genetic variation and analysis Flashcards

1
Q

population genetics

A

investigates genetic variation among individuals within and between groups
genetic basis for evolutionary change
how patterns vary geographically over time
applicable to all kinds of populations

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2
Q

human populations

A

demographic structure
genetic structure- genes that we possess
constitution- how many alleles are in the population + how the genes are passed on
continuing entity

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3
Q

genomic variation

A

mutations are pimary source- dna sequence/genes/repeat size/chromosome numbers
genetic variability is the raw material upon which natural selection operates
can occur at all levels- from micro- change in one letter of dna sequence
locus- location of dna sequence/ gene in genome
allele- different forms of same gene or dna sequence

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4
Q

specific loci

A

ABO locus- A, B, O alleles- has 4 phenotypes and 6 genotypes
A,B codominant, O is recessive
beta hb locus- S,C,C
SNP locus- A + G or C+T - or any combination
repeat loci-2-2 or 3-4 repeats- alu, II,ID,DD
insertion deletion

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5
Q

genetic constitutions

A

a pool of genes/alleles at any one time
can be specified in the form of allele frequencies
allows comparison- uni dimensional (one population), multidimensional (different population groups/ethnicities)
admixture- when 2 populations mix, offspring will have genetic makeup of mixture of migrating and receiving populations

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6
Q

genetic structure

A

the way alleles are distributed and combined with populations
human populations are heterogenerous
barriers to breeding/mating- cultural, religion or social
subdivisions affect distribution of genes within populations, lead to consequences –> divergence, fixation of genes at a locus, increased homozygosity

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7
Q

maintenance of genetic variation

A

errors in dna replicationa are not always repaired by the mechanisms - leads to mutations
some alleles may not be independently assorted
haploid gametes- crossing over (variation)

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8
Q

allele frequency calcs

A

SNPs, alu, STRs
eg 2 alleles I and D
homozygotes and heterozygotes
- I allele = (2 Homozygotes) + Heterozygotes/ 2*N
*1st allele = p, 2nd allele= q
if there are 2 alleles then p+q=1
any numbers of alleles, formula should work and still add up to 1)

polymorphisms will usually have 2 polymorphisms- insertion and deletion allele

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9
Q

SE of allele frequency

A

allows evaluation of range and calculation of CI
SE and SD are the same for allele frequencies
√p x(1-p) / 2xN
p= allele of interest
N= no. of individuals in study
small samples have larger SE
for 2 allele systems (alu/snps)- SE same for both alleles
STRs- multialleic systems- each allele has separate SE
SE low is good

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10
Q

heterozygosity

A

how many heterozygotes are in a population
observed heterozygosisy- frequency of the heterozygotes - h=nh/N
Where nh is the number of heterozygote individuals and N is the total number of individuals studied/analysed
expected heterozygosity= H=1-sum of p^2
p= allele freqency,

1- exp homozygosity= expected heterozygosity

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11
Q

HWE

A

in a large random mating population, allele and genotype frequencies do not change from 1 generation to next
assumptions
- random mating
- infinite population size
- no mutation or selection
- no migration
cant be used for humans
formula- (p+q)2 = p2+2pq+q2

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12
Q

how and why do we test hwe

A

tested within the population
null hyp= there is no difference between observed and expected genotype frequencies
population maintains hwe or population does not show departure/deviation from hwe

  1. calculate allele frequencies
  2. work out expected genotype frequencies
  3. work out expected genotype numbers
  4. use chi2 to test null hypothesis
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13
Q

HWE explained

A

HWE is calculated for each locus and each population
if not maintained, assumptions causing changes to allele frequencies need evaluation
could be due to selection, gene flow + migration, inbreeding, genetic drift and founder effect, mutation

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14
Q

genetic differences between populations

A

multiple usages (group comparisons/case control disease analyses)
categorical data
simple solution- compare genotype and allele frequencies using descriptive methods

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15
Q

statistical comparisons

A

using rxc contigency chi square methods (multidimensional chi square)
organise data into columns + rows, work out totals
work out expected numbers from observed data and work out chi2 for whole table
- expected number = (row totoal * column total)/grand total
- work out expected values for each cell – work it out individually
- degrees of Freedom = (Number of Columns -1) * (No of Rows -1)

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16
Q

quantifying genetic differences - Fst Gst statistic

A

variation within sub population is high- variation between sub population is zero= Fst = 0
cannot predict which sub pop an individual will belong to

variation within sub pop is low (0)- variation between sub population is maximised= Fst=1
can predict which sub population an individual belongs to

17
Q

gene diversity analysis

A

based on:
Hs= average heterozygosity
Ht= heterozygosity of total population
Dst= Ht-Hs
Gst= (Ht-Hs)/Ht
coefficient of gene differentiation
high Gst values are indicative of higher differentiation (inbreeding and isolation)=

18
Q

genetic distance

A

degree of relationship by descent between 2 individuals/ populations
difference between populations are multidimensional- difficult to describe descriptively
many measures available
different assumptions and conmputational requirements
allows construction of trees- dendrograms

19
Q

neils d

A

one of the simplest genetic distance measures, probability that a random chosen allele from each of the two populations will be identical, relative to the probability that 2 randomly chosen alleles from the same population will be identical

20
Q

neils d calculation

A

D = - ln I
where I = [Σxiyi / (Σxi2 Σyi2)0.5 ]
in is natural log

assumptions
- infinite allele model 
- all loci have same rate of neutral mutation 
- mutation- genetic drift equilibrium and stable effective population size