Fracture Mechanics Flashcards

1
Q

Why does fatigue cracking form?

A

as a result of a cyclic load being applies. This can be as a result of material discontinuity.

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2
Q

How to know if a material is adequate for its function?

A

Material is adequate if its strength is > applied stress.

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3
Q

What is the fracture mechanics approach? - 3 main variables

A

Applies stress will influence both the flaw size and fracture toughness. Of which both of these influence each other. This helps establish flaw tolerance limits.

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4
Q

Are ceramics more compressive or tensile in strength?

A

Ceramics have higher compressive
strength than tensile.

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5
Q

How does crack extension occur?

A

When the energy available for growth is sufficient to overcome the resistance of the materials – Creation of a new surface requires energy: surface energy + local deformation/rearrangements etc.

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6
Q

What is the energy supplied by and what are the energy losses in the energy approach to fracture mechanics?

A

Energy supplied by: stored elastic energy + work done by
external Forces
Other energy loss terms: kinetic energy, bulk plastic
deformation, etc

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7
Q

What are the 3 main energy approaches of laws to obey?

A

Elastic – energy associated with plastic deformation small
Linear – obeys Hooke’s Law ie., Stress ∝ Strain (homogeneous)
Quasi-static – kinetic energy term small

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8
Q

What is the equation for energy release rate?

A

G= aπσ^2/E
Where G is the energy release rate, E the youngs modulus and a is 1/2 the crack length.
Meaning that at a constant energy release rate, the stress varies with 1/sqrt a the length.

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9
Q

What is the stress intensity approach to fracture mechanics?

A

K= σ sqrt(πa)
Fracture occurs when Ki (driving force for fracture) = Kic (measure of material resistance - fracture toughness)
so G=Ki^2/E

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10
Q

How do fracture mechanics predict time dependent crack growth?

A

da/dN= C(∆K )^m
where da/dN is the crack growth per cycle, ∆K is the stress intensity range, C and m are material constraints.

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11
Q

How is the allowable flaw size defined?

A

By dividing the critical size by
a safety factor. Predicted
service life = time for ‘a’ to
become max. allowable size.

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12
Q

What are fracture mechanics types? -3

A
  1. Linear elastic fracture mechanics - no plastic deformation
  2. Elastic plastic fracture mechanics - considering plastic deformation
  3. Dynamic fracture mechanics, viscoelastic fracture mechanics, viscoplastic fracture mechanics. - time is the variable
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13
Q

What are the typical fracture behaviours of metals, polymers and ceramics?

A

METALS- linear elastic(high strength steel), elastic-plastic/fully plastic(low and medium strength steel), fully plastic (austenitic stainless steel), linear elastic(precipitation - hardened aluminium), viscoplastic(metals @ high temp), dynamic-viscoplastic(metals at high strain rates).
POLYMERS - below Tg(linear elastic/viscoelastic) and above Tg(viscoelastic)
CERAMICS- monolithic(linear elastic), ceramic composites(linear elastic) and high temperatures(Viscoplastic)

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14
Q

How does fracture toughness interact with failure stress and the failure mechanism)

A

When combination of mechanical performance and high temperature usage is needed – CERAMICS.
As the fracture toughness increases the failure stress increases through the LEFM(causing brittle fracture) to the non-linear fracture mechanics(brittle-ductile transition) to the limit load analysis (failure is insensitive to K and only determined by flow properties here)

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