Fluids Flashcards

1
Q

Which forces are supported in fluids?

A
  • tension is not supported
  • compression is supported and results in a small elastic deformation
  • shear is supported but results in flow
How well did you know this?
1
Not at all
2
3
4
5
Perfectly
2
Q

du/dx + dv/dy + dw/dz = 0

A

all flux in all three directions must equal to zero
mass must be concerved

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
3
Q

In which direction of pressure change is fluid driven?

A

From high to low pressure

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
4
Q

τ = F/A

A

Shear stress= force/area

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
5
Q

τ= μ δu/δy

A

Shear stress = dynamic viscosity * (velocity/ depth)

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
6
Q

What is the shear stress in viscous flow?

A

No longer zero

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
7
Q

Kinematic viscosity?

A

ν=μ/ρ (m^2/ s)

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
8
Q

Dynamic viscosity?

A

μ (kg/ms)

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
9
Q

What navier stokes simplification can you make by assuming the flow to be steady?

A

All time derivatives will be zero (d/dt)=0

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
10
Q

What navier stokes simplification can you make by assuming the flow to be fully developed?

A

The velocity component in the x-direction will remain constant (du/dx = 0)

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
11
Q

What navier stokes simplifications can you make when the sides are incredibly long. (Flow in one direction, boundaries in another)?

A

No flow in the the third direction and no effect by the boundaries.
W=0
d/dz=0

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
12
Q

What simplification to navier stokes equations by assuming its laminar flow?

A

The gradient of v is zero and v is zero at the boundary, v must be zero everywhere. (V is in the y direction)

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
13
Q

Re= ρUL/μ

A

Inertial forces/ viscous forces
Reynolds number= densityvelocity scale length scale/ dynamic viscosity

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
14
Q

What are Reynolds numbers for laminar flow?

A

Re < Recrit

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
15
Q

What Reynold numbers are turbulent flow?

A

Re> Recrit

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
16
Q

Q= π/4 D^2 U

A

Volume flux= π/4 * diameter^2 * velocity

(Only for uniform flow)

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
17
Q

What is Q along a pipe?

A

Constant

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
18
Q

What is M along a pipe

A

Momentum is constant along a pipe

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
19
Q

M= π/4 D^2 U^2 = QU

A

Momentum = π/4 * diameter ^2 * velocity ^2

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
20
Q

Hydraulic grade line?

A

Represents piezometric head (h)

How well did you know this?
1
Not at all
2
3
4
5
Perfectly
21
Q

Energy grade line?

A

Represents total head line (H)

22
Q

Piezometric head?

A

Pressure head + gravitational head combined

23
Q

p1/ρg + z1 = p2/ρg + z2 + τ0PL/ ρgA

A

p= pressure
ρ= density
g= gravitational acceleration
z= height
τ0= shear stress
P= wetted perimeter
L= length
A= area

24
Q

τ0= f/8 ρ U^2
where
f=f(Re,ks/D)

A

Shear stress = function of Reynolds and relative roughness * density * velocity^2/8

25
In what conditions is f= 64/Re
For laminar flow/ Re< 2300
26
In what condition is 1/f^(1/2) = -2log10[k/D/3.71 + 2.51/Re*f^(1/2)]
For turbulent flow/ for Re> 4000
27
When is 1/f^(1/2)= 2log10[Ref^(1/2)] -0.8
For turbulent flow in smooth pipes/ for Re>4000
28
hL = εU^2/2*g
minor head loss= loss coefficient* velocity^2/2*gravitational acceleration
29
ε= (1-Α1/A2)^2
Loss coefficient for sudden pipe enlargement = (1-small area before/ small area after)^2
30
RH= A/P
Hydraulic radius= flow area/ wetted perimeter
31
hf= f* L/4RH * U^2/2*g
head loss= function * length/4*hydraulic radius * velocity^2/2*gravitational acceleration
32
Entry length?
Region where boundary layer develops
33
Does laminar or turbulent flow boundary layers take longer to develop?
It takes longer for laminar pipe flow boundary layers to develop with longer entry lengths
34
Fully developed flow?
When boundary layers converges to pipe centreline
35
How does shear stress vary across a pipe?
Linearly with being 0 at the centreline
36
What effect of shear force have a long a plate?
The effect of shear force increases along a plate, increasing the thickness of fluid layer that is affected. Reynolds number also increases along a plate leading to turbulent flow conditions. There’s a laminar region, transition region and then turbulent region
37
u/u* = u*y/ ν
u= velocity u* = wall shear velocity ν= velocity viscosity y= depth/ distance from sublayer This works when yu*/ν is between 0 and 3~5
38
Sublayer thickness = (3-5) ν/ u*
ν= velocity viscosity u* = wall shear velocity
39
Irrationality equation?
dv/ dx - du/ dy = 0
40
What is the velocity normal to the cylinder on the surface of the cylinder?
Zero
41
Φ = Uo (r * D^2/4*r) cos θ
Φ = potential flow around a cylinder U0 = velocity r = distance from centre of cylinder D= diameter θ = angle to the point
42
ur = dΦ/ dr uθ = 1/r * dΦ/dθ
Velocity components in polar coordiantes
43
What are velocity on the surface of the cylinder?
ur = 0 uθ = -2U0 sinθ
44
P = 1/2 ρ U0^2 (1-4sinθ^2)
P = inviscid pressure distribution
45
What are the velocities on the surface of the cylinder in a real fluid?
ur = 0 (no flow in/ out of cylinder) uθ = 0 (friction between surface and fluid) No slip conditions
46
τ = μ duθ/dr
Shear stress = velocity gradient * dynamic viscosity
47
Drag force = Σ (τ ) ds
Drag force is the sum of all shear stresses taken round the surface of the cylinder
48
Explain the difference between upstream and downstream normal pressures for larger U0
For larger U0 the difference between upstream and downstream normal pressures contributes more significantly to the drag force. This pressure difference is caused by flow separation from the surface of the cylinder. In real solution pressure is a lot lower downstream than potential.
49
What causes flow seperation
-
50
What does flow separation depend on?
-