F5 Chapter 1: Redox equillibrium

Question 1

Oxidation
(oxygen)

Answer 1

Gain of oxygen

Question 2

Reduction
(oxygen)

Answer 2

Loss of oxygen

Question 3

Oxidation
(hydrogen)

Answer 3

Loss of hydrogen

Question 4

Reduction
(hydrogen)

Answer 4

Gain of hydrogen

Question 5

Oxidation
(electrons)

Answer 5

Loss of electrons

Question 6

Reduction
(electrons)

Answer 6

Gain of electrons

Question 7

Reduction
(Oxidation number)

Answer 7

Decrease of oxidation number

Question 8

Oxidation
(Oxidation number)

Answer 8

Increase of oxidation number

Question 9

Definition of Oxidation
(4 points)

Answer 9

• Gain of Oxygen
• Loss of Hydrogen
• Loss of electrons
• Oxidation number Increase

Question 10

Definition of Reduction
(4 points)

Answer 10

• Loss of Oxygen
• Gain of Hydrogen
• Gain of electrons
• Oxidation number Decrease

Question 11

Oxidising agent

Answer 11

A substance that Oxidises another substance

Question 12

Reducing agent

Answer 12

A substance that Reduces another substance

Question 13

H2S + Cl2 ——-> S + 2HCl

Which is the oxidising agent. Why?

Answer 13

Cl2 is the oxidizing agent.

This is because Cl2 is undergoing reduction, meaning it is gaining electrons and is causing the oxidation of H2S to S. In other words, Cl2 is taking electrons from H2S, causing H2S to lose electrons, which is the definition of oxidation. At the same time, Cl2 itself is being reduced, because it is gaining electrons, which is the definition of reduction.

Therefore, Cl2 is the oxidizing agent in this reaction because it is causing the oxidation of H2S to S.