General things Flashcards
recurring and terminating decimals
recurring decimals have one digit or a group of digits repeated forever
terminating decimals can be written exactly
How do you prove something can be written as a recurring or terminating decimal?
terminating: denominator of the simplified fraction has prime factors of 2 and 5
make the fraction over 10/1000 and convert to a decimal
recurring: simplified fraction has prime factors of its denominator other than 2 or 5
a) Show that 7/50 can be written as a terminating decimal
b) Show that 11/24 cannot be written as a terminating decimal
c) Show that 2/9 is equal to 0.222…
d) Hence, or otherwise, write 0.7222… as a fraction
a) 7/50 = 14/100 = 0.14
b) 11/24 = 11/2[3] x 3
denominator contains a factor other than 2 or 5 so decimal is recurring
c) (division) 2/9 = 0.222…
d) 0.7222 = 0.222… + 0.5
= 2/9 + 1/2
= 4/18 + 9/18 = 13/18
Do you round significant figures?
yes
Use the information below to find an appropriate degree of accuracy for the measurements.
Justify your answer
UB: 7.2618… cm
LB: 6.59963… cm
UB: 7.2… rounds to 7 (1 s.f.)
LB: 6.5… rounds to 7 (1 s.f.)
7 cm
counting strategies to find total number of possible combinations
- systematic list (when there is a low number of possible choices)
- multiply the number of choices for each option
a) how many 3 digits combinations can be made with these numbers: 456?
b) A lock on a briefcase has 3 dials.
The 1st dial can be any letter and the last 2 can be any digit from 0 to 9.
How many different ways are there of setting the code?
a) 456 465
546 564
645 654
six
b) letters: 26
digits: 10
26 x 10 x 10 = 2600
Show that there are two different ways of solving the equation:
2y/3 + y-4/2 = 5
1) add the fractions by finding a common denominator
2y/3 + y-4/2 = 4y/6 + 3y-12/6 = 7y-12/6 then solve 7y-12/6 = 5 7y-12 = 30 7y=42 y=6
2) multiply each fraction out one at a time, while also multiplying the other fraction
2y/3 + y-4/2 = 5 (x3) 2y + 3y-12/2 = 15 (x2) 4y + 3y -12 = 30 then solve 7y-12 = 30 7y=42 y=6
How do you find the gradient of a straight line using one point and algebra?
Use this example:
a straight line of gradient 2 passes through point (3,7)
- substitute the gradient
- substitute x and y values
- solve
y = mx + c y = 2x + c
7 = 2x3 + c 7 = 6 + c c = 1
y = 2x + 1
What is the equation of a straight line in algebra?
y = mx + c
a) what do parallel lines have in common?
b) what do perpendicular lines have in common?
c) a line L passes through the points (-3,6) and (5,4).
another line, P is perpendicular to L and passes through the point (0,-7).
Work out the equation of line P
a) same gradient
b) if a line has the gradient m, any perpendicular line has the gradient:
- 1/m
(reciprocal and going the other way)
c) gradient of L: -2/8 = -1/4
gradient of P: 1/0.25 = 4
y = 4x - 7
turning point
point where directin of the curve changes
shape of cubic graphs
x[3]
down, up, then down (or the other way around)
like an s shape
lines that get closer together but never touch
asymptote
shape of reciprocal graph
y = k/x
graphs get closer to a certain line but never touch