than double stranded DNA

50
Q

Tm

A

Point at which 50% of all strands separate

51
Q

Things that affect Tm

A
GC content
Length
Salt concentration
pH
Mismatches
52
Q

Complementarity

A

Perfect mathces have higher Tm
Perform hybridisation at the Tm of perfectly matched duplexes
Mismatches would be unstable at high temperatures

53
Q

Stringency

A

Manipulate conditions
Limit hybridisation between imperfectly matched sequences increases specificity
Determined by temperature near Tm or low salt concentration

54
Q

Microarrays

A

Ordered assembly of thousands of nucleic acid probes

Probes fixed to a solid surface, sample hybridised to probes

55
Q

What do restriction endonucleases do

A

Recognise specific sequence
Cut that sequence
Limit the transfer of nucleic acids from infecting phage’s into bacteria

56
Q

Migration

A

Physical movement of people from a different population = new pools of variants being introduced to an existing population = ADMIXTURE

57
Q

Cross species comparison

A

Generate evolutionary profile for a gene or gene family

58
Q

Cross species conservation

A

Identify important regions of a gene and its protein

59
Q

Gene duplication

A

Duplication of a DNA sequence containing a gene

Mechanism = unequal crossing over

60
Q

Unequal crossing over

A

Recombination between sequences that are not correct sequence but are very similar

61
Q

Alpha globin genes

A

Chromosome 16

3 genes and 3 pseudo genes

62
Q

Beta globin gene

A

Chromosome 11

5 gene 1 pseudogene

63
Q

Globin cluster evolution

A

Through duplication and divergence
Globin genes evolved through duplication and accumulation of mutations (divergence)
Some are functioning genes, and some are not (pseudogenes)
Divergence of promoters has occurred so bind different transcription factors and allow expression of genes at different stages of development

64
Q

Pseudogenes

A

Typically have mutations and are nono-functional
Many of them in genome
After gene duplication, 1 gene can maintain the original function and the other can diverge

65
Q

Sickle cell disease symptoms

A

Anaemia – fatigue, restlessness, jaundice
Acute pain episodes – due to O2 deprivation of tissues
Increased frequency of infections – spleen damage
Also, stroke, pulmonary hypertension, gallstones, liver and kidney problems, joint problems, delayed puberty

66
Q

Genetics of SCD

A

single base change in beta-globin gene of Hb A = HbS

Is an autosomal recessive genetic disease. Is a codon change

67
Q

Natural selection and HbS

A

2 copies of HbS variant has significant negative effects on reproductive ability – SCD
1 copy of HbS variant confers resistance to severe malaria = heterozygote advantage – HbS variant is maintained in the population

68
Q

Problems with GWAS

A
identify associations, however contribution to genetic component is low
Many common SNP
Rare SNP
Copy number variation
Epigenetic variation