forces and motion and radioactivity Flashcards
balanced and unbalanced forces
- the forces acting on an object are balnced, there is no change in motion; resultant force = 0N
- the friction and drag on a car= 500N traction force = 500Nresultant force = 0N car moves at constant speed
- if the forces are unbalanced, the object accelerates or decelerates
Drag = 700N
Traction = 500 N
resultant force= 200N
acceleration
acceleration= change in velocity/ time taken
units = m/s squared
negative accelerations are decelerations
time taken = change in velocity / acceleration
change in speed = time taken * acceleration
measuring distances from velocity - time graphs
- distance = area under graph
Newton’s second law
A force accelerates a mass (m). what is the acceleration (a)?
bigger force means bigger acceleration so acceleration is proportional to force
bigger mass means less acceleration so acceleration is inversely proportional to mass
F= Ma
1 newton will accelerate 1kg at 1 m/s
friction between surfaces
- caused when the jagged surfaces interlock- in order to move a book across a table you have to break the interlocking jaggedy bits- frictional forces always act in the opposite direction to your pulling force
measuring the coefficient of friction surfaces
- measure the angle tan at which various objects just start to slide down a slope. then we can calculate the coefficient of friction.
equipment: retort stand; boss; ramp; wooden block.
record the angle at which the object starts to slide; repeat with larger weights.
to work out the coefficient tyoe tan(angle) into your calculator correct to 2 decimal places
air resistance and terminal velocity
terminal velocity is reached when air resistance= weight of falling object
larger the surface area and the faster the speed the more air resistance there is
stopping veihcles
when you stop a vehicle the vehicle’s kinetic energy must be converted into heat and sound (usually by brakes)stopping distance is made up of two parts : 1) the thinking distance
2) the braking distance
thinking distance= distance over which you travel whilst thinking about braking
braking distance= distance over which you travel when the brakes are activated
stopping distance = braking distance + thinking distance
scalars and vectors
scalars have magnitude only eg. a speed of 12 m/s
vectors have magnitude and direction eg. velocity of 15 m/s N a journey from hampton to ealing: the distance from H to E is 12 km
the displacement (vector) from H to E is only 8km (as the crow flies)
speed = distance / Time (scalar)velocity = displacement/ time (vector
hooke’s law
- if a material obeys hooke’s law :
- the extension is proportional to the force
- if a material returns to its original shape or length when you remove the deforming forrce, the material is said to be elastic
experiment : investigating whether springs and rubber bands obey hooke’s law
aim: we’ll measure force against extension for : 1) two springs in series 2) two springs in parallel 3) rubber band
apparatus: - damp, boss, springs, masses (upto 10n)
method:
- first measure the original length of the two springs or the rubber band and record this in a table
- add one 0.5 n weight to the end of the spring/s and measure it’s extension
- record this in a suitable table
- repeat this for all three experiments adding 0.5 n weights each rime upto 10n
- record your results in a line graph (extension against force)
momentum
- momentum = MU
M= mass
U= velocity - it can be positive or negative
- e.g. a 2000Kg car moves at 25m/s. what is its momentum?
momentum = MU = 2000 * 25 = 50,000 kg m/s
-
collisions and conservation of energy
- whenever objects collide, the momentum after the collision is the same as the momentum before- always conserved
- law of conservation of momentum =
momentum before = momentum after
e.g. a 3000 kg lorry going at 20 m/s goes into a stationary mini (1000kg)
the two stick together. what speed do they move off
momentum = MU = 3000 * 20
= 60,000
momentum after = 60,000 = MU = 4,000 * U
U= 60,000/ 4000 = 15 m/s
recoil
- before you fire a gun the total momentum is 0. when you fire the bullet the total momentum must still be 0. this is only possible if the gun has momentum in the opposite direction to the bullet - gun recoils
- e.g. a 2kg gun fires a 0.001 kg bullet at 200 m/s . what is the gun’s recoil velocity?
gun momentum = bullet momentum
2kg*U = 0.001kg * 200 m/s
U= (0.001 * 2000) / 2
= 0.1 m/s
newton’s second law
- to stop an object you need to change its momentum
- to change an object’s momentum you need to apply a force e.g. catching a ball
- the more momentum the ball has the bigger the force needed to stop it
- force = change in momentum / time taken
- e.g. a 1 kg custard pie travelling at 5 m/s hits a wall and stops in a time of 0.5 s. what force did the wall exert?
m= 1kg U= 5m/s V= 0 m/s (final velocity) t= 0.5 s
F= (mV - mU) / t = (1 * 0 ) - (1*5) /0.5
= 10n