Genetic Counseling and Risk Flashcards

1
Q

In what ways are genetic conditions different from other medical conditions?

A
  • Predicting future health
  • Invasion of privacy
  • Life and death issues faced in prenatal decisions
  • Potential discrimination
  • Effect/risk to other family members

- Lack of treatment/interventions*

Genetic conditions are not always inherited (some occur de novo)

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2
Q

What is genetic counseling/what are the goals?

A

Communication process which deals with the human problems associated with the occurrence of risk of a genetic disorder in a family. Goals are to help the individual or family to:

  • Comprehend medical facts
  • Appreciate the way heredity contributes to the disorder and the risk of recurrence in specified relatives
  • Understand options for dealing with risk of recurrence
  • Choose a course of action which seems to them appropriate in view of their risk, their family goals, and their ethical and religious standards
  • To make the best possible adjustment to the disorder in an affected family member and/or to the risk of recurrence of that disorder
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3
Q

What are indications for genetic counseling?

A
  • Questions of diagnosis, cause, and prognosis of heritable or developmental disorders
  • Questions of disease risk for family members
  • Questions of the risk for a genetic disease in an expected or future child
  • Discussions of options of prenatal testing for certain genetic disorders
  • Discussions about and performance of predictive molecular genetic testing (e.g., for cancer disposition syndromes or for late manifesting heritable diseases such as Huntington disease)
  • Questions of management and anticipatory guidance for heritable disorders or disease susceptibility
  • Clarification and advice about:
  • Infertility or recurrent miscarriages
  • Advanced maternal or paternal age
  • Assisted reproductive therapy
  • Marriage between relatives (consanguinity)
  • Exposure to teratogens before or during pregnancy
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4
Q

What are some reasons for referral to genetic counseling?

A
  • Prenatal
  • ART, Male or Female Infertility
  • Pediatric: Abnormal newborn screening results, child with birth defect, neurologic disorders, ID/DD, FTT, short statures, autism spectrum disorders, hearing loss, vision loss
  • Cancer: Individuals with a personal or family history of cancer (especially those with multiple affected family members and cancer at unusually young ages)
  • Metabolic: diagnosis, treatment and follow-up for IEMs, couples who have had children died of SIDS or SUDC
  • Neurogenetics: Patients with suspected or known neurogenetic conditions or with a family history of hereditary neurogenetics condition (i.e., DMD, ALS, HD,)
  • Hematology: Individuals who have a diagnosis or family history of a hematologic condition (i.e., sickle cell, Fanconi anemia)
  • CV genetics: Suspected or known hereditary cardiovascular disease or with a family history of hereditary cardiovascular disease (i.e., Long QT, Marfan, HCM, sudden cardiac death under 50yo)
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5
Q

What is the structure of a genetic counseling visit?

A

Information, education; “Talking”:

  • Information gathering
  • Information giving
  • Communication of Risk

Counseling, support; “Listening”:

  • Psychosocial assessment and counseling
  • Help with decision making
  • Ongoing client support
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6
Q

What are some key points regarding communication of risk in genetics counseling?

A
  • Risk communication is an integral part of genetic counseling
  • Help an individual make a choice about whether or not to undergo testing
  • Help individuals and families adjust to the knowledge that an event has occurred.
  • People’s perception of the magnitude of risk are influenced by factors other than numerical data
  • Terms such as risk, chance, possibility, or probability also imply value judgments (e.g., risk = bad, chance = good), which may be perceived differently by different individuals
  • 1/800 sounds higher than 1/400 since denominator is higher
  • Use of nonnumeric phrases (often, rarely, never) introduces potential risk for bias
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7
Q

What are the best practices to use when communicating risk?

A
  • Provide risk in several ways
  • Provide likelihood of a negative outcome balanced by the likelihood of a positive outcome
  • Use visuals to emphasize key points
  • Use risk comparisons to help put risks in perspectives
  • Abstractions: use examples, stories, analogies
  • Fractions, percent
  • If risk is unclear, give a range
  • Assess patient’s perception of risk – more meaningful than the actual risk
  • Define technical terms, use words the patient is familiar with
  • Be cautious of nonverbal messages
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8
Q

What are some counseling skills/behaviors?

A
  • Sit if possible
  • Effective listening
  • Promote shared language
  • Silence
  • Rephrasing: stating in your own words what the pt has said
  • Reflecting: repeating the last phrase of a client’s statement in the form of a question
  • Redirecting: used to manage the rate of information exchange
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9
Q

What are the different types of responses you may get?

A
  • Factual responses
  • Aggressive/hostile response (“counterattack”; by patient)
  • Reassuring response (by doctor; but don’t do before concerns are heard)
  • Empathetic response
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10
Q

What are some common pitfalls made be doctors in counseling?

A
  • Wanting to be liked
  • Asking too many closed-ended questions
  • Reluctance to control the agenda
  • Avoiding emotionally charged issues
  • Bringing your own agenda/biases into the session
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11
Q

What are some themes in genetic counseling?

A
  • Non-directive
  • Autonomy
  • Informed Consent
  • Confidentiality
  • Beneficence (non-maleficence)
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12
Q

What are different methods of risk assessment

A

Straight forward risk assessment, use:

  • Inheritance/pedigree analysis to estimate risk
  • Hardy-Weinberg to estimate risk
  • Genotype to estimate risk

Not as straight forward:

  • Recurrence risks can be more difficult to assess if inheritance patterns are affected variable expression, reduced penetrance, under 100% sensitivity of molecular testing, new mutations
  • Use Bayesian analysis
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13
Q

What are some inheritance patterns?

  • Single gene inheritance
  • Non-traditional inheritance patterns
A

Single gene inheritance

  • Autosomal dominant
  • Expressivity and penetrance
  • Autosomal recessive
  • X-linked

Non-traditional inheritance patterns

  • Multifactorial
  • Mitochondrial
  • Trinucleotide repeat
  • Uniparental disomy
  • X-inactivation
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14
Q

What is the Hardy Weinberg Law?

  • Assumptions
A
  • Genotypes are distributed in proportion to the frequencies of the individual alleles in a population and remain constant from generation to generation if the population is at equilibrium
  • Using genotypes, can calculate allele frequencies

- Assumptions:

  1. Random mating
  2. No selection
  3. No new mutations
  4. Population is infinitely large
  5. No migration
    - If these assumptions are nearly correct, the locus is said to be in Hardy Weinberg equilibrium
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15
Q

How to calculate allele frequency

Ex) MN blood group system genotypes (M/M, M/N, N/N)

  • What is frequency of M allele? N? (pic 496 )
A
  • Multiply number of individuals with M/M genotype by 2 since each individual has 2 M alleles.
  • Similarly, multiply total number of individuals in population by 2 since each individual has 2 alleles/chromosomes
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16
Q

What is the Hardy Weinberg equation?

  • What do the variables stand for?
  • For A/a autosomal dominant alleles, how do you calculate frequency of AA? Aa? aa?
A
17
Q

Calculate the frequency of M/M, M/N, and N/N genotypes for the past example

A

How closely the numbers calculate match the genotype counting method determines whether the population is at equilibrium

18
Q

How can you use HW with more than 2 alleles?

A

If there are more than 2 alleles at the same locus: (p + q + r + …)^2 where each letter represents the frequency of each allele

19
Q

Ex) Calculate ABO blood group genotype frequencies (A/A, A/O, A/B, B/B, B/O, and O/O); what percentage should be blood group A?

  • A = 0.30 (p)
  • B = 0.10 (q)
  • O = 0.60 (r)
A
  • A = 0.30 (p)
  • B = 0.10 (q)
  • O = 0.60 (r)

Thus: (p + q + r)^2 = 1

Individuals who are phenotype A can be genotypes A/A or A/O

  • Therefore, the incidence of the A blood group equals: p^2 + 2pr = (0.30)^2 + 2(0.30)(0.60) = 0.45
20
Q

Look at this analysis of the HW equation for an autosomal dominant trait

A
21
Q

If the incidence of the Huntington disease is 1/10,000 (an autosomal dominant disease), what is the frequency of the HD gene?

A

Incidence of disease = 2pq = 1/10,000 q = 1/2(1/10,000) = 1/20,000

  • Therefore, for AD traits, the frequency of the mutant gene is equal to 1/2 the incidence of the trait
  • The ½ is from alleles in heterozygotes are HD gene with frequency q
22
Q

Look at this analysis of the HW equation for an autosomal recessive trait

A
23
Q

Cystic fibrosis affects approximately 1/2,500 non-Jewish, Caucasians in the US. What is the frequency of the CF gene and what is the frequency of heterozygotes (CF carriers)?

A
  • For rare recessive traits (incidence under 1/10,000), p, the frequency of the normal allele is very close to one and the carrier frequency equals 2q.
  • Therefore, for AR traits, the frequency of the mutant allele is the square root of the incidence (q2) and the carrier frequency is 2q(1-q) or 2q for rare traits.
24
Q

What is the equation for X-linked traits:

  • Males
  • Females
A
25
Q

Example: X-linked trait

  • The incidence of an X-linked trait is 1/40
  • What is the frequency of female unaffected carriers?
  • How many females will be affected?
A
  • Incidence of the trait in males = q = 1/40 = the frequency of disease gene
  • Frequency of female carriers = 2pq = 2(1/40)(39/40) ~ 1/20
  • Frequency of affected females = q2 = (1/40)2 = 1/1600
26
Q

What is Bayes Theorem/Bayesian analysis? When is it used?

  • What different probabilities are considered?
A

Used to adjust a person’s prior risk by taking into account further information (the conditional risk) to provide a modified posterior risk.

- PRIOR probability = probability of an even BEFORE taking additional information into account

- CONDITIONAL probability = the chance of someone occurring, assuming that each even is true

- JOINT probability = Prior probability x Conditional probability

- POSTERIOR probability = probability of the even after taking into account addtl information

27
Q

Example risk calculation using Bayesian Analysis for the following:

  • Prior probability
  • Conditional probability
  • Joint probability
  • Posterior probability
A
28
Q

Example of Bayesian analysis:

  • Mary wants to know if she is a carrier of DMD
  • Mary is the daughter of an obligate carrier (both her maternal uncle and brother have DMD)
  • Mary has 4 sons, all are healthy
A
  • Prior probability for situation A (carrier) and situation B (no carrier). The probability for each of these situations is 1/2. The two events are mutually exclusive; therefore, their sum is 1/2 + 1/2 = 1.
  • The conditional probability that four sons of a carrier are healthy is (1/2)4 = 1/16 (with a probability of 15/16 that at least one of the sons would have been affected).
  • Since the various pregnancies represent mutually independent events, the multiplication rule is applied. In the case that person B is not a carrier for muscular dystrophy, she would only have healthy sons. The conditional probability in this case is 1.
  • All this information is taken into account in the calculation according to the Bayes theorem as shown in Table 14.2. This results in an posterior probability of approximately 1/17 for situation A that she is a carrier, and in an posterior probability of 16/17 that she is not a carrier. This example demonstrates the considerable change in risk figures once all relevant information is taken into account.
29
Q

Example: Bayes + Hardy Weinberg The Potters have 2 healthy children. Mrs. Potter has found out that her niece has CF.

  • What is the risk for this couple to have a 3rd child with CF?
A

1/2 since at least 1 of her parents is an obligate carrier

30
Q

Example: Bayes + Hardy Weinberg The Potters have 2 healthy children. Mrs. Potter has found out that her niece has CF.

  • What is the chance that Mr. Potter is a CF carrier?
A
  • He has no relatives with CF, so his carrier risk is the same as the general population risk.
  • The incidence of CF in the general population (q2) = 1/2500
  • The allele frequency (q) = 1/(√2500) = 1/50
  • The carrier frequency (2q) = 1/25
31
Q

Example: Bayes + Hardy Weinberg The Potters have 2 healthy children. Mrs. Potter has found out that her niece has CF.

  • What is the probability that they have an affected child without taking into account their healthy children?
A
  • The chance that BOTH are carriers = ½ x 1/25 = 1/50
  • The chance that BOTH are carriers and have an affected child = ½ x ½ x 1/25 x ½ = 1/200
32
Q

Example: Bayes + Hardy Weinberg The Potters have 2 healthy children. Mrs. Potter has found out that her niece has CF.

  • What is the probability that they have an affected child if the healthy children are taken into consideration?
A

Use BAYES!

  • The chance that BOTH parents are carriers is about 1/88
  • Therefore, the chance to have a future child with CF is about 1/350 (0.3%)