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Chemistry 111 > Final Exam Review > Flashcards

Final Exam Review Flashcards

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1
Q

How do you calculate the steric number?

A

Number of Atoms bonded + the number of lone pairs on central atom

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2
Q

Fill in the blanks?
SN=2 BALPA=______ Lone Pairs on Central Atom=____
Shape=_______ Bond Angles=_______ Hybridzation=____

A 
Sn=2
BALPA=linear 
Lone Pairs on Central Atom=0
Shape=linear 
Bond Angles=180
Hybridization=sp
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3
Q 
Fill in the blanks-
Sn=3
BALPA= 
Lone Pairs on Central Atom=0
Shape=
Bond Angles=
Hybridization=
A 
Sn=3
BALPA=trignol planear 
Lone Pairs on Central Atom=0
Shape=Trignol planear 
Bond Angles=120
Hybridization=sp2
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4
Q 
Fill in the blanks-
Sn=3
BALPA= 
Lone Pairs on Central Atom=1
Shape=
Bond Angles=
Hybridization=
A 
Fill in the blanks-
Sn=3
BALPA= trignol planear
Lone Pairs on Central Atom=1
Shape=bent 
Bond Angles=120
Hybridization=sp2
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5
Q 
Fill in the blanks-
Sn=4
BALPA= 
Lone Pairs on Central Atom=0
Shape=
Bond Angles=
Hybridization=
A 
Fill in the blanks-
Sn=4
BALPA= tetrahedral
Lone Pairs on Central Atom=0
Shape=tetrahedral
Bond Angles=109.5
Hybridization=sp3
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6
Q 
Fill in the blanks-
Sn=4
BALPA= 
Lone Pairs on Central Atom=1
Shape=
Bond Angles=
Hybridization=
A 
Fill in the blanks-
Sn=4
BALPA= tetrahedral
Lone Pairs on Central Atom=1
Shape=trignol bipyramidal 
Bond Angles=109.5
Hybridization=sp3
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7
Q 
Fill in the blanks-
Sn=4
BALPA= 
Lone Pairs on Central Atom=2
Shape=
Bond Angles=
Hybridization=
A 
Fill in the blanks-
Sn=4
BALPA= tetrahedral 
Lone Pairs on Central Atom=2
Shape=bent 
Bond Angles=109.5
Hybridization=sp3
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8
Q 
Fill in the blanks-
Sn=5
BALPA= 
Lone Pairs on Central Atom=0
Shape=
Bond Angles=
Hybridization=
A 
Fill in the blanks-
Sn=5
BALPA= trignol bipyramidal 
Lone Pairs on Central Atom=0
Shape=trigonal bypyramidal 
Bond Angles=90, 120, 180
Hybridization=sp3d
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9
Q 
Fill in the blanks-
Sn=5
BALPA= 
Lone Pairs on Central Atom=1
Shape=
Bond Angles=
Hybridization=
A 
Fill in the blanks-
Sn=5
BALPA= trignol bipyramidal 
Lone Pairs on Central Atom=1
Shape=seesaw
Bond Angles=90, 120, 180
Hybridization=sp3d
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10
Q 
Fill in the blanks-
Sn=5
BALPA= 
Lone Pairs on Central Atom=2
Shape=
Bond Angles=
Hybridization=
A 
Fill in the blanks-
Sn=5
BALPA= trignol bipyramidal
Lone Pairs on Central Atom=1
Shape=t-shaped 
Bond Angles=90, 120, 180
Hybridization=sp3d
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11
Q 
Fill in the blanks-
Sn=5
BALPA= 
Lone Pairs on Central Atom=3
Shape=
Bond Angles=
Hybridization=
A 
Fill in the blanks-
Sn=5
BALPA= trignol bipyramidal
Lone Pairs on Central Atom=1
Shape=linear 
Bond Angles=180
Hybridization=sp3d
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12
Q 
Fill in the blanks-
Sn=6
BALPA= 
Lone Pairs on Central Atom=0
Shape=
Bond Angles=
Hybridization=
A 
Fill in the blanks-
Sn=6
BALPA= octahedral 
Lone Pairs on Central Atom=0
Shape=octahedral 
Bond Angles=90, 180
Hybridization=sp3d2
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13
Q 
Fill in the blanks-
Sn=6
BALPA= 
Lone Pairs on Central Atom=1
Shape=
Bond Angles=
Hybridization=
A 
Fill in the blanks-
Sn=6
BALPA= octahedral 
Lone Pairs on Central Atom=1
Shape=square pyramid 
Bond Angles=90, 180
Hybridization=sp3d2
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14
Q 
Fill in the blanks-
Sn=6
BALPA= 
Lone Pairs on Central Atom=2
Shape=
Bond Angles=
Hybridization=
A 
Fill in the blanks-
Sn=6
BALPA= octahedral 
Lone Pairs on Central Atom=2
Shape=square planear 
Bond Angles=90, 180
Hybridization=sp3d2
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15
Q 
Fill in the blanks-
Sn=6
BALPA= 
Lone Pairs on Central Atom=3
Shape=
Bond Angles=
Hybridization=
A 
Fill in the blanks-
Sn=6
BALPA= octahedral 
Lone Pairs on Central Atom=3
Shape=t-shape
Bond Angles=90, 180
Hybridization=sp3d2
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16
Q 
Fill in the blanks-
Sn=6
BALPA= 
Lone Pairs on Central Atom=4
Shape=
Bond Angles=
Hybridization=
A 
Fill in the blanks-
Sn=6
BALPA= octahedral 
Lone Pairs on Central Atom=4
Shape=linear 
Bond Angles=180
Hybridization=sp3d2
17
Q 
What Steric numbers are accompanied by each hybridization level?
sp=
sp2=
sp3=
sp3d=
sp3d2=
A 
sp=2
sp2=3
sp3=4
sp3d=5
sp3d2=6
18
Q

If a central atom has 0 lone pairs and all attached are the same, then the molecule is?

A

non-polar

19
Q

What is valence bond theory?

A

describes bonds as being formed by overlap of partially filled orbitals

Chemistry 111 (2 decks)

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