Force and Motion Flashcards

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1
Q

(Formula of motion)

v = ?

A

v = u + at

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2
Q

(Formula of motion)

s = ? (no V)

A

s = ut + ½ at²

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3
Q

(Formula of motion)

s = ? (no a)

A

s = ½ (u+v)t

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4
Q

(Formula of motion)

v² = ?

A

v² = u² + 2as

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5
Q

(Formula of motion)

Sn = ?

A

Sn = Vi + a/2 (2n-1)

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6
Q

(Formula of motion)

What is the sign of g when downward motion vs upward motion

A

Downward: g
Upward: -g

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7
Q

Newtons First Law

A

Body will continue to be at rest when no external force acts upon it

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8
Q

Newtons Second Law

A

Force produces acceleration in direction of force. (a is directly proportional to applied F and inversely proportional to mass)

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9
Q

1N = ___ dyne

A

10^5 dyne

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10
Q

Newtons Third Law

A

For every action there is an equal and opposite reaction

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11
Q

Equal and opposite reactions always act on ______. They never _______

A

Always act on TWO DIFFERENT BODIES . They never CANCEL / NEUTRALIZE THE EFFECT OF FORCE .

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12
Q

(Motion of connected bodies)

F1 =
F2 =

A

F1 = (m1/m1+m2) F

F2 = (m2/m1+m2) F

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13
Q

P = mv
SI Unit of P?
Another unit?

A

SI Unit is kgms^-1

Another unit is Ns

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14
Q

Newtons Second Law in terms of momentum

A

Time rate of change of momentum is equal to the force acting on the body

(F = p/t)

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15
Q

Impulse (J) =

A

J = Ft

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16
Q

Elastic collision vs Inelastic collision

A

Elastic = both momentum and KE is conserved
Inelastic = only momentum is conserved. (KE converted to another form)

17
Q

P1 + P2 = P1’ + P2’

A

m1u1 + m2u2 = m1v1 + m2v2

18
Q

Speed of approach = Speed of recession

v1 =
v2 =

A

v1 = (m1-m2/m1+m2) u1 + (2m/m1+m2) u2

v2 = (2m1/m1+m2) u1 + (m2-m1/m1+m2) u2

19
Q

Case when masses equal (m1 = m2)

A

EXCHANGE Vs

v1’ = u2 and v2’ = u1

20
Q

Case when equal masses, stationary target (u2 = 0)

A

v1’ = 0
v2’ = u1

(Incident stops moving after collision and target moves with incident’s velocity)

21
Q

Case when incident heaver than target and target is stationary
(m1&raquo_space; m2) (u2 = 0)

A

v1 = u1 (Velocity of incident wont change)
v2 = 2u1 (Velocity of target will be twice of incident’s)

22
Q

Case when target heavier than incident and target is stationary
(m1 &laquo_space;m2) (u2 = 0)

A

v1 = —u1 (Incident gets pushed back in opposite direction but same velocity)
v2 = 0 (Target remains stationary)

23
Q

Path of projectile motion is dependent on 2 things:

A

— Initial velocity (u)
— Forces

24
Q

(Projectile motion)
Velocity at an instant
Vx = ?
Vy = ?

A

Vx = Vcosø
Vy = Vsinø - gt

25
Q

(Projectile motion)
Position at an instant
Sx = ?
Sy = ?

A

Sx = ucosøt
Sy = usinøt - ½gt²

26
Q

(Projectile motion)
Height

A

h = (u² sin² ø / 2g)
(Weird g in height so 2g)
(When 2g then 2 exponents)

27
Q

(Projectile Motion)
Range

A

x = (u² sin 2ø / g)
(One g in range so 1 exponent)
(but also 2ø)

28
Q

(Projectile Motion)
Time

A

t = (2u sin ø / g)
(Time = Two)

29
Q

(Projectile Motion)
Max Range
ø = ?º

A

ø = 45º
R = (v² sin 2(45) / g)
which equals
R = v²/g (because sin 90 = 1)

30
Q

Rmax = ___H
when how many degrees

A

Rmax = 4H
when 45º

31
Q

R = H when?

A

tan^-1 (4) = ø = 76º

32
Q

H with respect to T ?

A

H = gT² / 8
so
T = √(8H/g)

33
Q

When are ø1 and ø2 the same range?

A

When complimentary angles
ø1 + ø2 = 90

34
Q

(Projectile Motion)
When is a = 0

A

a = 0 on x axis at all times

35
Q

(Projectile motion)
When is v = 0 ?

A

v = 0 on y axis at max height

36
Q

(Projectile Motion)
KE H = ?

A

KE H = ½ mu² cos² ø
or
KE H = KEinitial cos² ø

37
Q

(Projectile Motion)
PE = ?

A

PE = ½mu² sin² ø

38
Q

(Projectile Motion)
Momentum?

A

Pu = mucosø

39
Q

(Projectile Motion)
PE H / KE H = ?

A

PE H / KE H = tan² ø