Final Year Test Flashcards

1
Q

Converting distributed load to concentrated load

A

Total force = area of load (width * height) (height is the force)
Point of action: centre point of area

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2
Q

Pin vs roller vs fixed support (reaction forces)

A

Pin support has x and y forces
Roller support only has y force
Fixed has x, y and moment forces

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3
Q

Finding shear force and bending moments in any section

A
  1. Draw free body diagram
  2. Find reactions
  3. Find SF’s and BM’s-select sections before and after each applied load and reaction
  4. Calculate SF and BM for section using equilibrium equations
  5. Plot SF and BM diagrams
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4
Q

Youngs modulus, stress strain

A

YM=stress/strain
Stress=Force/Area
Strain=Difference in length/length

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5
Q

T/J = Gθ/L = τ/r

A
τ = shear stress (force/area)
G = shear modulus
L = length
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6
Q

Macaulays method for working out deflection

A

Use the equation (d^2v)/(dx^2) = M/EI

  1. Do normal bending moment but cut off just before the end
  2. Get an equation for M(x)
  3. Sub in for M in equation above
  4. Intergrate twice to find V. You can just square the X brackets and divide by 2. You’ll end up with two constants
  5. Look back at your original diagram. Under each support V = 0. Set x to the support values to find the two constants
  6. Sub in x for any point to find the deflection there
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7
Q

Izz formula

A
Izz = (b*h^3)/12 + b*h*(ȳ - y1)^2
b = width
h = height
ȳ = centroid
y1 = centre of block 1

Izz = Izz1 + Izz2

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8
Q

Finding shear force and bending moments when there’s a distributed load

A
Q(x): Draw into it a bit
Do F(x-x1) where F is the force and x1 is the point at which it starts to act
M(x): F(x-x1) * (x-x1)/2
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