Genome structure and chromatin (8) Flashcards

1
Q

Minor and major groove

A

The major groove occurs where the sugar-phosphate backbones are far apart, the minor groove occurs where they are close together.

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2
Q

Structure of the DNA molecule

A

The DNA molecule consists of 2 polynucleotide chains forming a double helix. The repeating unit is a nucleotide, consisting of a phosphate group, a sugar (2´ deoxyribose), and a nitrogen base (purines adenine, guanine and pyramidines thymine and cytosine). There´s always a purine interacting with a pyrimidine, with either 2 or 3 hydrogen bonds. Nucleotides are joined together in polypeptide chains, with so-called phosphodiester linkages.

The two stands are complementary, with one strand in 3´-5´direction and the oter in 5´-3´direction. The molecule is negatively charged because of the negative phosphate group.

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3
Q

Differences in genome organization between prokaryotes and eukaryotes (origin of replication, telomeres, centromeres)

A

Prokaryotic cells have their circular chromosome organized in the nucleoid (as well as plasmids), whereas eukaryotic have their linear chromosomes organized within the cell nucleus.

Both have origins of replication, but while prokaryotic cells one have a single origin, eukaryotic cells have several (each 30-40 kb throughout) -> enables effective replication

Prokaryotes don´t need telomeres because of their circular chromosomes, while eukaryotes have it to maintain the ends of their linear chromosomes. Consists of tandem repeats and act as specialized origins of replication.

Only eukaryotes have centromeres. Consist of tandem repeats and direct the formation of kinetochores.

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4
Q

How do you determine complexity of an organism? Genome size, number of genes, gene density? How do you calculate gene density?

A

Genome size generally increases with the complexity of the organism, but we can’t only look at genome size to describe the complexity. The same goes for number of genes. Gene density (number of genes/Mb) is the best way to determine complexity, as it decreases with the complexity -> Complex organisms like humans have low gene density. This is because complexity isn´t determined by the number of genes, but rather by their regulation from intergenic sequences.

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5
Q

What % of the human genome is classified as pure genes?

A

1.5%

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6
Q

Of human genes, approx. how many % are made up of introns? What’s the average number of introns per human gene?

A

95%, average is 6 introns per gene

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7
Q

Gene fragment

A

A former function gene has been truncated due to mutations, leaving only a small part of the gene. This gene fragment is no longer functional.

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8
Q

Pseudogene

A

Originates from reverse-transcribed mRNAs. When a gene is transcribes into an mRNA strand, this strand might be reversely transcribed back into DNA and reincorporated in the gene. The result is a pseudogene that can no longer produce a protein, but might play a role in the regulation of their parent genes.

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9
Q

Types of repetitive intergenic sequences in the human genome

A

Microsatellites: Short repeated sequences (< 13 bp), approx. 3% of the genome. Can be either tandemly repeated (same repeat over and over) or interspersed throughout the genome.

Genome wide repeats: Repeats originating from transposable elements (100 to > 1000 bp), approx. 45% of the genome. Interspersed, caused by transposable elements “jumping” throughout the genome and leaving copies behind. Rare event, but accumulates over time.

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10
Q

Nucleosome

A

The fundamental unit of the chromatin, consisting of two copies of each of the core histones (H2A, H2B, H3 and H4) and approximately 147 basepairs (bp) of DNA. Protein-DNA complex, first level of compaction (6-fold). Nucleosomes are connected by linker DNA (length varies between and within species)

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11
Q

Histone octamer

A

Consists of 2 times the 4 core histone proteins H2A, H2B, H3 and H4 - equal amounts of the histones. The DNA is wrapped around the histone core to form the nucleosome.

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12
Q

Histone-fold domain

A

All the core histones consists of a histone-fold domains, which is generated by 3 alpha-helixes. This domain is conserved between species, and aids the histones with nucleosome assembly.

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13
Q

Histone tails

A

The N-terminals (amino-terminal) of the histone proteins, protruding out of the nucleosome through the minor groove channels. These tails can be covalently modified.

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14
Q

Assembly of a nucleosome

A

With the help of the histone-fold domain, a tetramer of H3 and H4 and two dimers of H2A and H2B assembles into a histone core. The DNA strand first associates with the H3-H4 tetramer before two H2A-H2B dimers associate. All together there are 8 histone proteins in the core of an assembled nucleosome, with the DNA strand wrapped around the core 1.7 times.

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15
Q

DNA nucleosome interactions

A

The central 60 bp of DNA interacts with H3-H4 at the top half of the nucleosome, whereas the H2A and H2B associates with about 30 bp on the sides of the central. These interactions are around equal in strength. The interaction within the nucleosome are completely sequence-independent, meaning that there’s so sequence specificity and it doesn’t matter which nitrogen base takes part in the interaction (gene and repeat is equally treated).

There are 14 distinct sites of contacts, and they are all to the minor groove of the DNA molecule. Between histones and the DNA there are about 40 hydrogen bonds, mostly between the oxygen of the histone and the phosphodiester in the DNA backbone.

Such interactions facilitates the bending of DNA; DNA is generally negatively charged, and without basic (positive) histones it would not be able to bend because the two negative strands would repel each other.

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16
Q

Histone H1

A

(not core) Histone which facilitates the formation into more complex structures after the first level of compaction (the nucleosome). Binds to linker DNA between nucleosomes and the central helix, which facilitates compaction of DNA into the structure called 30 nm fiber, which is a 40-fold compaction. A consequence of this is the DNA being less accessible to many DNA binding proteins. H1 is 50% as abundant as core histones.

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17
Q

The 30nm chromatin fiber

A

40-fold compaction structure facilitated by H1-binding of nucleosomes. Histone tails are also required for formation of the 30 nm fiber, as the positively charged tails most likely stabilizes the fiber through interaction with the negative DNA on adjacent nucleosomes.

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18
Q

2 models of structures (configurations) of the chromatin fiber

A

Solenoid: The DNA forms a superhelix with (approx.) 6 nucleosomes in a “circle”, where the linker DNA is buried within the circle. As a consequence, the entry/exit is not accessible.

Zigzag: Requires linker DNA to pass through the centre axis, meaning that there are DNA strands throughout the entire structure. This configuration is favored by longer linker DNA.

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19
Q

A higher-order structure of chromatin after 30 nm chromatin fiber involves a nuclear scaffold . What is this, and which proteins are involved?

A

A popular model propose that the 30 nm chromatin fiber forms loops around a protein scaffold, which leads to a higher level of compaction. The proteins involved in this scaffold is topoisomerase II (which can cut both DNA strand simultaneously, thereby manage DNA tangles and supercoils) and SMC proteins (structural maintenance of chromosomes) like cohesin and condensin.

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20
Q

Euchromatin

A

A low compaction of chromatin (lightly stained) where the DNA strand is open and easier to accessed, although not all genes are expressed even though they are located in euchromatin areas.

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21
Q

Heterochromatin

A

A high compaction of chromatin (densely stained) where the DNA strand is more closed off and difficult to access, although there can still be some degree of gene expression in heterochromatin areas (not 9%).

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22
Q

What are the 2 types of chromosome organization during the cell cycle? What are the key differences between the two?

A

Interphase chromosomes and metaphase chromosomes

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23
Q

Interphase chromosomes

A

Chromosomes are in this state during the G1, S and G2 phase of the cell cycle. During the interphase the chromosomes occupies all the nucleus, with each chromosome having its own territory. There is little interaction between chromosomes in the different territories, and the territories of two copies of the same chromosome aren’t necessarily adjacent. You can find heterochromatin towards the nuclear membrane, surrounding the nucleus, while euchromatin is usually dispersed throughout the center.

During the S-phase of the interphase the chromosomes are duplicated during the DNA replication. This occurs while the chromosomes are still in their respective chromosome territories. The replication starts at the origins of replication, and the two sister chromatids will be bound together by a large protein complex called cohesin immediately after replication. Cohesin forms large rings that establishes sister-chromatid cohesion, keeping the copies closely together within the nucleus. This is the beginning of the formation of metaphase chromosomes.

24
Q

Metaphase chromosomes

A

Formation of M phase chromosomes is induced by cohesin- and condensin protein complexes. Sister-chromatid cohesion is established by cohesin rings during the S-phase, holding the chromosome copies closely together. Condensin will bind to the chromatid to condense it even further (mitotic chromatin condensation).

25
Q

Sister-chromatid cohesion

A

The two copies of replicated chromosomes (sister chromatids) are held together by rings of cohesin immideately after DNA replication. Stays together until anaphase, where the cohesin is cleaved.

26
Q

Cohesin

A

Large, ring-shaped protein complex which establishes sister-chromatid cohesion, keeping the chromosome copies closely together within the nucleus before mitosis is initiated.

27
Q

How is the amount of histones duplicated during the S-phase of the interphase?

A

The nucleosomes are first disassembled; H3:H4 is never released from the DNA, while H2A:H2B is released and enters the local pool of histones. The nucleosomes are then reassembled, with the H3:H4 binding to one of the daughter duplexes at random, followed by H2A:H2B. Assembly of nucleosomes is promoted by histone chaperones.

28
Q

Histone chaperones

A

Promotes assembly of nucleosomes by bringing in histones to the nucleosome. There are many different chaperones which interact with different types of histones.

29
Q

Describe the condensation and organization of the chromatin during the different stages of the cell cycle (briefly)

A

Interphase: Located in chromosome territories, occupies all parts of the nucleus. S-phase: Copied into sister chromatids and held together by cohesin.

Prophase: Sister chromatids condensed further with condensin.

Metaphase: All chromosomes moved into the metaphase plate, centromeres associate with proteins to form kinetochores (monovalent or bivalent)

Anaphase: Cohesin cleaved, sister chromatids separate into different daughter cells

Telophase: Condensin cleaved -> Chromasomes no longer condensed -> Into interphase stage

30
Q

Condensin

A

Large, ring-like protein complex which induces mitotic chromatin condensation by bindin to the chromatid to condense it even further. Required for the formation of M phase chromosomes.

31
Q

Monovalent attachment

A

Only one side of the centromere gets attached to the mitotic spindle

32
Q

Bivalent attachment

A

Both sides of the centromere attaches to the mitotic spindle

33
Q

Which mechanism allows the sister chromatids to segregate during the anaphase? What makes the chromosomes return to the interphase structure in the telophase?

A

Proteolysis of cohesins allows segregation of sister chromatids. Proteolysis of condensins leads to interphase chromosomes in telophase by reversing the compaction from the preparation in prophase.

34
Q

What happens in the scenarios where a chromosome has 0, 1 or 2 centromeres?

A

0 centromere: If there is no centromere on a chromosome, there is no option for the microtubules to attach, leading to random segregation of the chromosome.

1 centromere: Normal, ideal scenario. The result is one chromosome in each daughter cell.

2 centromeres: A mutation causing two centromeres leads to the mitotic spindle attaching to both centromere locations on the chromosome, leading to chromosome breakage.

35
Q

What kind of attachment with the kinetochore happens during the meiosis?

A

Meiosis I: Monovalent attachment with the kinetochore -> One (random) chromosome (consisting of two copies) gets pulled into each cell.

Meiosis II: Bivalent attachment with the kinetochore -> The mitotic spindle attaches to each of the copies on a duplicated chromosome, pulling each chromosome copy into a haploid daughter cell. The result is 4 haploid cells with halved chromosome number and unduplicated chromosomes.

36
Q

What are the 4 different things/mechanisms that can regulate and influence chromatin structure? (only names)

A

Histone variants

Nucleosome remodeling

Nucleosome positioning

Histone PTMs (acetylation, methylation)

37
Q

Histone variants (incl. example)

A

Non-canonical histones that can be exchanged for our regular, canonical histones (H2A, H2B, H3 or H4), hereby creating alternative nucleosomes with specialized functions. An example of a variant is CENP-A, which is a histone H3 variant. Can be found in both euchromatin and heterochromatin.

38
Q

Canonical histones

A

H2A, H2B, H3 and H4 (also known as core histones)

39
Q

What’s the difference in the regulation of canonical histones and histone variants?

A

Canonical histones are tightly regulated in their expression during the cell cycle. They are only deposited onto DNA in a process that is strictly coupled to DNA replication during S-phase.

Histone variants are expressed throughout the cell cycle, and can be added to the nucleosomes at any time. They can both be deposited during and after S-phase.

40
Q

CENP-A

A

A histone H3 variant with an extended N-terminal tail that gets incorporated in nucleosomes at the centromere. CENP-A interacts with microtubules in kinetochore proteins and are very important for the separation of chromosomes during mitosis. (loss of CENP-A hinders the association of kinetochore components with centromere DNA).

41
Q

Nucleosome remodeling complexes (3 types + explanation of mechanism)

A

Alter the position of / mobilizes nucleosomes and increase the accessibility of DNA incorporated into nucleosomes. Three possible actions to achieve this:

  • Sliding: .. of the histone octamer along the DNA
  • Ejection: Complete release of the histone octamer from the DNA
  • Dimer exchange: Facilitate the exchange of H2A/H2B dimers

There are many different complexes which prefer different types of action of the nucleosomes.

42
Q

Sliding

A

A process in which remodeling complexes use ATPase enzymes to move nucleosomes to new positions, usually with the purpose of making a protein binding site on the nucleosome slide out of the compaction and become accessible. Translocase domain binds to the DNA molecule and displaces it, pulling DNA from the linker region into the nucleosome (more details on PP).

43
Q

Ejection

A

A process in which remodeling complexes eject histones from nucleosomes, leaving open and accessible regions.

44
Q

Dimer exchange

A

A process in which remodeling complexes facilitating incorporation of histone variants, for example by taking out H3 and adding CENP-A.

45
Q

Nucleosome positioning

A

A dynamic process which indicates where nucleosomes are located with respect to the genomic DNA sequence, and whether genes are located tightly packed inside a nucleosome (hard to access) or outside of a nucleosome / on linker DNA (easily accessible). As a consequence of this kind of positioning, accessibility to genes varies with the position of nucleosomes along the DNA strand.

46
Q

Positioned nucleosomes (positive or negative effect)

A

The consequence of sequence-specific DNA-binding proteins, which can have either a positive or negative effect on the accessibility of nearby DNA sequences. In a nucleosome free zone there will be an open DNA formation, and for example DNA polymerase can easily come in and initiate transcription -> Positive effect on the accessibility of DNA. A negative effect would be if a protein binds and positions the nucleosomes so that it is unable to be moved to the side, which would make a gene located in the middle area difficult to access and express.

Some sequences favor nucleosomes: AT-rich sequences, which are easily bendable (towards the minor groove). GT-rich areas are usually gene rich, and they usually don’t bind into nucleosomes because its favorable that the genes are easy to access and express.

47
Q

Post translationally modification (PTMs) of histone N-terminals (types, nomenclature, active/repressed genes) - what are the most studied types of modification?

A

Histone tails protrude out from the minor groove channels of the nucleosome and can be accessed and modified, leaving epigenetic marks. They can either be phosphorylated, methylated, acetylated or ubiquinated -> Methylated and acetylated are the most studied types.

The histone tails can be modified at several different amino acids, and there is a special nomenclature to refer to where and what kind of modification there is. For example: Histone H3 lysine 9 acetylated is written as H3K9ac, while a methylation would be H3K9me.

Different modifications are enriched at specific parts of the genome, for example H3K27 ac in active genes and H3K27me3 in repressed genes. Generally you can find a lot of di- and trimethylation in heterochromatin. A gene with a lot of H3K27ac is probably an activated enhancer.

48
Q

Histone writers

A

Enzymes that add acetylation or methylation group to a histone tail:

Histone acetyl transferases (HATs) & histone methyl transferases (HMTs)

49
Q

Histone erasers

A

Enzymes that remove a modification (acetylation or methylation group):

Histone deacetylases (HDACs) & histone demethylases (HDMs)

50
Q

Histone readers

A

Enzymes which can have different binding domains in the proteins, enabling them to bind to specific modified (or unmodified) areas of histone tails. Some examples are readers with bromodomains (acetylation), chromodomaints (methylation), and SANT domain (unmodified).

51
Q

Histone acetylation (charge of lysine, active/repressed)

A

Acetylation of histone tails is associated with regions of active gene expression and inhibits formation of the 30 nm fiber. This is caused by a change in the charge of lysine from positive to neutral. The strong binding between the DNA strand and the histones will release, with the DNA strand no longer binding tightly to the chromatin. The nucleosome structure opens up to a more open configuration.

52
Q

Histone methylation (charge of lysine, active/repressed)

A

The charge of lysine on the histone tail remains the same (positive), and the effect of methylation varies with the position of the lysines methylated. Methylation modifications are therefore found on both active and repressed genes (no general rule), for example H3K4me3 in an active gene and a H3K27me3 in a repressed gene.

53
Q

HDAC inhibitors (HDACi)

A

Histone deacetylase inhibitors restrict HDACs from removing acetyl groups, meaning that the histone tail remains neutral and the chromatin compaction remains loose. These inhibitors have been exploited in cancer treatment, where they induce activation and expression of tumor suppressor genes (which would’ve normally been made inaccessible because of HDACs removing the attached acetyl groups).

54
Q

Epigenetic memory

A

Post translationally modifications being transferred from parental DNA to daughter DNA. This is done by histone acetyl transferases (HATs) using bromodomains to bind acetylation marks, thereby acetylating neighboring nucleosomes so that both old and new nucleosomes are acetylated.

55
Q

How can histone modifications (PTMs) and nucleosome remodeling complexes work together to regulate chromatin structure?

A

Change in histone modification can lead to recruitment of nucleosome remodeling complexes, with both cooperating in order to loosen (or condense) chromatin. Example scenario: If you have a histone acetyl transferase acetylating which opens up the chromatin configuration in an area, it will be possible for DNA-binding protein 1 to bind. This leads to the recruitment of a remodeling complex, which slides the nucleosome along the DNA, enabling another DNA-binding protein (2) to bind.

Some nucleosome remodeling complexes have histone reader domains, which bind directly to acetylation modification.

56
Q

Chromatin

A

The combination of eukaryotic DNA and its associated proteins. Nucleosome as its fundamental unit.

57
Q

Why is DNA packaged with proteins? (4 reasons)

A
  • Allows it to fit into the nucleus
  • Serves to protect DNA from damage
  • Regulates accessibility -> restricts accessibility to the DNA (regulation of gene expression etc.)
  • Essential in transmission to daughter cells