Final Exam Flashcards

1
Q

What are three methods to solving limit problems?

A
  1. Try along different paths, such as (x,0), (0,y), (x,x), (y^2, y)…
  2. Convert to polar coordinates.
  3. Use the Squeeze theorem. This can work for trig functions or e; e^-1 < e^(y^2) < e.
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2
Q

How do you find the equation of a plane?

A
  • Find the normal vector to the plane.
  • Make these components the coefficients in the equation.
  • Pick some point on the plane.
  • (n)(x - x0) + n(y - y0) = 0
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3
Q

How do you find the normal vector to a plane?

A
  • Given that <0,0,1>, <1,2,0>, <1,1,1> lie in the plane.
  • Subtract the first from the other two.
  • = <1,2,-1> , <1,1,0>
  • Compute the cross product.
  • <1,2,-1>
  • <1,1, 0>
  • = <1, -1, 1>
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4
Q

How would you find the directional derivative of f?

A

Dot the gradient with the unit vector in the direction you want.

If you want to go in the maximum rate of change, dot the gradient with itself.

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5
Q

What is the vector equation of a line?

A

r(t) = (starting point) + tv, where v is a parallel vector

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6
Q

Compute the equation of the plane given a point and a line.

A

Use the vector from the line as one term in the cross product.

Use the vector from subracting (given point) - (equation point) as the other term.

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7
Q

What are cylindrical coordinate substitutions?

A

Cylindrical Coordinates
Jacobian = dV = r [dz dr dt]
x = rcos(t)
y = rsin(t)
z = z

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8
Q

What are spherical coordinate substitutions?

A

Spherical Coordinates
Jacobian = dV = r^2 sin(ø) [dr, dt, dø]
x = r cost sinø
y = r sint sin ø
z = r cos ø
r^2 = x^2 + y^2 + z^2

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9
Q

How do you compute the arc length of a function?

A

Apply ∫ from a to b for the absolute value of r’(t).
∫ |r’(t) | dt
How to find the boundaries for t? Sometimes, the given vector function will have a straight “t” which one can solve for?

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10
Q

For any vector v, we have v x v =

A

0

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11
Q

If f is a function of three variables that has continuous second order partial derivatives, then _____ = 0.

A

curl(gradient • F) = 0

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12
Q

Iff a vector field F is conservative, then its curl is

A

zero.

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13
Q

If you take the divergence of a curl of the vector field, you will get ___.

A

0.

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14
Q

Given that r”(t) ≠ a constant, is it true that r’(t) x r”(t) ≠ constant?

A

Plug in an example r(t).
For example, r(t) = <t^3, 0, 0>
Then r’(t) = <3t^2, 0,0> , r”(t) = <6t, 0, 0>, and their curl = 0.
0 is a constant, so this is false.

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15
Q

How do you apply the FTLI?

A

Check that Py = Qx. (This shows that it is conservative.)
Construct some function f such that the gradient of f = F.
Take the partials of F with respect to x and y.
Integrate one.
Solve for any differences.
Take f(endpoint) - f(starting point).

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16
Q

Given that r”(t) ≠ a constant, can r’(t) • r’(t) be constant?

A

Clever. Consider

Sin and Cos.

Take r(t) = <cos(t), sin(t), 0>.

Then r’(t) = < -sin(t), cos(t), 0> dotting with

With r’(t) = < -sin(t), cos(t), 0>

= sin^2(t) + cos^2(t) = 1

17
Q

If asked if some manipulation of theorems is true, what’s the first thing you should do?

A

Check to see whether they would result in scalars / vectors.

Dot product = scalar

Cross product = vector

18
Q

The value of the line integral does not depend on the parametrization of the curve, provided that ___

A

the curve is traversed exactly onece as t increases from a to b.

19
Q

What is the “jacobian” of ds?

A

ds = sqrt( (dx/dt)^2 + (dy/dt)^2) dt

20
Q

How do you find the line integral with respect to x?

A

∫ f(x,y) dx = f( x(t), y(t) ) , x’(t) dt

21
Q

What’s a vector way to solve this line integral

∫F • dr =

A

From a to b of F(r(t) • r’(t) dt

You’re plugging in the vector parametrization to the vector field, and then dotting with the derivative of the vector curve. Everything’s in “t.”

22
Q

By the Divergence Theorem, ∫∫{S} F • ds =

A

∫∫∫ {E} div(F)

23
Q

By the Divergence theorem, ∫∫∫ {E} div(F) =

A

∫∫F•ds over the boundary S

24
Q

How do you find the surface integral ∫∫{S} F•dS?

A

Normally, find a parametric representation of the surface. Then take the partials and take the cross product.

Then take ∫∫ {D} F(r) | r x r | dA

25
Q

What are the bounds for z in spherical coordinates?

A

From 0 to π

26
Q

Say you want to close a hemisphere. How would you do so?

A

The hemisphere consists of the hemisphere minus the unit disk boundary. Solve for the entire unit sphere using spherical coordinates, and then subtract – really, add, since its normal vector is downards – the unit disk.

When taking the surface integral of the unit disk, its normal vector is -k, and z = 0. This simplifies the calculation considerably.

27
Q

What does Stokes Theorem say?

A

∫∫{S} curl F • dS = ∫{C} F • dr

28
Q

Via Stokes,

∫{C} F • dr =

A

= ∫∫{S} curl F • dS

29
Q

Explain the three ways of directly evaluating surface integrals.

A

Method 1: If you have some function z, then then take ∫∫ (given) sqrt (dz/dx + dy + 1)

Convert to polar to solve.

Method 2: If you have some spherical function, parametrize it using spherical coordinates, and then take ∫∫ F(r) r(theta) x rø d(theta) dø. That is, cross the partials of the parametrization.

Method 3: If you have some z, then find a normal vector and dot it with the function F. A good normal vector is just the gradient of the boundary function.

Again, you’ll convert to polar to solve.

30
Q

How can you show that F is conservative?

A

Method 1: Compare it with Pi + Qj. If the partial of P wrt y (eg PAY) is equal to the partial of Q wrt x (QUIX?), then the vector field is conservative if the doman of F is open and simply connected.

Method 2: Show that there exists a function f such that ∆f = F. (where ∆ is actually del).

Method 3: Show that the curl = 0.

31
Q

You’re creating a potential function. You’ve already taken the integral of fx (i.e., the i term) and it has some constant of integration in it like g(x,z). What do you do?

A

Differentiate with respect to y.

Compare this new term with fx (i.e., the j term). Set them equal to solve for the g’(x,y) term.

32
Q

State Green’s Theorem.

A

∫∫{D} (Q wrt y) - ( P wrt y) = ∫ Pdx + Qdy.

That is, if you have some line integral that’s in PADDQ form, you can take the (?) integral of the area rather than a line integral if you take it with respect to QUIX MINUS PAY.

33
Q

What is the second derivative test for critical points?

A

Multiply two foxes by two eyes. Subtract the square of a mixed second derivative.

fxx*fyy - (fxy)2

If > 0 and fxx > 0, then a minimum.

If > 0 and fxx < 0, then a maximum.

If D < 0, then it is a saddle point.

34
Q
A