Free Energy and Phase & Chemical Equilibria Flashcards

(43 cards)

1
Q

How do you derive the equation where du can be used to determine spontaneity of a reaction? Why is this not the most helpful?

A

ds>=dq/T
dq<=TdS

du= dq + dw
du <= TdS -Pex dV (from inequality above)
if constant S and V
du<=0 to be spontaneous, or =0 at equilibrium

Hard to maintain a constant entropy in a lab

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
2
Q

What is the equation for Helmholtz free energy? Derive how the condition for equilibrium can obtained

A

A= u- TS
dA=du - TdS - SdT
dA<= TdS -P ex dV - TdS -SdT
dA<= -Pex dV - SdT

for a process at constant V and T
dA<= 0, at equilibrium=0

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
3
Q

What is the equation for Gibbs free energy? Show how it can be used for a reaction at equilibrium?

A

G= A + pV
dG= dA + pdV + Vdp
dG<= -Pex dV - sdT + pdV + Vdp
at mechanical equilibrium where p=p ex
dG<= Vdp - sdT

for a process at constant p and t, dG<0
and dG=0 at equilibrium

e.g phase transitions, chemical reactions…

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
4
Q

How can the Gibbs free energy incorporate enthalpy?

A

G= A + pV
G= U - TS + pV
G= U + pV - TS
G= H - TS

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
5
Q

How can a systems ability to do non pV work be used within the free energy equations? What is the maximum available work of a system?

A

dw= -P ex dV + dwe, other work
dG<= dwe or equal at equilibrium
The maximum work from a process at constant T and P is equal to the decrease gibbs free energy

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
6
Q

What are the terms involved in the fundamental equations?

A

They show how the 4 energy state functions, U, H, A, G, vary with P, V, S, and T

Can all be derived from definitions of the the energy state functions, and using the first and second law and pv work

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
7
Q

How can the fundamental equation for H be derived? and A?

A

H= U + pV
dH= du + pdV + Vdp
dH= TdS - pdV + pdV + Vdp
dH= TdS + Vdp

A= u -TS
dA= du - Tds - SdT
dA= TdS- pdV - TdS - SdT
dA= pdV - SdT

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
8
Q

Why can we remove the inequality when deriving the fundamental equations but not for spontaneity arguements?

A

Replacing du rev with du
As valid for changes between equilibrium states

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
9
Q

How can the maxwell relations be derived?

A

Start with any fundamental equation

e.g dH= TdS + Vdp
implies H= H(S, p )
dH= (∂H/∂S)p dS + (∂H/∂p)s dP
implies (∂H/∂S)p = T and (∂H/∂p)s = V

and as ∂²H / ∂s∂p = ∂²H / ∂p∂s
so taking the derivative with respect to p for t as already done for s

(∂T/∂P)s = (∂V/∂s)p

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
10
Q

How do you derive the Gibbs-Helmholtz equation?

A

G= H -TS
-S= (G-H) / T
From the maxwell equations,
-S=(∂G/∂T)p

(∂G/∂T)p - G/T= -H/T from subbing in and rearranging

but if we take G/T and differentiate implicitly with respect to T, using the product rule

= 1/T (∂G/∂T)p - G/T²
=1/T ((∂G/∂T)p - G/T)

which is 1/T a factor of -H/T

so
∂/∂T (G/T) = - H / T²

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
11
Q

How do you derive the van’t Hoft equation from the Gibbs Helmholtz?

A

ΔrG⦵ = -RTlnkp
ΔrG/T⦵=-Rlnkp

∂/∂T (ΔrG/T⦵) = - ΔH / T²

∂/∂T (Rlnkp) = ∂/∂T (ΔrG/T⦵)
∂/∂T (lnkp) = - ΔH / RT²

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
12
Q

How do you derive an equation to show how G varies with pressure for ideal gases and solids?

A

dG= Vdp - SdT
using the maxwell relation, (∂G/∂p)T= V

moving the p over and integrate

G2-G1= ∫ v dp
of a perfect gas, using v= nrt/p
G2-G1= nRTln(p2/p1)

using p1=1 atm
G2- G⦵=nRTln(p2/p⦵)
G2= G⦵ + nRTln(p2/p⦵)

for solids
G2-G1=v ∫ dp, as V independent of p
G2= G⦵ + V⦵(p-p⦵)

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
13
Q

How can the idea of isothermal compressibility used for an equation of how G of solids varies with pressure?

A

graph lnV against p
slope=-k = (∂lnV/∂p)T= -1/v (∂V/∂p)T
rearrange for V

then same G integral as before, replace V with -1/k (∂V/∂p)T
G2-G1= (v2-v1) / k

-k = (∂lnV/∂p)T, rearrange for v2 in terms of v and e

end up with
G2= G⦵ + V/k(1-e^-k(p2-p⦵)
and as k approaches 0,
G2= G⦵ + v⦵(p2-p⦵)

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
14
Q

What are the conditions for phase equilibrium and how have these been derived?

A

Suppose an equilibrium between a and b, where dn moles of a is converted to b, constant p,t
dG= G(b) - G (a) dn
at equilibrium dG=0

so G(b) = G(a)

can be 2 or 3 states. but 3 states have isolated points in the p,t plane

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
15
Q

What does the p/t graph for water look like?

A

Y=mx line from origin between s and g
almost backwards line from triple point between solid and liquid
almost quadratic from triple point up ish between liquid and gas

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
16
Q

How do you calculate the degrees of freedom for a substance?

A

F= 3 - p, the number of phase in equilibrium

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
17
Q

Derive the Clapeyron equation

A

The slope of a pt graph is dp/dT
Consider the points p,t and p+dp, T + dT

at p+dp, T + dT, G(a) + dG(a) = G(b) + dG(b)
at p,T G(a)=G(b)
subtracting the equations

dG(a)= dG(b)

using the fundamental equation dG= Vdp - SdT, which applies to both

V(a)dp - S(a)dT= V(b)dp - S(b)dT
V(b)dp - V(a)dp= S(b)dT- S(a)dT
ΔV(b-a)dp= ΔS(b-a)dT
dp/dT=ΔS/ΔV

where ΔV is the volume change between the phases and ΔS the entropy change between the phases

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
18
Q

How can the Clapeyron equation be used to incorporate enthalpy?

A

ΔG=ΔH - TΔS
at equilibrium, ΔG=0
ΔS= ΔH/T

dp/dT=ΔS/ΔV (Clapeyron equation)
dp/dT= ΔH/TΔV

19
Q

How can the Clausius-Clapeyron equation be derived?

A

Clapeyron= dp/dT= ΔS/ΔT = ΔH/TΔV
For sublimations and vaporisations, we can assume the volume change= volume of the gas, and there is such a large increase in volume, volume solid/liquid negligible
And we can use the ideal gas law for the volume of gas
pV=nrt with 1 mol
V=RT/p

substituting into the Clapeyron equation
dp/dT= ΔH/T/(RT/p) = pΔH/RT²
1/p dp/dT = ΔH/RT²
dlnp/dT=ΔH/RT²

an approximation

20
Q

If given the vapour pressures of a gas at different temperatures, how can the enthalpy changes of vaporisation and sublimation be calculated?

A

The Clapeyron equation can be written in the form
ln(p)= C -ΔH/RT When integrating out
Sketch a graph of this and it will give two opposing best fits
The first one is vaporisation, with higher temperatures but lower pressures and the second sublimation
Then you can calculate the slopes

Or you can use the equation with suitable data points

21
Q

What is the chemical potential of a pure substance?

A

The amount of Gibbs energy of one mole of the pure substance

G(m)=μ
G=nμ

22
Q

What is the fundamental equation for dG in an open system?
How does this vary for a mixture?

A

dG= Vdp - SdT + sum of μdn

for a mixture, μ1dn1 + μ2dn2 …

from exact differential from G=G(P,T,n)

23
Q

What is the Gibbs energy of a system using chemical potential? What is the differential for μ?

A

G= sum of n x μ for all components of the system

G=nμ
∂G/∂n = μ

24
Q

What is the Gibbs- Duhem equation and how is it derived?

A

G= sum of nμ
dG= sum of ndμ + sum of μdn

dG=Vdp - SdT + sum of μdn
at constant p and t
dG= sum of μdn

subtracting the equations
0= sum of ndμ

25
How do you calculate the change in Gibbs energy of mixing two gases at constant pressure?
G2= G⦵ + nRTln(p2/p⦵) and assume 1 molar μ2= μ⦵ + RTln(p2/p⦵) mixing n moles of a and n moles of b Pa= xaP Pb= xbP where p is the total pressure and x is the mole fraction p= external pressure as balanced before mixing initial G= na(μa⦵ + RTln(p/p⦵)) + nb(μb⦵ + RTln(p/p⦵)) after mixing new G= na(μa⦵ + RTln(pa/p⦵)) + nb(μb⦵ + RTln(pb/p⦵)) ΔG=new G - initial G = naRT(ln(pA/p⦵)-lnp/p⦵)+nbRT(ln(pb/p⦵)-lnp/p⦵) =naRT(ln(pA/p)+nbRT(ln(pb/p) =naRTlnxa + naRTlnxb =nRT(xalnxa + xblnxb)
26
What happens to the chemical potentials upon mixing perfect gases? Comment on the likelihood of this occuring?
Chemical potentials of the gases are lower in the mixture than pure A and B Spontaneous and entropy driven
27
Following on from the equation for the the change in Gibbs energy for mixing perfect gases, show by calculation the process is entropy driven. Also calculate the maximum change in Gibbs energy?
ΔG=nRT(xalnxa + xblnxb) from the Maxwell relation, (∂G/∂T)p=-S -S= nR(xalnxa + xblnxb) ΔG=ΔH-TΔS ΔH=ΔG + TΔS = 0, so entropy driven X= total Xa=1-Xb ΔG=nRT(1-xb)lnx(1-xb) + xblnxb) differentiating with respect to Xb =nRT(lnxb - ln(1-xb)) maximum when xb= 1/2 ΔG=nRT(1/2ln1/2 + 1/2ln1/2) = -nRTln2
28
How has gibbs energy been defined in terms of extent of reaction?
dn= component x d extent (dE) dG= Vdp - SdT + sum of μ dn at constant p/t dG= sum of μ x component dE dG= ΔG dE
29
What is the condition for equilibrium?
ΔG=0
30
How has Kp been derived, and the equation associated with it?
μj = μj⦵ + RTln(Pj/P⦵) summing each of the components ΔG= ∑ μj = ∑μj⦵ + ∑j RTln(Pj/P⦵) =ΔG⦵ + ∑j RTln(Pj/P⦵) ΔG=ΔG ⦵+ RT ∑ln(Pj/P⦵) ^ j ΔG=ΔG ⦵+ RT lnKp when at equilibrium, ΔG=0 ΔG⦵=-RT lnKp
31
What is the equation for Kp? What are the units and what factors does Kp depend on?
Kp= e^-ΔG⦵/RT dimensionless, as only depends on ΔG⦵ so not total pressure It is dependent on temperature
32
Why does temperature affect Kp? Why is there an approximation? How can accuracy be increased for this approximation?
From the van't Hoft equation: ∂/∂T (lnkp) = - ΔH / RT² and after integrating everything out lnKp(T2) approximately = lnKp(T1) + ΔH⦵/R (1/T1 - 1/T2) so dependent on temperature Assumes enthalpy change independent on temperature so not exact Replace enthalpy with Cp values and equations...
33
How does pressure affect the position of equilibrium and how can these calculations be carried out?
Increased pressure, push to the side with fewer gaseous moles The products will have a degree of disassociation between 0 and 1 Use algebra to start with mole changes and stoichiometry, think A level table Put into partial pressures and the Kp expression with standard pressure
34
What is the general equation for chemical potential e.g for a solid, real gas...
μj = μj⦵ + RTlnaj where aj is the activity of a component
35
What happens to substances in terms of state at a high enough temperature?
The the liquid/gas phase boundary disappears and results in a fluid state
36
What do the PV graphs for a substance look like before, after, and at the critical temperature? Explain
Above, follows inverse proportionality of a gas, increase pressure, lower volume Below, from the right, curve for a gas, then a straight line across and then straight up This is because gases follow inverse proportionality, liquids and gases have a range of volume for that phase, and liquids can have higher pressures but similar volumes so straight up At Tc, negative cubic shape with point of inflection, in between two temperatures
37
What are the conditions for the critical point? How can the critical point be found for a substance?
The point where P=Pc, T=Tc, and V=Vc, above this acts as fluid Singular ∂P/∂V= 0 and also the second derivative
38
Why does a critical point occur? Why isn't it seen in perfect gases?
Arises from intermolecular interactions, perfect gases ignore these From derivative of ideal gas equation, so way for it to equal 0 at any pressure
39
What happens to the isothermal compressibility at the critical point? And Cp-Cv?
Compressibility tends to infinity as dividing by ∂P/∂V which is 0 As does Cp-Cv
40
What are the units for Gibbs equations for GIbbs?
J/mol
41
How can you calculate the temperature/pressure of a triple point?
All phases have the same pressure, temperature Equate the functions for t or p to find it
42
How can you calculate Kp from concentrations and temp?
Convert conc into pressure via ideal gas equation Pv=nrt C=n/v P=cRT , then multiply by mole fractions and sub into equation
43