Fomulas Flashcards
Ohms Law 1
E=I R I = E/R R= E/I
Ohms Law 2
P = I E E = P/I I = P/E
Convert to dB Voltages
20log(#/ref)
eg—20log(50 V / 25 V) = 6dB
3dB is only a double for power changes, not voltage only
Convert Power to dB
10log(#/ref)
eg
10log(50/25) = 3dB
Voltage ratio from dB
10^(# / 20)
eg
5dB = 10^(5/20) = 1.77
Power ratio from dB
= 10^(#/10)
eg
3dB = 10^(3/10) = 1.995 (so, 2)
Percent voltage to dB
dB = 20 log (% V / 100%)
eg, a 200% voltage change:
20 log (200/100) = 6dB
Percent power to dB
dB = 10log(% A / 100%)
eg, a 3000% increase in power:
10log(3000/100)=10log(30)=14.77dB
Find percentage voltage from dB
100*10^(dB/20)
eg, 10dB loss (-10dB):
100*10^(-10/20)=31% voltage
Find percent power from dB
100*10^(dB/10)
eg, a component loses 2dB:
100*10^(-2/10)=63% power remains
Wavelength
L= c/f f = c/L
wl = 300/f f = 300/L
Use 300 bc we’re dealing with MHz, not Hz
Peak Voltage to RMS
0.707*Vpk (If given peak voltage)
or
0.707*(Vp-p/2).
(If given a peak to peak voltage)
Find Peak voltage if given Vrms
1.414*Vrms
Find Vp-p
2.828*Vrms
PEP
=(Vrms^2) / Resistance