Gamsat Flashcards
π (pi)
3.14
√ 2
1.4
√ 3
1.7
e
2.71
SUM of Interior Angles of a Polygon
S = (x - 2).180degrees
Area of Triangle
1/2 Base.Height
Circumference
2πr
Area of Circle
πr^2
Length of an Arc (*=degrees)
n/360 x 2πr
Area of Sector (Circle) (*=degrees)
1/2r^2.θ (in degrees)
or
n/360 x πr^2 (in radians)
Sphere Surface Area
4πr^2
Sphere Volume
4/3πr^3
Area of TRAPEZOID
(a + b)/2 . h
a = top length
b = bottom length
TRIG: 0 degrees…
radians = 0 sin = 0 cos = 1
TRIG: 30 degrees…
radians = π/6 sin = 1/2 cos = (√ 3)/2
TRIG: 45 degrees…
radians = π/4 sin = 1/√2 cos = 1/√2
TRIG: 60 degrees…
radians = π/3 sin = (√ 3)/2 cos = 1/2
TRIG: 90 degrees…
radians = π/2 sin = 1 cos = 0
Velocity =
Δx/t
displacement Δx / time
UNIT: m/s
Instantaneous Velocity =
assess the SLOPE of the graph @ that point in time.
the tangential line of the slope
rise/run
Acceleration =
Δv/Δt
V(final) - V(initial) / Δtime
UNIT: m/s^2
Kinematic Formula 1. (missing Δx)
V = Vi + a.t
Kinematic Formula 2. (missing a)
Δx = (Vf + Vi)/2.t
Kinematic Formula 3. (missing Vf)
Δx = Vi.t + 1/2.a.t^2
Kinematic Formula 4. (missing t)
Vf^2 = Vi^2 +2.a.Δx
Force
F = ma
Force = Mass x Acceleration
UNIT: kg.m^2 …. = N
Fn (Normal Force)…
Perpendicular force
acceleration in relation to force…
a = ΣF/m
Centripetal Acceleration…
Ac = v^2/r
Centripetal Force…
Fc = m.v^2/r
Gravitational Acceleration =
9.8m/s^2
Gravitational Force of attraction between 2 masses.
F = G.m1.m2 / r^2
Work
W = F.D .cosθ
Work = force x distance
W = m.g.h W = m.v^2/2
UNIT: Nm … = Joule
Gravitational Potential Energy
= m.g.h
Power
P = W/t
UNIT: watts (watts = Joules/sec)
Springs: Hooke’s Law …
F = -kx
Instantaneous Power =
F.V.cosθ
Momentum
Momentum = m.v
Impulse
Impulse = Δmomentum
= F.Δt
Torque
= F.r. sinθ
= force x radius x sinθ
@ Equilibrium —> ΣCCforces = ΣCforces
Density (p)
p = m/v
density (p) = mass / volume
Specific Gravity
SG = p (substance) / p (h2O)
p (h2O)
Density of water = 1g/cm^3
= 1000kg/m^3
Pressure
P = F/Area
UNIT: Pascal —> N/m^2
Buoyant Force
F(buoyant) = m.g
Archimedes Principle (in relation to Buoyant Force)
SG is equivalent to the fraction of the height of a buoyant object below the surface of the fluid.
Thus, if SG = 0.9 then 90% of the height would be immersed.
And obviously, if SG > 1 then more than 100% of the object’s height is immersed —> i.e. completely submerged!
Frequency
Frequency (f) = number of cycles / time
= per second
UNIT: Hertz
Period
Period (T) = duration of one cycle
= 1/f (INVERSE of FREQUENCY)
Electric Current (I)
I = Q/t
Current = Charge / Time
UNIT: Amperes
Ohm’s Law
re. V=…
V = I.R
Voltage = Current x Resistance
UNIT: volts
Ohm’s Law
re. R=…
R = V/I
Resistance = voltage / Current (ampere)
UNIT: ohm (Ω)
Magnification
M = -i/o
i = image distance o = object distance
*For i and o: POSITIVE value = REAL image
NEGATIVE value = VIRTUAL image
**For M: POSITIVE = erect
NEGATIVE = inverted
