Further Algebra and Functions Flashcards
How many roots can a polynomial of order n have?
n roots
How many turning points can a polynomial of order n have?
n - 1 turning points
Where α and β are roots of the quadratic equation ax² + bx + c, what does α + β equal?
α + β = -b/a
Where α and β are roots of the quadratic equation ax² + bx + c, what does αβ equal?
αβ = c/a
The roots of 2z² + 3z + 5 = 0 are α and β.
i) Find values for α + β and αβ.
ii) Form a quadratic equation with roots 2α and 2β.
iii) Do this with a different method.
i) α + β = -b/a = -3/2
αβ = c/a = 5/2
ii) 2α + 2β = 2(α + β) = 2(-3/2) = -3 2α * 2β = 4αβ = 4(5/2) = 10 Let a be 1: a = 1 b = 3 c = 10 z² + 3z + 10 = 0
iii) x = 2α α = x/2 2(x/2)² + 3(x/2) + 5 = 0 2x²/4 + 3x/2 + 5 =0 x² + 3x + 10 = 0
Where α and β and γ are roots of the cubic equation ax³ + bx² + cx +d, what does α + β + γ equal?
α + β + γ = -b/a
Where α and β and γ are roots of the cubic equation ax³ + bx² + cx +d, what does αβ + βγ + αγ equal?
αβ + βγ + αγ = c/a
Where α and β and γ are roots of the cubic equation ax³ + bx² + cx +d, what does αβγ equal?
αβγ = -d/a
If 1+2i and 3/4 are roots of the cubic 4x³ - 11x² + 26x - 15 = 0, what is the third root and why?
The third root is 1-2i because the complex conjugate of a root is also a root, unless one of the coefficients of the equation is complex.
n
Σ (1)
r=1
n
Σ (1) = n
r=1
n
Σ (r)
r=1
n
Σ (r) = 1/2 n (n+1)
r=1
n
Σ (r²)
r=1
n
Σ (r²) = 1/6 n (n+1) (2n+1)
r=1
n
Σ (r³)
r=1
n
Σ (r³) = 1/4 n² (n+1)²
r=1
Use proof by induction to show that n Σ (r) = 1/2 n (n+1) r=1 is true for all positive integers of n.
1) For n = 1 : n Σ (1) = 1 r=1 and 1/2 (1)(1+1) = 1
2) Assume true for n = k : k Σ (r) = 1/2 k (k+1) r=1
3)
k+1 k
Σ (r) = Σ (r) + (k+1) = 1/2 k (k+1) + (k+1)
r=1 r=1
1/2 k (k+1) + (k+1) = 1/2 (k (k+1) + 2(k+1)) = 1/2 (k² + 3k +2) = 1/2 (k+1)((k+1)+1)
4)
Since true for n = 1, and if true for n = k, true for n = k + 1, must be true for all n
Solving summations
1) Expand brackets and rearrange to get the expression in the form of a polynomial.
2) Split up the summation into sums of terms; e.g. 2Σ(r²).
3) Substitute the formulas.
4) Simplify.
Method of differences with 1/r(r+1)
Partial fractions 1/r(r+1) = A/r + B/r+1 1 = A(r+1) + Br 1 = Ar + A + Br Compare coefficients: A = 1 B = -1 1/r(r+1) = 1/r - 1/r+1
Method of differences Σ 1/r(r+1) = Σ 1/r - 1/r+1 = 1/1 - 1/2 \+ 1/2 - 1/3 \+ 1/3 - 1/4 + ... \+ 1/n-1 - 1/n \+ 1/n - 1/n+1 = 1 - 1/n+1 = n/n+1
Standard Maclaurin Series for sin x
sin x = x - x^3/3! + x^5/5! - … + (-1)^r x^(2r+1)/(2r+1)!
Standard Maclaurin Series for cos x
cos x = 1 - x^2/2! + x^4/4! - … + (-1)^r x^(2r)/(2r)!
Standard Maclaurin Series for e^x
e^x = 1 + x + x^2/x! + x^3/3! + … + x^r/r!
Standard Maclaurin Series for ln (1+x)
ln (1+x) = x - x^2/2 + x^3/3 - … + (-1)^(r+1) x^r/r
Standard Maclaurin Series for (1 + x)^n
(1 + x)^n = 1 + nx + n(n-1)x^2/2! + … + n(n-1)(n-2)…(n-r+1)x^r/r!