Exponents Flashcards
-3² Equals
9
Product Rule
r s r + s
Y × Y = Y
Exp.
Y³ × Y⁵ =
Y⁸
Quotient Rule
r
Y r - s
---------- = Y
s
Y
Exp.
6
A
----------- =
2
A
4
A
Power of Product
2 2 2
(x . y) = x . y
Exp.
2
(a.b) =
2 2
a . b
Power of Power
r s rs
( x ) = x
Exp.
2 5
( z )
10
z
Power of quotient
r r r ( x/y) = x / y
Exp.
3
(5/7) =
3 3
5 / 7
Negative exponent
-r r
x = 1/ x
Exp.
-6
b =
1/ b⁶
Zero exponent
0
X =1 , if x ≠ 0
Exp
0
7 =
1
Negative exponent with a quotient
- r r
( x / y ) = (y/x)
Exp.
-3
( 1/2) =
Or
-2
5 =
3
(2/1) or 2³
-2 -2 2
5 = (5/1) = (1/5)
Describe what this equals in Simple terms
-3
2
It equals 1÷2÷2÷2 = 0.125
Or
1/8 = 0.125
Law of exponent of 1
1 1 1
X = , 4 =, 79 =
X, 4, 79
Law of exponent of 0
0 0 0
X = , 25 = , 444 =
1, 1, 1
Law of Negative exponents in simple terms
-n
Give solución x
The negative interger is divided by 1
n 1/ x
It is x to the positive n power
(4²)³
4⁶
(x⁴ × y² × z³)⁴
x¹⁶× y⁸×z¹²
(2 x y³)²
2² x² y⁶ = 4 x² y⁶
(2x + 3)²
What method do we use to solve when there is a plus or minus sign inside the parentheses and raised to an exponent
Foil
(2x + 3) (2x + 3)
4x² + 12x + 9
(2x + 3)²
What method do we use to solve when there is a plus or minus sign inside the parentheses and raised to an exponent
Foil
2x + 3) (2x + 3
Y⁴ × Y⁵ =
Y⁹
( x³)⁴
x¹²
( X to negative 3)
Negative 3
X =
How to “Solve this Problem”
= 1 / X³
1
—–
-4
X
How to Simplify
⁴
X
_____
1
Y ⁵ × Y ² =
Y ⁷
X⁷/ X³ =
X⁴
