Genetics Flashcards

1
Q

Describe an unplanned or chance event that led to a major discovery in the history of early DNA research.

A

Griffith discovering that the combination of two non-lethal strains of bacteria could produce a fatal case of pneumonia in the mice
James Watson being allowed to see Rosalind Franklin’s unpublished X-ray crystallography results, enabling him to realize which of his own models was probably right

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2
Q

DNA consists of

A

wo long strands made up of repeating sequences of simple units called nucleotides (or bases). Each nucleotide is attached to a sugar and a phosphate group. The sugar and phosphate groups join together in adjacent nucleotides to form a backbone for the DNA molecule. The nucleotide sequences in the two strands run in opposite directions to each other, which is why we describe the molecule as anti-parallel.

Nucleotides consist of a nitrogen base, a five-carbon sugar (deoxyribose), and a phosphate group.

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3
Q

pyrimidine-to-pyrimidine pairings are energetically unfavourable why

A

molecules are too far apart for hydrogen bonding to be established. The opposite is true for purine-to-purine pairings, which are energetically unfavourable because the molecules are too close, leading to overlap repulsion.

AC and GT pairings are impossible because the positions of hydrogen donors and acceptors are mismatched.

The 5 and 3 carbon atoms play a role in identifying the start and end,

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4
Q

how is DNA joined

A

the deoxyribose and phosphate molecules are joined together by a covalent bond called a phosphodiester bond, which forms between the third and fifth carbon atoms of adjacent sugar rings. It is the sugar-to-phosphate linkage that forms the backbone of the DNA molecule.
The 5 and 3 carbon atoms play a role in identifying the start and end, Because the phosphate always joins at the 3’ end of the sugar as nucleotides are added, this means that the DNA strand has a direction.

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5
Q

how do you know where DNA starts

A

first nucleotide on the DNA strand has a phosphate group attached to the 5’ carbon in the sugar, so it is called the 5’ end. The last nucleotide on the strand has a hydroxyl group (OH) in the 3’ position of the sugar, so this is called the 3’ end.

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6
Q

why is dna twisted

A

bond angles between the phosphate and sugar, as well as between the nucleotides. By twisting into this shape, the molecule achieves its most stable configuration.
twist is about 3.4 nm long

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7
Q

steps of DNA extraction

A

First physically broken up to make it easier to get at the DNA. To break up the cell walls of the tissues to help release the DNA solution is added, called a lysis solution sometimes also called a buffer. The lysis mixture chemically broke up the cell and nuclear membranes to release the DNA into solution.
DNA is physically separated from the other chemicals in the solution through a filtering process.
DNA can be further purified by repeated washing with water and filtering. To wash the DNA out of the filter paper, since DNA is soluble in water The result will be a clear fluid containing water and dissolved DNA,
ideal fruit from which to isolate DNA, since they are octoploid, eight copies of their DNA

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8
Q

Used x-ray diffraction to show the helical nature of DNA

A

rosalind

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9
Q

chargaff

A

Identified that there is a one-to-one ratio between Adenine-Thymine and Cytosine-Guanine through experimentatio

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10
Q

hershey and chase

A

Used bacteriophages which are composed of DNA and protein, to show that DNA enters host bacteria after infected by bacteriophage

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11
Q

avery

A

Experiments showed that DNA not protein was the transforming agent in Pneumonococcus Bacteria and the hereditary molecule

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12
Q

griffth

A

Experiments using Pneumonococcus Bacteria showed bacteria can transfer genetic material through a process called transformation

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13
Q

levene

A

Proved that Nucleotides were composed of a phosphate-sugar-base complex and proposed the “polynucleotide” model for how DNA molecules were put together

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14
Q

miescher

A

Isolated nuclein and first to identify DNA as a distinct molecule

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15
Q

conservative model,

A

the parent, or original DNA molecule, produces an exact copy of itself but remains intact. The result is two daughter DNA molecules— one made entirely of new nucleotides, and the other composed of the same original nucleotides as the parent. However, because they are

identical copies, the nucleotide sequence is the same in each.

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16
Q

semi-conservative model,

A

arent DNA molecule splits apart, with each strand acting as a template for the newly synthesized strand. This produces two new DNA molecules, with each one containing one strand from the original parent DNA, and the other strand made up of new DNA. As in the conservative model, the nucleotide sequence is the same in each daughter DNA molecule. THIS IS IT

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17
Q

dispersive model,

A

parental DNA molecule is broken into fragments and that each daughter DNA is made up of a random mix of parental and new DNA, again with the same nucleotide sequence as the parent.

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18
Q

Meselson and Stahl experiments

A

use isotopes of nitrogen to mark new nucleotides, thus distinguishing them from the ones in the original DNA.
nitrogen as their indicator atom, because it needs to be absorbed in large quantities in order for DNA replication to occur. and ecoli reproduced quickly in culture and its biology was well understood. n14 and n15 as they both have different weights - separated out by density using a centrifuge.

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19
Q

replication in prokaryotes is much faster, why

A

Prokaryotes have circular strands of DNA and contain about a thousand times fewer nucleotides than the long, twisted strands of DNA found in eukaryotes

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20
Q

DNA replication in both eukaryotes and prokaryotes can be broken down into three main phases

A

Initiation: DNA is unwound and separated to expose each strand in the pair at multiple sites of replication along the DNA molecule.

Elongation: Enzymes attach complementary nucleotides onto the 3’ end of each exposed strand in a linear sequence and check for errors.

Termination: Nucleotide addition stops, enzymes are removed, and the newly formed strands of DNA coil back into the double helix shape.

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21
Q

Origins of Replication

A

Initiation

Multiple sites along DNA where replication begins

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22
Q

Helicase

A

Initiation

At each origin of replication point, the double-stranded DNA is unwound and separated by Helicase using ATP as energy.
“Unzips and unwinds” DNA

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23
Q

Replication Fork

A

Initiation

When the two DNA strands split apart with the help of Helicase, a two-pronged form that resembles a fork is created and is known as the replication fork.

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24
Q

Replication Bubbles

A

Initiation

When helicase opens up the DNA molecule somewhere in the middle, a bubble containing two replication forks is formed in the DNA, one on each side of the bubble and these are known as replication bubbles.

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25
Q

Topoisomerase

A

Initiation

In order to eliminate this coiling stress, topoisomerase, moves along the DNA, just ahead of the helicase, cutting the DNA and relaxing the coils.
Prevents super-coiling of a DNA molecule during replication

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26
Q

Single-stranded DNA binding proteins (SSBs)

A

Initiation

The SSBs help prevent the two template parent DNA strands from re-establishing hydrogen bonds and protect the exposed bases until they are ready to bond with their complementary nucleotides.

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27
Q

DNA Polymerase I

A

Elongation

DNA polymerase I is active mostly near the end of DNA replication, where it removes the RNA primer.

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28
Q

DNA Polymerase III

A

Elongation

DNA polymerase III is responsible for joining the nucleotides together and checking for errors.
Catalyzes the formation of the daughter strands in DNA replication
DNA Polymerase replaces the incorrect base with the correct one.

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29
Q

Deoxyribonucleoside triphosphates

dNTP

A

Elongation

dNTP’s are the nucleotides adenine, thymine, guanine and cytosine with two extra end phosphate groups on each nucleotide that form dATP, dTTP, dGTP and dCTP respectively that provide energy required for the formation of DNA.

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30
Q

Primase

A

Elongation

Helps to form RNA primer

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31
Q

RNA Primer

A

Elongation

A starting sequence of nucleotides for DNA polymerase III to attach to formed from RNA with the help of primase

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32
Q

Leading Strand

A

Elongation

DNA polymerase III continuously adds nucleotides, starting from the initial RNA primer in a 5’ to 3’ direction

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33
Q

Lagging Strand

A

Elongation

The lagging strand is synthesized discontinuously in short fragments in the opposite direction to the leading strand (that is, away from the fork) with the use of many RNA primers and the formation of Okazaki fragments and DNA ligase.

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34
Q

Okazaki Fragments

A

Elongation

DNA fragments about 100 nucleotides long that are formed on the lagging strand between RNA primers. All Okazaki fragments are eventually joined together by the enzyme DNA ligase.

35
Q

DNA Ligase

A

Elongation

Adjacent Okazaki fragments are joined together using the enzyme called DNA ligase.

36
Q

Proofreading

A

Elongation

DNA polymerase III is responsible for joining the nucleotides together and checking for errors.

37
Q

Telomeres

A

Termination

Telomeres are found at the end of DNA where primers are removed after DNA replication. In humans the sequence is TTAGGG

38
Q

Telomerase

A

Termination

The enzyme that helps to form telomeres at the end of DNA molecules after the RNA primers have been removed.

39
Q

Hydrogen bonds are quite weak compared to covalent bonds. Explain why this fact is actually advantageous to DNA in its role as the hereditary material in cells.

A

This is an advantage because it allows these bonds to be easily broken, thus facilitating the process of DNA replication. In order for DNA replication to occur, helicase must break the hydrogen bonds formed between nitrogenous bases.

40
Q

DNA replication occurs in virtually all cells, prior to cell division. Why is DNA replication essential?

A

DNA replication is essential because it preserves the genetic information from generation to generation, in each new daughter cell. This includes the information for an organism’s genes, growth, repair, and reproduction.

41
Q

single stranded binding proteins

A

Holds the parental DNA strand apart, preventing rebinding

42
Q

What role do telomeres play in aging?

A

Telomeres protect the genetic information near the ends of a DNA molecule. With each replication, short segments of them break off, resulting in the telomeres getting shorter over time. This sets a limit to how many times a cell can divide because, at some point, the telomeres get too short and DNA replication stops. When this happens, the cell dies. Cells with longer telomeres live longer.

43
Q

Protein synthesis

A

process by which the genetic code in the DNA is decoded through different kinds of RNA into amino acids and eventually, proteins.

follows one-way sequence from DNA to protein
DNA >(TRANSCRIPT)>RNA>(TRANSLATION)>PROTEIN called central dogma

44
Q

transcription stage.

A

starts in the nucleus and ends in the cytoplasm. The section of DNA where the gene is being expressed is unwound, in order to give messenger RNA (mRNA) access to transcribe (copy) it.
Phase 1: Initiation of mRNA transcription - begins when RNA polymerase binds to the DNA at the promoter region. transcription factors need to bind

Phase 2: Elongation of mRNA

Phase 3: Termination of mRNA transcription

45
Q

translation

A

mRNA with genetic info leaves nucleas DNA stays behind. mRNA enters cytoplasm and attaches to ribosomes which provide a site where tRNA translates mRNA code into a polypeptide chain which is then release and folded into a protein. Ribosomes, tRNA and mRNA are reused for other proteins

Phase 1: Initiation

Phase 2: Elongation (making the polypeptide)

Phase 3: Termination

46
Q

In a sentence, explain the one gene-one polypeptide hypothesis and describe one example of evidence that supports the hypothesis.

A

The one gene-one polypeptide hypothesis says that one gene is responsible for producing one polypeptide.
each mutation in a gene corresponded to a change in only one amino acid.
hemoglobin valine substitution for sickle cell

47
Q

Explain why a codon that is two nucleotides long would be unable to code for all 20 amino acids.

A

Because there are only four nucleotide bases, a codon that is two nucleotides long could only code for a maximum of 4 × 4 = 16 amino acids. This is less than the 20 needed.

48
Q

Because there are only four nucleotide bases, a codon that is two nucleotides long could only code for a maximum of 4 × 4 = 16 amino acids. This is less than the 20 needed.

A

A main reason is that the cytoplasm is a very dangerous place for DNA molecules. There are lots of enzymes and chemicals floating around that could permanently damage the DNA molecules and so destroy the recipe needed to keep the cell alive. That is why eukaryotic DNA is kept safely stored in the nucleus, protected by the nuclear membrane. RNA works like a temporary and throw-away copy of the DNA.

49
Q

operon

A

group of genes under the control of a single regulatory protein. The result is that the genes contained in the operon are either expressed together or not at all.
primarily in prokaryotes but some have been found in the euks

two regions: control (promoter (Plac) and an operator (O)) and coding.

50
Q

Operons can operate using negative or positive regulation.

A

Negative regulation involves the binding of a regulatory protein (“repressor”) to the operator to prevent transcription.
Positive regulation involves the binding of a regulatory protein (“activator”) to an area close to the promoter region to stimulate transcription. The lac operon shows both types of regulation.

51
Q

Translational level

Regulatory proteins

A

cytoplasm can bind near the 5’ cap of an mRNA transcript.

once the polypeptide is released from the ribosome, it can be modified by chaperone proteins.

52
Q

What are transcription factors, and what is their role in protein synthesis in eukaryotes

A

Before transcription can begin in eukaryotes, a protein called an initiation factor binds to the promoter region. This facilitates the binding of other transcription factors that stabilize the RNA polymerase to help it bind to the correct starting codon on the mRNA transcript. The transcription factors can either inhibit or stimulate the transcription process.

53
Q

Describe one example of positive regulation in an operon.

A

When glucose levels are low in a cell, an activator protein will bind to a site close to the promoter (Plac) region on the lac operon. This makes it easier for the RNA polymerase to bind to the promoter so that the lac genes will be transcribed at a higher rate, which will ultimately result in more glucose for the cell.

54
Q

Example of negative regulation

A

o save energy, E. coli will not produce the lactase enzymes unless the sugar, lactose, is present in the cells’ environment.
repressor protein (lacl) attaches to the operator region, preventing the binding of RNA polymerase to the DNA strand.
actose is present, the repressor protein lacl releases itself, allowing RNA polymerase to bind and turn on the lac operon.

55
Q

somatic cell mutations

A

Mutations that occur only in the body cell

only affect that individual.

56
Q

germ cell mutations.

A

When mutations occur in the sex cells, they have the potential to be passed on to the next generation.
sickle-cell anemia, hemophilia,

57
Q

two classes of mutations:

A

Gene-level mutations: mistakes in the base-pair sequence of genes
Chromosome-level mutations: are mistakes in the arrangement or number of genes on a chromosome.

58
Q

Point Mutations gene level

A

Silent
Missense
Nonsense mutations

59
Q

silent mutation

A

mutation in one nucleotide, but because of the redundancy of the genetic code, there is no change of amino acid. As a result, there is no effect on the resulting polypeptide.

60
Q

missense mutation

A

occurs when a nucleotide substitution results in the replacement of one amino acid in the polypeptide chain. Even changing one amino acid can have drastic effects on the structure of the polypeptide (as you saw in the example of sickle-cell anemia ß-hemoglobin

61
Q

nonsense mutation

A

nucleotide substitution results in an amino acid codon changing to a STOP codon.

polypeptide would be too short

62
Q

Frameshift Mutations

A

insertion of a nucleotide -Adding a single nucleotide to the sequence can result in a frameshift mutation.

deletion of a nucleotide- Removing a single nucleotide from the sequence can also result in a frameshift mutation.

63
Q

Chromosome-level mutations

A

Translocation-relocation of groups of base pairs from one part of the chromosome to the other. - mitosis

Inversion-segment on the chromosome is cut out, and then turned around and reinserted backwards. meiosis

64
Q

difference between RNA and DNA

A

dna - deoxyribose - one OH
replicates and stores genetic information.
DNA consists of two strands, arranged in a double helix
DNA is a much longer polymer than RNA
DNA is found in the nucleus
DNA is vulnerable to damage by ultraviolet light.

RNA, - ribose - 2 OH
converts the genetic information to build proteins
RNA only has one strand, but like DNA,
forms in the nucleolus, and then moves to cytoplasm
RNA is more resistant to damage from UV light than DNA.

65
Q

The Barcode of Life Project

A

tool of genetic sequencing is being used for biodiversity conservation.
a DNA-based identification system that can catalogue all species on earth using these barcodes

66
Q

Two (or more) benefits of DNA barcoding

Two potential drawbacks of barcoding

A
  • Fast
  • Inexpensive
  • It doesn’t yet work for all types of species, especially plants.
  • Some worry that it will reduce the recruitment and training of scientific experts in taxonomy and other biological fields.
67
Q

From the timeline, what are three key developments in the history of biotechnology that directly relate to the DNA barcoding project?

A

Discovery of the structure of DNA (1953), electrophoresis (1959), PCR (1984)

68
Q

Extracting DNA

A

Break open the cell - lysis centrifuge

The lipid-rich membranes are torn apart, using a detergent. Most laboratories use the detergent sodium dodecyl sulphate (SDS)

DNA mixes with the cytoplasm. The enzymes present in the cytoplasm can quickly degrade the DNA. Many labs add a protease (an enzyme that degrades proteins) to the mixture, to destroy the enzymes. cold mix

DNA can be separated using a water filtration process or it can be extracted out of solution, using alcohol

69
Q

restriction endonuclease

A

genes can be cut from the chromosome

70
Q

sticky ends,

A

allow the fragment to join with other DNA that has also been cut by the same RE. The result is that the DNA fragments can be joined together—even with DNA from different species—to form new DNA called recombinant DNA.

71
Q

Electrophoresis

A

Negatively charged DNA molecules are forced to pass through a gelatin-like material called agarose, which slows them down. The negatively charged molecules are pulled towards the positively charged end of the agarose gel. The larger molecules get blocked more easily, so they move through the gel more slowly. Smaller molecules can avoid some obstacles, so they move through the gel more rapidly.
. The result is that the different sizes of DNA molecules are spread out across the gel in stripes or bands

72
Q

DNA ladder IN ELECTROPHORESIS

A

adder is a solution made up of a variety of DNA fragments of known length

LIKE A RULER representing DNA fragments of known size

73
Q

Amplification

A

PCR - amplifying a particular sequence of DNA selected by the researcher

The vial is then heated to 94°C, which causes the two coiled DNA strands to unravel and separate (denature). As you learned earlier, in normal DNA replication, this unravelling and separation of the DNA strands is done using the enzymes helicase and topoisomerase.
The temperature is then lowered to 60°C, which allows the primer to bind to the template DNA strand at the correct location. This is called the annealing temperature, because the primer anneals (binds) to the DNA.
The temperature is then raised to 72°C, which is the optimal temperature for the Taq polymerase to start adding DNA nucleotides at the 3’ end of the template strand. This elongation process is completed in a few minutes and the result is a doubling of the target DNA in the sample.

74
Q

Taq polymerase that makes PCR possible.

A

its optimal activity occurs at a high temperature (around 72°C)

75
Q

chain termination sequencing

A

The process of chain termination sequencing results in the creation of many short segments

76
Q

Dideoxynucleotide triphosphates (ddNTPs) as DNA chain terminators.

A

use of dideoxynucleotide triphosphates (ddNTPs) as DNA chain terminators. The ddNTPs are like regular nucleotides, except that they don’t have a 3’-OH bonding site for the next incoming phosphate group. This means that no other nucleotide can bind to them, so the elongation process of the DNA strand stops immediately after they are added.

77
Q

Recombinant DNA

A

take individual genes from one genome and insert them into another genome
Insulin

78
Q

What is the role of restriction enzymes in the process of making recombinant DNA?

A

Restriction enzymes are designed to cut the DNA at particular locations. They are like “molecular scissors” that can be designed to cut out specific genes or fragments of genes.

79
Q

plasmids

A

small circular ribbons of DNA that can move between bacteria
separate from the chromosomal DNA but are also used by the bacteria to code for proteins.

it is cut open from ecoli and sections of DNA with all sticky ends from euks, join them - called a vector
genes not normally found in the plasmid can be inserted into it to create a recombinant plasmid
The recombinant plasmid vector is then placed in a culture medium where the bacterium takes in the plasmid.
When the bacterium undergoes replication, the plasmid DNA is copied, along with the cell’s chromosomal DNA.

80
Q

transgene issues in canada

A

anti-freeze gene from the flounder, a cold-water fish, into strains of strawberries and oranges to help them tolerate freezing
people with seafood allergies couldnt eat the food

81
Q

intorn

A

noncoding sections of an RNA transcript,

82
Q

exon

A

sections of DNA (or RNA) that code for proteins
serve as hot spots for recombination in the formation of new combinations of exons

covalently bonded to one another in order to create mature mRNA

83
Q

Spliceosomes

A

multimegadalton RNA–protein complexes

esponsible for the faithful removal of noncoding segments (introns) from pre-messenger RNAs