genetics discussion 6 (sager sequencing, forensics) Flashcards

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1
Q

What’s the difference between pre-mRNA and mRNA?

A

Pre-mRNA = product of transcription
*which is comprised of both EXONS & INTRONS.

mRNA = After transcription pre-mRNA is SPLICED,
*which involves the REMOVE INTRONS
resulting in the formation of mRNA.

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2
Q

What information does Sanger sequencing provide?

A

tells you the ORDER OF BASE SEQUENCE of DNA

but DOES NOT provide information on
GENE FUNCTION or LOCATION

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3
Q

What are two types of information that Sanger sequencing DOES NOT provide?

A

the gene FUNCTION

the gene LOCATION

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4
Q

What would happen if only labelled dNTPs were added to the sequencing reaction?

*dNTP = deoxyribonucleotide triphosphate
made up of a 
-phosphate group, a 
- deoxyribose sugar and a 
- nitrogenous base. 
4 types dNTPs / split into two groups: 
- purines
- pyrimidines.

*The function of dNTPs in PCR
- to expand the growing DNA strand
with the help of
- Taq DNA polymerase.
The dNTPs are bind with the complementary DNA strand by hydrogen bonds.

*The PCR is an in vitro technique of DNA synthesis.

A

If only labelled dNTPs were added, the sequence wouldn’t elongate as labelled dNTPs signal to terminate the chain.

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5
Q

What would happen if multiple primers were added to the sequencing reaction?

A

= lots of pieces
and some of those pieces would be the same size.

*A single primer is used so that multiple PCR reactions
ALL START AT THE SAME POINT
and you can build up a picture of the END LETTER when you line up the pieces from SMALL TO LONG,
thus you can then read the sequence.

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6
Q

Why can’t we just look for the ATG codon to find genes?

A

We can’t just look for ATG Becuase we DON’T KNOW whether it is in place to
- START THE GENE or to simply
- CODE FOR THE AA METHIONINE
to be added to the protein chain.

*A protein chain may have many ATG sequences.

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7
Q

Why can’t genomic DNA alone be used to determine gene sequence?

A

Genomic DNA will
give BOTH INTRONS & EXONS sequences.

The FINAL GENE SEQUENCE that determines the protein
= is a product of MATURE mRNA

pre-mRNA
= CANNOT DIFFERENTIATE WHICH PART of the sequence is INTRONS & EXONS based on sequence alone

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8
Q

What must be done first before the mRNA sequence can be obtained?

A

==> “mRNA EXTRACTED FROM TISSUES”
==> then converted to cDNA (copy DNA)
*using REVERSE TRANSCRIPTASE (from viruses)
*bec..we don’t have polymerase to make copies of RNA, we do once we make DNA
==> Then we can work out the mRNA sequence
*as it will be COMPLEMENTARY to the cDNA sequence.

mRNA is first EXTRACTED FROM THE TISSUE

  • if mRNA is present==> it means the gene is being transcribed OW transcription factors are in place for transcribing that gene, the only genes being transcribed in that gene are the ones
  • specifict to that cell
  • important to that cell
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9
Q

What parameters are used to find ORFs in a DNA sequence?

*open reading frames

A

ORFs must consist of
= a START SEQUENCE “INITIATION SITE” with ATG
= an ending in a frame STOP CODON of either
- TAA
- TGA or
- TAG.

= It also must be found “IN FRAME”.

Then there must be
= SUFFICIENT CODON PRESENT BETWEEN the START codon and the STOP codon to encode for the
- USUAL SIZE OF A GENE.

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10
Q
What are 
- two reasons why a 
- disease gene can’t be found 
by comparing the cDNA sequence of a 
- diseased and 
- normal individual?
A

= only feasible when a single gene is suspected
= NOT POSSIBLE TO SEQUENCE ALL
~18,000 - 30,000 genes
in a diseased and a normal person

= MANY DIFFERENCES WOULD BE FOUND
so you could NOT DETERMINE WH IS RESPONSIBLE
*the diff could be just hair colour phenotype (blonde or brown)

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11
Q

When would a single chromosome look a cross (X)?

A

= when has been REPLICATED

  • It is a DUPLICATED HOMOLOGOUS CHROMOSOME
    with
    “2 SISTER CHROMATIDS” (X)

Occurs as a result of DNA REPLICATION
- during the cell cycle

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12
Q

When would a single chromosome look like a stick (I)?

A

= During CELL DIVISION

*the CHROMOSOMES SPLIT and become
“SINGLE SISTER CHROMATIDS” ( I )

*They now look like ‘sticks’ when shown on karyotypes.

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13
Q

How can the two chromosomes in a pair be matched up?

A

==>STAINED WITH DYE
==>reveals a pattern of lighter and darker BANDS
==> matched by BANDING PATTERN

*Each chromosome has a UNIQUE BANDING PATTERN.

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14
Q

What sort of
- DNA mutations can be seen
in a

“karyotype analysis”?

A

= LARGE SCALE GENETIC MUTATIONS
eg. trisomy 21 = extra copy of chromosome

EG…

  • PARTIAL chromosome DELETIONS
  • MISSING chromosomes
  • EXTRA COPIES of chromosomes.
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15
Q

Give two examples of chromosomal mutations able to be seen in a karyotype

A

= Down Syndrome (Trisomy 21)
*an extra chromosome at 21

= Edwards Syndrome (Trisomy 18)
*an extra chromosome at 18

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16
Q

Where would the genetic locus 11q21 be found?

A

= on chromosome 11.
= Q represents the long arm
= 21 refers to which BAND it is found on.

*chromosome 11 on the long arm of band 21.

Danilla note- some systems use the
21
= SUB band 2
= SUB SUB band 1

17
Q

Why does bacterial DNA need to be methylated?

A

= to PROTECT FROM CLEAVAGE by their own
restriction enzymes.

==> bacteria make restriction enzymes as a
DEFENCE AGAINST VIRAL DNA
(wh is not methylated)

==> bacterial DNA methylated
==> methylation PROTECTs them from
CLEAVAGE by their own restriction enzymes.
==> restriction enzymes cleave foreign DNA
(eg. non methylated viral DNA)

18
Q

Why are PCR-based methods preferred to RFLP in forensic analysis?

  • Restriction Fragment Length Polymorphism (RFLP)
    = a molecular method
    of genetic analysis
    allows individuals to be identified
    based on unique patterns of
  • restriction enzyme cutting in specific regions of DNA.
A

PCR-based methods require
= less DNA
= takes less time (than RFLP)
= less expensive.

While RFLP requires
= larger amounts of DNA
= often difficult to obtain

  • eg. DNA from a crime scene may be
  • scant or
  • partially degraded.
19
Q

Could a suspect be convicted of a crime if they have
- 1 matching microsatellite repeat

to the sample found at the crime scene?

A

No.
A suspect REQUIRES SEVERAL

= 13 satellites are required (in USA)
to make the CHANCES MINUSCULE
- of ANY 2 INDIVIDUALS matching the crime scene DNA

full mark -
= up to 20% of the population
can share that one microsatellite.

20
Q

Why is a

  • potential father with
  • several matching microsatellite repeats to the offspring

definitely the parent?

A

The chances of having a
- same SINGLE MICROSATELLITE with another person
= HIGH

but having SEVERAL MATCHING microsatellite are
= VERY LOW

With this being said the “potential father” is
MOST DEFINITELY THE PARENT