formulas

Question 1

Empirical formula

Answer 1

Lowest whole number ration of elements in a compound

Question 2

ef- C3H6 ->

Answer 2

CH2

Question 3

calculating EF - compound x contains 50% S and 50% O. What is EF of X (we have 100g of x)

Answer 3

50g - S : moles of S - 50/32=1.56m
50g - O :moles of O -50/16= 3.12m

3.12:1.56
2:1
EF= S2O (we need two O to have equal)

Question 4

use a table

Answer 4

mass
ram
moles
ratio

Question 5

mf of CH

• given the rfm of the compound is 78
• given the rfm of CH is 13

Answer 5

78/13 = 6

6x the ration

C6H6

Question 6

compound x contains 44.4% C, 3.7% H, 51.9% N - calculate EF

rfm
c-12
h-1
n-14

Answer 6

44. 4/12=3.7
45. 7/1=3.7
46. 9/14=3.7

CHN